Theorem 1.1 (mutually singular case): the excursion-coupling definition is well-defined
ProvedExcursionCoupling.excursion_coupling_well_definedLet be mutually singular Borel probability measures on , let , and let
Then the measure with density relative to Lebesgue measure is a probability measure. For -almost every sampled level , the level is nonzero, its completed-graph section is nonempty and finite of even cardinality, every intersection is an increasing or decreasing crossing, and the crossings alternate in order, starting with an increasing crossing for and a decreasing crossing for .
Pair adjacent crossings as in Juillet's construction and, conditionally on the sampled level, choose uniformly among those pairs. The resulting joint law is Juillet's excursion coupling in the exact formal sense: it is the completed-graph occupation measure
it is a probability measure, and its coordinate laws are respectively and .
This is the mutually singular case of the well-definedness assertion in Theorem 1.1, with every implicit claim listed in Remark 1.2 made explicit.
Formalization Note The named predicate
IsJuilletExcursionCoupling requires equality with the occupation measure,
not only concentration on the paired-route set.
import Definitions.Def_JuilletExcursionCoupling open MeasureTheory Set Function
namespace ExcursionCoupling
theorem excursion_coupling_well_defined
(mu nu : Measure Real)
[IsProbabilityMeasure mu] [IsProbabilityMeasure nu]
(hsing : mu ⟂ₘ nu) :
IsProbabilityMeasure (excursionLevelLaw mu nu) ∧
(∀ᵐ h ∂excursionLevelLaw mu nu,
h ≠ 0 ∧
(levelSet (Fsigma mu nu) h).Nonempty ∧
regularLevel (Fsigma mu nu) h) ∧
∃ gamma : Measure (Real × Real),
IsJuilletExcursionCoupling mu nu gamma := by sorry
end ExcursionCouplingRead-back
What the Lean code literally says, in plain math · openai-codex
For every pair of probability measures on that are mutually singular, define . For any , let , , and let consist of those for which there exists such that every with and satisfies ; define identically except that the required inequality is . Say that is regular for when there exist and a strictly increasing map such that , every lies in , and, for every , ; here is allowed. Let be the sum, in , of the extended cardinalities of and , and let . Then is a probability measure; for -almost every , one has , , and is regular for ; and there exists a probability measure on whose first and second coordinate pushforwards are respectively and , together with functions and Borel sets for every , such that every and is measurable, every excludes , and the following hold: for Lebesgue-almost every , implies that is regular for ; for Lebesgue-almost every , every with satisfies , , and either , , and no belongs to , or , , and no belongs to ; for Lebesgue-almost every , every satisfying , regularity of , and has a unique with and ; for Lebesgue-almost every , every satisfying , regularity of , and has a unique with and ; for Lebesgue-almost every , the set is finite; and .
Confirmed by the mission captain (proposal self-audit).