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Lemma 27.3: for coordinatewise ρ-Lipschitz φ, N(ρr, φ ∘ A) ≤ N(r, A)

Proved
UnderstandingML.covering_contraction

by naimengye · Sep 24, 2026 · Mathlib 0df444a (Lean v4.33.1)

contractioncovering-numberslipschitz

Lemma 27.3. For each i∈[m]i \in [m]i∈[m], let φi:R→R\varphi_i : \mathbb{R} \to \mathbb{R}φi​:R→R be a ρ\rhoρ-Lipschitz function; namely, for all α,β∈R\alpha, \beta \in \mathbb{R}α,β∈R we have ∣φi(α)−φi(β)∣≤ρ∣α−β∣|\varphi_i(\alpha) - \varphi_i(\beta)| \le \rho|\alpha - \beta|∣φi​(α)−φi​(β)∣≤ρ∣α−β∣. For a∈Rma \in \mathbb{R}^ma∈Rm let φ(a)\varphi(a)φ(a) denote the vector (φ1(a1),…,φm(am))(\varphi_1(a_1), \dots, \varphi_m(a_m))(φ1​(a1​),…,φm​(am​)). Let φ∘A={φ(a):a∈A}\varphi \circ A = \{\varphi(a) : a \in A\}φ∘A={φ(a):a∈A}. Then, N(ρr,φ∘A)≤N(r,A)N(\rho r, \varphi \circ A) \le N(r, A)N(ρr,φ∘A)≤N(r,A).

Preamble
import Definitions.Def_UnderstandingML_Covering

open MeasureTheory
Formal statement
namespace UnderstandingML

/-- **Lemma 27.3** (p. 389). For each `i ∈ [m]`, let `φᵢ : ℝ → ℝ` be a `ρ`-Lipschitz function.
For `a ∈ ℝ^m` let `φ(a) = (φ₁(a₁), …, φ_m(a_m))` and `φ ∘ A = {φ(a) : a ∈ A}`. Then
`N(ρ r, φ ∘ A) ≤ N(r, A)`. -/
theorem covering_contraction {m : ℕ} (A : Set (Fin m → ℝ)) (ρ : NNReal) (φ : Fin m → ℝ → ℝ)
    (hφ : ∀ i, LipschitzWith ρ (φ i)) (r : ℝ) :
    coveringNumber (ρ * r) ((fun a i ↦ φ i (a i)) '' A) ≤ coveringNumber r A := by sorry

end UnderstandingML
Source
Shalev-Shwartz and Ben-David, Understanding Machine Learning: From Theory to Algorithms, Cambridge University Press 2014, doi:10.1017/CBO9781107298019, §27.1.1 p. 389, Lemma 27.3 with its proof
Human review
  • Endorsed by Shuze Chen · Sep 25, 2026

    Confirmed by the moderator at approval.

  • Endorsed by naimengye · Sep 25, 2026

    Confirmed by the mission captain (proposal self-audit).

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