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Theorem 6.12(c), converse direction — integrability on two adjacent intervals glues

Proved
Rudin.ch06_integral_glue_of_bounded

by Lucas · Sep 18, 2026 · Mathlib 0df444a (Lean v4.33.1)

analysisintegration

Let a≤c≤ba \le c \le ba≤c≤b, let α\alphaα be monotonically increasing on [a,b][a,b][a,b], and let fff be bounded on [a,b][a,b][a,b]. If f∈R(α)f \in \mathcal R(\alpha)f∈R(α) on [a,c][a,c][a,c] and f∈R(α)f \in \mathcal R(\alpha)f∈R(α) on [c,b][c,b][c,b], then f∈R(α)f \in \mathcal R(\alpha)f∈R(α) on [a,b][a,b][a,b] and

∫acf dα+∫cbf dα=∫abf dα.\int_a^c f\,d\alpha + \int_c^b f\,d\alpha = \int_a^b f\,d\alpha .∫ac​fdα+∫cb​fdα=∫ab​fdα.

Rudin's Theorem 6.12(c) asserts the implication in the other direction, from integrability on [a,b][a,b][a,b] to integrability on the two pieces. The converse recorded here is what one uses to integrate a function assembled from pieces — for instance a function with finitely many jumps, integrated by treating each piece separately — and it follows from the same partition constructions, because the upper integral and the lower integral are each additive over adjacent intervals.

Preamble
import Mathlib
import Definitions.Def_Rudin_ch06_stieltjes

open Filter Topology
Formal statement
namespace Rudin

/-- Converse of Rudin, Theorem 6.12(c): a bounded `f` that is integrable on `[a, c]` and on
`[c, b]` is integrable on `[a, b]`, and the two integrals add up to the integral over `[a, b]`. -/
theorem ch06_integral_glue_of_bounded (a c b : ℝ) (hac : a ≤ c) (hcb : c ≤ b) (f α : ℝ → ℝ)
    (hα : MonotoneOn α (Set.Icc a b))
    (hfb : ∃ M, ∀ x ∈ Set.Icc a b, |f x| ≤ M)
    (h₁ : RSIntegrable a c f α) (h₂ : RSIntegrable c b f α) :
    RSIntegrable a b f α ∧
      RSIntegral a c f α + RSIntegral c b f α = RSIntegral a b f α := by sorry

end Rudin
Source
Walter Rudin, Principles of Mathematical Analysis, 3rd edition, McGraw-Hill, 1976, Chapter 6, p. 128, Theorem 6.12(c) (converse direction)

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