Gauss sum times its conjugate equals the field size
ProvedWeil.gaussSum_mul_starexponential-sumsfinite-fieldsgauss-sumsnumber-theoryweil-bound
Let be a finite field, a non-trivial multiplicative character of with values in , and a primitive additive character of . Write for the associated Gauss sum. Then
This is the algebraic core of the classical evaluation : it combines the identity with the fact that complex conjugation inverts both characters.
Preamble
import Mathlib.NumberTheory.GaussSum import Mathlib.NumberTheory.LegendreSymbol.QuadraticChar.GaussSum import Mathlib.NumberTheory.MulChar.Lemmas import Mathlib.GroupTheory.SpecificGroups.Cyclic import Mathlib.GroupTheory.Index import Mathlib.Analysis.SpecialFunctions.Complex.CircleAddChar import Mathlib.Analysis.SpecialFunctions.Sqrt import Mathlib.Analysis.RCLike.Basic import Mathlib.Analysis.Complex.Basic import Mathlib.Algebra.Field.GeomSum import Mathlib.Algebra.Order.BigOperators.Group.Finset set_option autoImplicit false set_option linter.unusedSectionVars false set_option linter.unusedVariables false universe u_1 u_2 open AddChar MulChar Finset
Formal statement
namespace Weil
theorem gaussSum_mul_star : ∀ {F : Type u_1} [inst : Field F] [inst_1 : Fintype F] (χ : MulChar F ℂ), χ ≠ 1 → ∀ (ψ : AddChar F ℂ), AddChar.IsPrimitive ψ → gaussSum χ ψ * star (gaussSum χ ψ) = (↑(Fintype.card F) : ℂ) := by sorry
end WeilSource
Ireland & Rosen, A Classical Introduction to Modern Number Theory, 2nd ed., Springer GTM 84, Ch. 8 (Gauss and Jacobi Sums)