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Lemma 4.11 -- comparing d(t)d(t)d(t) and dˉ(t)\bar d(t)dˉ(t)

Proved
MarkovMixing.dist_le_distPairs

by Shuze Chen · Aug 21, 2026 · Mathlib c5ea003 (Lean v4.30.0)

markov-chainsmixing-timesprobability

Let PPP be the transition matrix of a Markov chain on a finite state space VVV with stationary distribution π\piπ (that is, ∑xπ(x)P(x,y)=π(y)\sum_x\pi(x)P(x,y)=\pi(y)∑x​π(x)P(x,y)=π(y) for all yyy), and write Pt(x,⋅)P^t(x,\cdot)Pt(x,⋅) for the distribution of the chain at time ttt started at xxx, and ∥μ−ν∥TV=max⁡A⊆V∣μ(A)−ν(A)∣\|\mu-\nu\|_{TV}=\max_{A\subseteq V}|\mu(A)-\nu(A)|∥μ−ν∥TV​=maxA⊆V​∣μ(A)−ν(A)∣ for the total variation distance. Chapter 4 of Levin–Peres–Wilmer measures convergence by two quantities: the worst-case distance to stationarity and the worst pairwise distance,

d(t)=max⁡x∈V∥Pt(x,⋅)−π∥TV,dˉ(t)=max⁡x,y∈V∥Pt(x,⋅)−Pt(y,⋅)∥TV.d(t)=\max_{x\in V}\bigl\|P^t(x,\cdot)-\pi\bigr\|_{TV},\qquad \bar d(t)=\max_{x,y\in V}\bigl\|P^t(x,\cdot)-P^t(y,\cdot)\bigr\|_{TV}.d(t)=x∈Vmax​​Pt(x,⋅)−π​TV​,dˉ(t)=x,y∈Vmax​​Pt(x,⋅)−Pt(y,⋅)​TV​.

The theorem (Lemma 4.11) asserts that for every time ttt these are equivalent up to a factor of two:

d(t)  ≤  dˉ(t)  ≤  2 d(t).d(t)\;\le\;\bar d(t)\;\le\;2\,d(t).d(t)≤dˉ(t)≤2d(t).

The left inequality holds because π\piπ is an average of the rows Pt(y,⋅)P^t(y,\cdot)Pt(y,⋅); the right is the triangle inequality through π\piπ. The point of dˉ\bar ddˉ is that, unlike ddd, it is submultiplicative — the subject of the companion lemma.

Preamble
import Definitions.Def_mm_mixing
Formal statement
namespace MarkovMixing

/-- **Lemma 4.11** (LPW): `d(t) ≤ d̄(t) ≤ 2 d(t)`. -/
theorem dist_le_distPairs {V : Type*} [Fintype V] [DecidableEq V] [Nonempty V]
    (P : Matrix V V ℝ) (hP : IsStochastic P)
    (π : V → ℝ) (hπ : IsStationary P π) (t : ℕ) :
    distStationary P π t ≤ distPairs P t ∧
    distPairs P t ≤ 2 * distStationary P π t := by
  sorry

end MarkovMixing
Source
D. A. Levin, Y. Peres, E. L. Wilmer, Markov Chains and Mixing Times, AMS 2009, https://documents.epfl.ch/groups/i/ip/ipg/www/2013-2014/Random_Walks/markovmixing.pdf, Section 4.4, Lemma 4.11, p. 53
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What the Lean code literally says, in plain math · claude-fable-5

Let VVV be a finite, nonempty type with decidable equality, let PPP be a V×VV \times VV×V real matrix assumed stochastic (every entry satisfies 0≤P(x,y)0 \le P(x,y)0≤P(x,y) and every row sums to 111: ∀x, ∑yP(x,y)=1\forall x,\ \sum_y P(x,y) = 1∀x, ∑y​P(x,y)=1), let π:V→R\pi : V \to \mathbb{R}π:V→R be assumed stationary for PPP — meaning π\piπ is a probability distribution (∀x, 0≤π(x)\forall x,\ 0 \le \pi(x)∀x, 0≤π(x) and ∑xπ(x)=1\sum_x \pi(x) = 1∑x​π(x)=1) and the row-vector–matrix product satisfies πP=π\pi P = \piπP=π, i.e. ∑xπ(x) P(x,y)=π(y)\sum_x \pi(x)\,P(x,y) = \pi(y)∑x​π(x)P(x,y)=π(y) for every yyy — and let ttt be an arbitrary natural number (including t=0t = 0t=0, where P0P^0P0 is the identity matrix and each row is a point mass). The statement uses the custom total-variation quantity

tvDist(μ,ν)  =  sup⁡A⊆V ∣∑x∈Aμ(x)−∑x∈Aν(x)∣\mathrm{tvDist}(\mu,\nu) \;=\; \sup_{A \subseteq V}\ \Bigl|\sum_{x \in A}\mu(x) - \sum_{x \in A}\nu(x)\Bigr|tvDist(μ,ν)=A⊆Vsup​ ​x∈A∑​μ(x)−x∈A∑​ν(x)​

(a supremum over all subsets of the finite type VVV, with no factor 12\tfrac1221​), and the two derived quantities

d(t)  =  sup⁡x∈V tvDist(Pt(x,⋅ ), π),dˉ(t)  =  sup⁡(x,y)∈V×V tvDist(Pt(x,⋅ ), Pt(y,⋅ )),d(t) \;=\; \sup_{x \in V}\ \mathrm{tvDist}\bigl(P^t(x,\cdot\,),\ \pi\bigr), \qquad \bar d(t) \;=\; \sup_{(x,y) \in V \times V}\ \mathrm{tvDist}\bigl(P^t(x,\cdot\,),\ P^t(y,\cdot\,)\bigr),d(t)=x∈Vsup​ tvDist(Pt(x,⋅), π),dˉ(t)=(x,y)∈V×Vsup​ tvDist(Pt(x,⋅), Pt(y,⋅)),

where Pt(x,⋅ )P^t(x,\cdot\,)Pt(x,⋅) denotes the function y↦(Pt)(x,y)y \mapsto (P^t)(x,y)y↦(Pt)(x,y), the xxx-th row of the ttt-th matrix power of PPP. All suprema are taken in R\mathbb{R}R (with the convention that an empty or unbounded supremum equals 000; here the index sets are nonempty and finite over subsets/points of VVV, so under the hypotheses they are genuine maxima). The theorem asserts the conjunction of two non-strict inequalities:

d(t)  ≤  dˉ(t)anddˉ(t)  ≤  2 d(t).d(t) \;\le\; \bar d(t) \qquad \text{and} \qquad \bar d(t) \;\le\; 2\, d(t).d(t)≤dˉ(t)anddˉ(t)≤2d(t).

Both inequalities are claimed for every single ttt, under the stated stochasticity and stationarity hypotheses; nothing further (irreducibility, aperiodicity, etc.) is assumed.

Human review
  • Endorsed by Community (Bot) · Aug 21, 2026

  • Endorsed by Shuze Chen · Aug 21, 2026

    Confirmed by the mission captain (proposal self-audit).

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