Geometric decay of the autocovariance, with an constant
ProvedMarkovChainCLT.abs_integral_mul_iterKernel_leThe autocovariance of a uniformly ergodic chain decays geometrically. For a bounded measurable with ,
whenever the -step kernel satisfies with . Since for the stationary chain, this is exactly the statement that the autocovariance function decays geometrically in the lag, with a constant proportional to rather than to .
Why the constant matters. The martingale approximation behind the Markov chain central limit theorem is available only for bounded observables. To reach a square-integrable one truncates, , and must show the discarded part contributes negligibly to the normalized variance. That requires a bound on in terms of — a sup-norm bound is useless, since does not go to zero. Summing the estimate above over lags gives
because each block of consecutive lags contributes at most ; expanding the square of a partial sum then yields .
Proof. Cauchy–Schwarz would give , and by the geometric decay of the transition operator. The proof here uses the equivalent weighted arithmetic–geometric mean inequality, which avoids square roots entirely: with ,
since . Integrating and inserting makes the two terms equal, each , and the bound closes.
import Definitions.Def_MarkovErgodicity import Definitions.Def_MarkovIterKernel import Definitions.Def_TotalVariationDist import Mathlib.Probability.Kernel.Invariance import Mathlib.MeasureTheory.Integral.Bochner.Set open Filter Finset Function MeasurableSpace MeasureTheory ProbabilityTheory open MarkovChainCLT open scoped ENNReal NNReal Topology
theorem MarkovChainCLT.abs_integral_mul_iterKernel_le {X : Type*} [MeasurableSpace X]
(P : Kernel X X) [IsMarkovKernel P] (π : Measure X) [IsProbabilityMeasure π]
(hinv : Kernel.Invariant P π) (N : ℕ) (hN : 1 ≤ N) (ρ : ℝ) (hρ0 : 0 ≤ ρ)
(hρ : 4 * ρ ≤ 1 / 4) (hrate : ∀ x, tvDist (iterKernel P N x) π ≤ ρ)
(r : X → ℝ) (hr : Measurable r) (Br : ℝ) (hBr : ∀ x, |r x| ≤ Br)
(hmean : ∫ x, r x ∂π = 0) (d : ℕ) :
|∫ x, r x * (∫ y, r y ∂(iterKernel P d x)) ∂π|
≤ (1 / 2 : ℝ) ^ (d / N) * ∫ x, (r x) ^ 2 ∂π := by sorry