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Lemma 5.1 — at least ηx/(2log⁡x)\eta x/(2\log x)ηx/(2logx) primes in ((1−2η)x,(1−η)x]((1-2\eta)x,(1-\eta)x]((1−2η)x,(1−η)x]

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IntMul.HvdH.lemma_5_1

by avi · Oct 8, 2026 · Mathlib 0df444a (Lean v4.33.1)

number-theoryprimes

Let η\etaη be a real number with 0<η<140<\eta<\tfrac140<η<41​, and let xxx be a real number with x≥e2/ηx\ge e^{2/\eta}x≥e2/η. Then the interval ((1−2η)x,(1−η)x]\big((1-2\eta)x,(1-\eta)x\big]((1−2η)x,(1−η)x] contains many primes:

#{q prime:(1−2η)x<q≤(1−η)x} ≥ ηx2log⁡x.\#\{q\text{ prime}:(1-2\eta)x<q\le(1-\eta)x\}\ \ge\ \frac{\eta x}{2\log x}.#{q prime:(1−2η)x<q≤(1−η)x} ≥ 2logxηx​.

Here log⁡\loglog is the natural logarithm. In the paper this lemma supplies ddd distinct primes s1,…,sds_1,\dots,s_ds1​,…,sd​ slightly below the power-of-two lengths t1,…,tdt_1,\dots,t_dt1​,…,td​, so that every ratio ti/sit_i/s_iti​/si​ stays away from 111 while the product t1⋯td/(s1⋯sd)t_1\cdots t_d/(s_1\cdots s_d)t1​⋯td​/(s1​⋯sd​) stays bounded.

Preamble
import Mathlib
Formal statement
namespace IntMul.HvdH

theorem lemma_5_1 (η : ℝ) (hη₀ : 0 < η) (hη₁ : η < 1 / 4) (x : ℝ) (hx : Real.exp (2 / η) ≤ x) :
    η * x / (2 * Real.log x) ≤
      ({q : ℕ | q.Prime ∧ (1 - 2 * η) * x < q ∧ (q : ℝ) ≤ (1 - η) * x}.ncard : ℝ) := by sorry

end IntMul.HvdH
Source
D. Harvey, J. van der Hoeven, Integer multiplication in time O(n log n), Annals of Mathematics 193(2) (2021) 563-617, https://doi.org/10.4007/annals.2021.193.2.4 (preprint https://hal.science/hal-02070778v2), §5.2, Lemma 5.1, p. 37
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What the Lean code literally says, in plain math · claude-opus-5-5

Statement. Let η\etaη be a real number with

0<η<14(both strict),0 < \eta < \tfrac14 \quad(\text{both strict}),0<η<41​(both strict),

and let xxx be a real number with

x≥e2/η(non-strict).x \ge e^{2/\eta} \quad(\text{non-strict}).x≥e2/η(non-strict).

Then the number of primes in the half-open interval ((1−2η)x, (1−η)x]\big((1-2\eta)x,\ (1-\eta)x\big]((1−2η)x, (1−η)x] is at least ηx2log⁡x\dfrac{\eta x}{2\log x}2logxηx​:

η x2log⁡x  ≤  #{ q∈N  :  q is prime, (1−2η)x<q≤(1−η)x }.\frac{\eta\, x}{2\log x} \;\le\; \#\big\{\, q \in \mathbb{N} \;:\; q \text{ is prime},\ (1-2\eta)x < q \le (1-\eta)x \,\big\}.2logxηx​≤#{q∈N:q is prime, (1−2η)x<q≤(1−η)x}.

Binders and hypotheses. There are exactly two universally quantified variables, the real numbers η\etaη and xxx, and three hypotheses: 0<η0<\eta0<η (strict), η<1/4\eta < 1/4η<1/4 (strict), and e2/η≤xe^{2/\eta} \le xe2/η≤x (non-strict). No other assumptions are made; in particular xxx need not be an integer.

Meaning of the symbols.

  • log⁡\loglog is the natural logarithm (base eee), and e2/ηe^{2/\eta}e2/η is the real exponential.
  • qqq ranges over natural numbers that are prime (so q≥2q \ge 2q≥2); the comparisons with (1−2η)x(1-2\eta)x(1−2η)x and (1−η)x(1-\eta)x(1−η)x are made after viewing qqq as a real number. The lower endpoint is excluded (strict <<<) and the upper endpoint is included (≤\le≤).
  • #\## denotes the cardinality of the set, returned as a natural number and then regarded as a real number for the comparison. (The counting function used assigns the value 000 to an infinite set; here the set is always finite, since every element satisfies q≤(1−η)xq \le (1-\eta)xq≤(1−η)x, so the count is the genuine number of such primes.)
  • The inequality is a non-strict ≤\le≤ between two real numbers.

Edge cases and remarks on the hypothesis range. The hypotheses are jointly satisfiable (e.g. η=1/8\eta = 1/8η=1/8, x=e16x = e^{16}x=e16). Since 0<η<1/40<\eta<1/40<η<1/4, we have 2/η>82/\eta > 82/η>8, so x≥e2/η>e8≈2981x \ge e^{2/\eta} > e^8 \approx 2981x≥e2/η>e8≈2981; hence log⁡x≥2/η>8>0\log x \ge 2/\eta > 8 > 0logx≥2/η>8>0, the denominator 2log⁡x2\log x2logx is strictly positive, and no division-by-zero or junk value arises. Also 1−2η∈(1/2,1)1-2\eta \in (1/2, 1)1−2η∈(1/2,1) and 1−η∈(3/4,1)1-\eta \in (3/4,1)1−η∈(3/4,1), so the interval ((1−2η)x,(1−η)x]\big((1-2\eta)x, (1-\eta)x\big]((1−2η)x,(1−η)x] is a non-empty interval of positive reals of length ηx\eta xηx, lying strictly below xxx. The left-hand side ηx/(2log⁡x)\eta x/(2\log x)ηx/(2logx) is a positive real number, not rounded to an integer, so the statement in particular asserts the interval contains at least one prime.

Human review
  • Endorsed by wurtle · Oct 8, 2026

    Confirmed by the moderator at approval.

  • Endorsed by avi · Oct 8, 2026

    Confirmed by the mission captain (proposal self-audit).

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