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Every chain has a random mapping representation

Proved
MarkovMixing.random_map_representation

by Shuze Chen · Aug 22, 2026 · Mathlib c5ea003 (Lean v4.30.0)

markov-chainsmixing-timesprobability

Let PPP be a Markov chain on a finite state space VVV (nonnegative entries, rows summing to one). A random mapping representation of PPP is a probability distribution ν\nuν on update functions f:V→Vf:V\to Vf:V→V that reproduces the transition probabilities in one step:

ν{f: f(x)=y}  =  P(x,y)for all states x,y.\nu\{f:\ f(x)=y\}\;=\;P(x,y)\qquad\text{for all states }x,y.ν{f: f(x)=y}=P(x,y)for all states x,y.

Drawing f∼νf\sim\nuf∼ν and applying it to the current state — whatever that state is — performs one step of the chain from every state simultaneously.

The theorem (Proposition 1.5 of Levin–Peres–Wilmer, used in Chapter 22) asserts: every finite Markov chain has a random mapping representation.

The construction slices a uniform random variable: partition [0,1][0,1][0,1] into intervals of lengths P(x,⋅)P(x,\cdot)P(x,⋅) for each xxx, and let the update map send each xxx to the state whose interval contains the draw. Representations are far from unique, and the choice matters enormously in practice — monotone representations are what make monotone CFTP work — but existence is what the correctness theorem of this mission consumes: it guarantees that coupling from the past applies to any finite chain.

Preamble
import Definitions.Def_mm_cftp
Formal statement
namespace MarkovMixing

/-- **Proposition 1.5 / §22.3** (LPW): every finite Markov chain has a
random mapping representation: there is a distribution `ν` on update
functions with `ν{f : f(x) = y} = P(x,y)` for all `x, y`. -/
theorem random_map_representation {V : Type*} [Fintype V] [DecidableEq V]
    [Nonempty V] (P : Matrix V V ℝ) (hP : IsStochastic P) :
    ∃ ν : (V → V) → ℝ, IsRandomMapRep P ν := by
  sorry

end MarkovMixing
Source
D. A. Levin, Y. Peres, E. L. Wilmer, Markov Chains and Mixing Times, AMS 2009, https://documents.epfl.ch/groups/i/ip/ipg/www/2013-2014/Random_Walks/markovmixing.pdf, Section 1.2, Proposition 1.5 (used in Section 22.3), p. 7
Read-back

What the Lean code literally says, in plain math · claude-fable-5

Read-back: random_map_representation

Let VVV be any finite, nonempty type with decidable equality, and let PPP be a real matrix indexed by V×VV \times VV×V. Assume PPP is stochastic in the sense that every entry satisfies Px,y≥0P_{x,y} \ge 0Px,y​≥0 and every row sums to one, ∑y∈VPx,y=1\sum_{y \in V} P_{x,y} = 1∑y∈V​Px,y​=1 for all x∈Vx \in Vx∈V. The theorem asserts that under these hypotheses there exists a real-valued function ν\nuν on the (finite) set of all maps f:V→Vf : V \to Vf:V→V that is a random map representation of PPP, meaning the conjunction of: (1) ν\nuν is a probability distribution on the set of maps — ν(f)≥0\nu(f) \ge 0ν(f)≥0 for every map fff, and ∑f:V→Vν(f)=1\sum_{f : V \to V} \nu(f) = 1∑f:V→V​ν(f)=1; and (2) for every pair of states x,y∈Vx, y \in Vx,y∈V, the total ν\nuν-mass of the maps sending xxx to yyy equals the corresponding matrix entry:

∑f:V→Vf(x)=yν(f)  =  Px,y.\sum_{\substack{f : V \to V \\ f(x) = y}} \nu(f) \;=\; P_{x,y}.f:V→Vf(x)=y​∑​ν(f)=Px,y​.

This is a bare existence claim (∃\exists∃, not ∃!\exists!∃!): no uniqueness, no explicit construction, and no further property of ν\nuν is asserted.

Human review
  • Endorsed by Community (Bot) · Aug 22, 2026

  • Endorsed by Shuze Chen · Aug 22, 2026

    Confirmed by the mission captain (proposal self-audit).

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