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Examples 1.12 and 1.20 -- simple random walk on a graph

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MarkovMixing.graph_walk_reversible

by Shuze Chen · Aug 21, 2026 · Mathlib c5ea003 (Lean v4.30.0)

markov-chainsmixing-timesprobability

On a finite graph with no isolated vertices, simple random walk (move to a uniformly chosen neighbour) is a Markov chain; the distribution

π(x)=deg⁡(x)2∣E∣\pi(x)=\frac{\deg(x)}{2|E|}π(x)=2∣E∣deg(x)​

satisfies detailed balance with it, and is therefore its stationary distribution.

Preamble
import Definitions.Def_mm_basic
Formal statement
namespace MarkovMixing

/-- **Examples 1.12 and 1.20** (LPW): on a graph with no isolated vertices,
simple random walk is a Markov chain, the distribution
`π(x) = deg(x) / 2|E|` satisfies detailed balance, and it is stationary. -/
theorem graph_walk_reversible {V : Type*} [Fintype V] [DecidableEq V] [Nonempty V]
    (G : SimpleGraph V) [DecidableRel G.Adj] (hdeg : ∀ x : V, 0 < G.degree x) :
    IsStochastic (graphWalk G) ∧
    DetailedBalance (graphWalk G)
      (fun x => (G.degree x : ℝ) / (2 * G.edgeFinset.card)) ∧
    IsStationary (graphWalk G)
      (fun x => (G.degree x : ℝ) / (2 * G.edgeFinset.card)) := by
  sorry

end MarkovMixing
Source
D. A. Levin, Y. Peres, E. L. Wilmer, Markov Chains and Mixing Times, AMS 2009, https://documents.epfl.ch/groups/i/ip/ipg/www/2013-2014/Random_Walks/markovmixing.pdf, Sections 1.4-1.6, Examples 1.12 and 1.20, pp. 10 and 15
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What the Lean code literally says, in plain math · claude-fable-5

Let VVV be any finite, nonempty type with decidable equality, let GGG be a simple graph on VVV (undirected, no loops) with decidable adjacency, and assume every vertex has strictly positive degree: deg⁡(x)>0\deg(x) > 0deg(x)>0 for all x∈Vx \in Vx∈V. Define the real V×VV \times VV×V matrix PPP (the "graph walk" of GGG) entrywise by

P(x,y)={1deg⁡(x)if x∼y in G,0otherwise,P(x,y) = \begin{cases} \dfrac{1}{\deg(x)} & \text{if } x \sim y \text{ in } G, \\ 0 & \text{otherwise,} \end{cases}P(x,y)=⎩⎨⎧​deg(x)1​0​if x∼y in G,otherwise,​

and define the function π:V→R\pi : V \to \mathbb{R}π:V→R by

π(x)=deg⁡(x)2 ∣E∣,\pi(x) = \frac{\deg(x)}{2\,|E|},π(x)=2∣E∣deg(x)​,

where ∣E∣|E|∣E∣ is the number of edges of GGG (the cardinality of its finite edge set; note that if GGG had no edges this would be a division by zero, which in this formalization yields the value 000 — though the positive-degree hypothesis rules that case out, since VVV is nonempty). The theorem asserts the conjunction of the following three claims:

  1. PPP is stochastic: every entry satisfies P(x,y)≥0P(x,y) \ge 0P(x,y)≥0, and every row sums to one, ∑y∈VP(x,y)=1\sum_{y \in V} P(x,y) = 1∑y∈V​P(x,y)=1 for all xxx.

  2. PPP satisfies detailed balance with respect to π\piπ: for all x,y∈Vx, y \in Vx,y∈V,

π(x) P(x,y)=π(y) P(y,x).\pi(x)\,P(x,y) = \pi(y)\,P(y,x).π(x)P(x,y)=π(y)P(y,x).
  1. π\piπ is a stationary distribution for PPP, meaning both that π\piπ is a probability distribution — π(x)≥0\pi(x) \ge 0π(x)≥0 for all xxx and ∑x∈Vπ(x)=1\sum_{x \in V} \pi(x) = 1∑x∈V​π(x)=1 — and that π\piπ is fixed by right multiplication as a row vector: πP=π\pi P = \piπP=π, i.e. ∑x∈Vπ(x) P(x,y)=π(y)\sum_{x \in V} \pi(x)\,P(x,y) = \pi(y)∑x∈V​π(x)P(x,y)=π(y) for every y∈Vy \in Vy∈V.

All three parts concern exactly this matrix PPP and this function π\piπ; no irreducibility or aperiodicity is asserted, and no uniqueness of the stationary distribution is claimed.

Human review
  • Endorsed by Community (Bot) · Aug 21, 2026

  • Endorsed by Shuze Chen · Aug 21, 2026

    Confirmed by the mission captain (proposal self-audit).

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