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MOSS large-gap arm expected pull bound

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BanditAlgorithm.moss_large_gap_arm_expected_pull_bound

by MKPynnic · Jul 21, 2026 · Mathlib c5ea003 (Lean v4.30.0)

Fix an arm iii with Δi>8k/n\Delta_i>8\sqrt{k/n}Δi​>8k/n​ in a 1-subgaussian bandit and run MOSS for horizon n≥k>0n\ge k>0n≥k>0. Then Δi E[Ti(n)]≤Δi+15n/k\Delta_i\,\mathbb E[T_i(n)]\le\Delta_i+15\sqrt{n/k}Δi​E[Ti​(n)]≤Δi​+15n/k​. The source defines κi\kappa_iκi​, proves Ti(n)≤κiT_i(n)\le\kappa_iTi​(n)≤κi​ from the MOSS index rule, and applies Lemma 8.2 to obtain this displayed armwise bound.

Preamble
import Definitions.Def_banditRegret
import Definitions.Def_mossPolicy

open MeasureTheory ProbabilityTheory
Formal statement
theorem BanditAlgorithm.moss_large_gap_arm_expected_pull_bound
    {k : ℕ} (hk : 0 < k)
    {ν : BanditAlgorithm.StochasticBandit k}
    (hν : BanditAlgorithm.IsSubgaussianBandit 1 ν)
    {n : ℕ} {π : BanditAlgorithm.BanditPolicy k}
    (hπ : BanditAlgorithm.IsMOSSPolicy n π) (hkn : k ≤ n)
    (i : Fin k)
    (hi : 8 * Real.sqrt ((k : ℝ) / n) < BanditAlgorithm.banditGap ν i) :
    BanditAlgorithm.banditGap ν i *
        MeasureTheory.integral
          (BanditAlgorithm.banditMeasure ν π n)
          (fun h ↦ (BanditAlgorithm.armPullCount i h : ℝ)) ≤
      BanditAlgorithm.banditGap ν i + 15 * Real.sqrt ((n : ℝ) / k) := by
  sorry
Source
Lattimore and Szepesvari, Bandit Algorithms (CUP 2020), proof of Theorem 9.1, printed pp. 126-127 / PDF pp. 135-136: definition of kappa_i, T_i(n) <= kappa_i, Lemma 8.2 application, and displayed Delta_i E[kappa_i] <= Delta_i + 15 sqrt(n/k).

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