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Both completions are the Fano plane

Proved
FanoUnique.completions_are_fano

by ShapeZero · Sep 24, 2026 · Mathlib 0df444a (Lean v4.33.1)

combinatoricsfano-planesteiner-triple-systems

Let SSS be a Steiner triple system on {0,…,6}\{0, \dots, 6\}{0,…,6} whose lines are exactly completion A or exactly completion B:

A: {0,1,2},{0,3,4},{0,5,6},{1,3,6},{1,4,5},{2,3,5},{2,4,6},\text{A: } \{0,1,2\}, \{0,3,4\}, \{0,5,6\}, \{1,3,6\}, \{1,4,5\}, \{2,3,5\}, \{2,4,6\},A: {0,1,2},{0,3,4},{0,5,6},{1,3,6},{1,4,5},{2,3,5},{2,4,6}, B: {0,1,2},{0,3,4},{0,5,6},{1,3,5},{1,4,6},{2,3,6},{2,4,5}.\text{B: } \{0,1,2\}, \{0,3,4\}, \{0,5,6\}, \{1,3,5\}, \{1,4,6\}, \{2,3,6\}, \{2,4,5\}.B: {0,1,2},{0,3,4},{0,5,6},{1,3,5},{1,4,6},{2,3,6},{2,4,5}.

Then SSS is the Fano plane up to relabelling: some permutation of the points carries its lines exactly onto {{i,i+1,i+3}:i∈Z/7}\{\{i, i+1, i+3\} : i \in \mathbb{Z}/7\}{{i,i+1,i+3}:i∈Z/7}. For A the permutation 0↦0, 1↦1, 2↦3, 3↦2, 4↦6, 5↦5, 6↦40\mapsto0,\ 1\mapsto1,\ 2\mapsto3,\ 3\mapsto2,\ 4\mapsto6,\ 5\mapsto5,\ 6\mapsto40↦0, 1↦1, 2↦3, 3↦2, 4↦6, 5↦5, 6↦4 works.

Preamble
import Mathlib
import Definitions.Def_FanoUnique_isFano
Formal statement
namespace FanoUnique

open RolesForceSeven

theorem completions_are_fano (S : STS 7)
    (h : S.lines = {{0, 1, 2}, {0, 3, 4}, {0, 5, 6}, {1, 3, 6}, {1, 4, 5}, {2, 3, 5}, {2, 4, 6}} ∨
      S.lines = {{0, 1, 2}, {0, 3, 4}, {0, 5, 6}, {1, 3, 5}, {1, 4, 6}, {2, 3, 6}, {2, 4, 5}}) :
    IsFano S := by
  sorry

end FanoUnique
Source
Shape Zero LLC, "Formal Proofs of the C1 Verification Package" (August 2026), §3, proof of Theorem 3.3 ("Uniqueness of STS(7) is classical"); this is a step of the standard textbook proof, supplying the step C1 calls classical: https://github.com/ShapeZeroSZ/shape-zero/blob/main/01_source/proofs/ShapeZero_C1_Formal_Proofs.pdf ; public references: Wikipedia, "Fano plane": https://en.wikipedia.org/wiki/Fano_plane ; Wikipedia, "Steiner system": https://en.wikipedia.org/wiki/Steiner_system
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What the Lean code literally says, in plain math · claude-opus-5-5

Setting. Throughout, the point set is Z/7={0,1,…,6}\mathbb{Z}/7 = \{0,1,\dots,6\}Z/7={0,1,…,6} (the type of natural numbers below 777, with addition taken modulo 777). A Steiner triple system on nnn points (in the sense used here) is a triple consisting of

  • a finite collection L\mathcal{L}L of subsets of {0,…,n−1}\{0,\dots,n-1\}{0,…,n−1} (the lines),
  • the property that every line l∈Ll \in \mathcal{L}l∈L has exactly 333 elements,
  • the property that for all points x≠yx \neq yx=y there is exactly one line l∈Ll \in \mathcal{L}l∈L with x∈lx \in lx∈l and y∈ly \in ly∈l.

The theorem takes an arbitrary such system SSS on n=7n = 7n=7 points, with line collection LS\mathcal{L}_SLS​ (the two axioms are part of the data of SSS).

Hypothesis. LS\mathcal{L}_SLS​ is literally equal (as a set of 333-element subsets of Z/7\mathbb{Z}/7Z/7) to one of the following two collections:

A={{0,1,2},{0,3,4},{0,5,6},{1,3,6},{1,4,5},{2,3,5},{2,4,6}},\mathcal{A} = \bigl\{\{0,1,2\},\{0,3,4\},\{0,5,6\},\{1,3,6\},\{1,4,5\},\{2,3,5\},\{2,4,6\}\bigr\},A={{0,1,2},{0,3,4},{0,5,6},{1,3,6},{1,4,5},{2,3,5},{2,4,6}}, B={{0,1,2},{0,3,4},{0,5,6},{1,3,5},{1,4,6},{2,3,6},{2,4,5}}.\mathcal{B} = \bigl\{\{0,1,2\},\{0,3,4\},\{0,5,6\},\{1,3,5\},\{1,4,6\},\{2,3,6\},\{2,4,5\}\bigr\}.B={{0,1,2},{0,3,4},{0,5,6},{1,3,5},{1,4,6},{2,3,6},{2,4,5}}.

That is, LS=A\mathcal{L}_S = \mathcal{A}LS​=A or LS=B\mathcal{L}_S = \mathcal{B}LS​=B (an inclusive "or"). Each of A\mathcal{A}A and B\mathcal{B}B consists of seven distinct 333-element sets, and in each every pair of distinct points of Z/7\mathbb{Z}/7Z/7 lies in exactly one of the seven sets, so both alternatives are compatible with the Steiner-system axioms; the hypothesis is not vacuous.

Reference system. The fixed "Fano" system FFF on Z/7\mathbb{Z}/7Z/7 has as lines the sets {i, i+1, i+3}\{i,\ i+1,\ i+3\}{i, i+1, i+3} (addition mod 777) for i=0,…,6i = 0,\dots,6i=0,…,6, i.e.

LF={{0,1,3},{1,2,4},{2,3,5},{3,4,6},{0,4,5},{1,5,6},{0,2,6}}.\mathcal{L}_F = \bigl\{\{0,1,3\},\{1,2,4\},\{2,3,5\},\{3,4,6\},\{0,4,5\},\{1,5,6\},\{0,2,6\}\bigr\}.LF​={{0,1,3},{1,2,4},{2,3,5},{3,4,6},{0,4,5},{1,5,6},{0,2,6}}.

Conclusion. SSS "is Fano", which by definition means: there exists a bijection e:Z/7→Z/7e : \mathbb{Z}/7 \to \mathbb{Z}/7e:Z/7→Z/7 (a permutation of the seven points) such that

{ e(l)  :  l∈LS }  =  LF,\bigl\{\, e(l) \;:\; l \in \mathcal{L}_S \,\bigr\} \;=\; \mathcal{L}_F ,{e(l):l∈LS​}=LF​,

where e(l)={e(x):x∈l}e(l) = \{e(x) : x \in l\}e(l)={e(x):x∈l} is the pointwise image of the line lll. In words: under either hypothesis on the lines of SSS, some relabelling of the points carries the set of lines of SSS exactly onto the set of lines of the reference system FFF (equality of collections of lines, so every line of SSS maps to a line of FFF and every line of FFF is the image of some line of SSS). Only existence of such a permutation is asserted; no uniqueness is claimed.

Human review
  • Endorsed by Shuze Chen · Sep 25, 2026

    Confirmed by the moderator at approval.

  • Endorsed by ShapeZero · Sep 25, 2026

    Confirmed by the mission captain (proposal self-audit).

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