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BanditAlgorithm.bretagnolle_huber_inequality

Proved

by Shuze Chen · Jul 18, 2026 · Mathlib c5ea003 (Lean v4.30.0)

inequalitiesinformation-theorylower-bounds

(Bretagnolle–Huber, GOAL) Let PPP and QQQ be probability measures on the same measurable space (Ω,F)(\Omega, \mathcal{F})(Ω,F) with D(P,Q)=D(P,Q) = D(P,Q)= klDiv P Q finite, and let A∈FA \in \mathcal{F}A∈F be measurable. Then

P(A)+Q(Ac)≥12exp⁡(−D(P,Q)),P(A) + Q(A^c) \ge \frac{1}{2}\exp(-D(P,Q)),P(A)+Q(Ac)≥21​exp(−D(P,Q)),

with probabilities as Measure.real. CRITICAL BOUNDARY: the hypothesis D(P,Q)≠∞D(P,Q) \ne \inftyD(P,Q)=∞ is REQUIRED — without it the Lean statement is FALSE, since (∞).toReal = 0 would make the right-hand side 12\frac1221​ while e.g. P=δ0P = \delta_0P=δ0​, Q=δ1Q = \delta_1Q=δ1​, A={1}A = \{1\}A={1} gives P(A)+Q(Ac)=0P(A)+Q(A^c) = 0P(A)+Q(Ac)=0. The book's statement is trivially true at D=∞D = \inftyD=∞ (right-hand side 12e−∞=0\frac12 e^{-\infty} = 021​e−∞=0); only the toReal junk-value encoding breaks.

Preamble
import Mathlib.InformationTheory.KullbackLeibler.Basic


open MeasureTheory InformationTheory Real
open scoped ENNReal
Formal statement
theorem BanditAlgorithm.bretagnolle_huber_inequality {Ω : Type} {mΩ : MeasurableSpace Ω}
    (P Q : Measure Ω) [IsProbabilityMeasure P] [IsProbabilityMeasure Q]
    {A : Set Ω} (hA : MeasurableSet A) (hD : klDiv P Q ≠ ∞) :
    2⁻¹ * exp (-(klDiv P Q).toReal) ≤ P.real A + Q.real Aᶜ := by
  sorry
Source
L&S Theorem 14.2, Eq. (14.7), p.190
Read-back

What the Lean code literally says, in plain math · claude-fable-5

Setup and notation. Let Ω\OmegaΩ be an arbitrary measurable space, P,QP, QP,Q two probability measures on it, and A⊆ΩA \subseteq \OmegaA⊆Ω a measurable set. Here D(P ∥ Q)∈[0,∞]D(P\,\|\,Q) \in [0,\infty]D(P∥Q)∈[0,∞] denotes the library's Kullback–Leibler divergence: when PPP is absolutely continuous with respect to QQQ and the log-likelihood ratio ω↦log⁡dPdQ(ω)\omega \mapsto \log\frac{dP}{dQ}(\omega)ω↦logdQdP​(ω) is PPP-integrable, D(P∥Q)D(P\|Q)D(P∥Q) is the image in [0,∞][0,\infty][0,∞] of the real integral ∫log⁡dPdQ dP\int \log\frac{dP}{dQ}\,dP∫logdQdP​dP (a negative value — impossible for probability measures — would be truncated to 000); in every other case D(P∥Q)=∞D(P\|Q) = \inftyD(P∥Q)=∞. Assume D(P∥Q)≠∞D(P\|Q) \neq \inftyD(P∥Q)=∞ and write d∈[0,∞)d \in [0,\infty)d∈[0,∞) for its finite real value. Write P(A)P(A)P(A) and Q(Ac)Q(A^{\mathsf c})Q(Ac) for the real-valued measures of AAA and of its complement (the extended-nonnegative measure values converted to reals — finite here, since both are probability measures).

Assertion. As an inequality between real numbers,

12 e−d  ≤  P(A)  +  Q(Ac).\frac{1}{2}\, e^{-d} \;\le\; P(A) \;+\; Q\big(A^{\mathsf c}\big).21​e−d≤P(A)+Q(Ac).

Hypotheses:

  • PPP and QQQ are both probability measures on the same measurable space Ω\OmegaΩ.
  • AAA is a measurable subset of Ω\OmegaΩ (the claim is universally quantified over such AAA).
  • D(P∥Q)≠∞D(P\|Q) \neq \inftyD(P∥Q)=∞ — in particular P≪QP \ll QP≪Q with PPP-integrable log-likelihood ratio.

Edge cases and caveats:

  • ddd is obtained from the extended-real divergence by the conversion that sends ∞\infty∞ to 000; the finiteness hypothesis blocks that junk case (without it, at D=∞D = \inftyD=∞ the left side would evaluate to 12\tfrac1221​, a stronger, unintendedly different claim).
  • The left-hand side 12e−d\tfrac12 e^{-d}21​e−d is always strictly positive, so the statement is never vacuous under its hypotheses.
  • The inequality is non-strict; the right-hand side pairs PPP on the set AAA with QQQ on the complement of AAA.
Human review
  • Endorsed by Community (Bot) · Jul 18, 2026

  • Endorsed by Shuze Chen · Jul 18, 2026

    Confirmed by the mission captain (proposal self-audit).

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