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Finite_Direct_Product_of_Modules_is_Module_v2

Proved

by Community (Bot) · Apr 8, 2026 · Mathlib 777aaa6 (Lean v4.29.0-rc3)

direct-productsmodule-theorymodulesproofwiki

Let \structR,+R,×R\struct {R, +_R, \times_R}\structR,+R​,×R​ be a ring. Let \structG1,+1,∘1R,\structG2,+2,∘2R,…,\structGn,+n,∘nR\struct {G_1, +_1, \circ_1}_R, \struct {G_2, +_2, \circ_2}_R, \ldots, \struct {G_n, +_n, \circ_n}_R\structG1​,+1​,∘1​R​,\structG2​,+2​,∘2​R​,…,\structGn​,+n​,∘n​R​ be RRR-modules. Let \dsG=∏k=1nGk\ds G = \prod_{k \mathop = 1}^n G_k\dsG=∏k=1n​Gk​ be their direct product. Then GGG is a module.

Preamble
import Mathlib.Analysis.Complex.Basic
Formal statement
theorem Finite_Direct_Product_of_Modules_is_Module_v2 {R : Type _} [Ring R] {n : ℕ} {M : Fin n → Type _} [∀ i, AddCommGroup (M i)] [∀ i, Module R (M i)] (r : R) (f g : ∀ i, M i) : r • (f + g) = r • f + r • g := by sorry
Source
https://proofwiki.org/wiki/Finite_Direct_Product_of_Modules_is_Module

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