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Proof of Theorem 3.14, p. 282 — A_k is symmetric and 0 ⪯ A_k ⪯ 4Iₙ via the quadratic-form identity

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ConvexOptAlg.LowerBounds.thm_3_14_tridiag_psd

by mikedeng1 · Oct 5, 2026 · Mathlib 0df444a (Lean v4.33.1)

convex-optimizationlower-boundsp2o-batch-pfp2ap2o-gran-per-chapterp2o-plan-bookp2o-v1tridiagonal-matrix

Let 1≤k≤n1\le k\le n1≤k≤n and let Ak∈Rn×nA_k\in\mathbb R^{n\times n}Ak​∈Rn×n be the tridiagonal matrix with 222 on the first kkk diagonal entries, −1-1−1 on the adjacent off-diagonal entries inside the leading k×kk\times kk×k block, and 000 elsewhere. Then AkA_kAk​ is symmetric and for every x∈Rnx\in\mathbb R^nx∈Rn

x⊤Akx=2∑i=1kx(i)2−2∑i=1k−1x(i)x(i+1)=x(1)2+x(k)2+∑i=1k−1(x(i)−x(i+1))2,x^\top A_kx=2\sum_{i=1}^{k}x(i)^2-2\sum_{i=1}^{k-1}x(i)x(i+1)=x(1)^2+x(k)^2+\sum_{i=1}^{k-1}\bigl(x(i)-x(i+1)\bigr)^2 ,x⊤Ak​x=2i=1∑k​x(i)2−2i=1∑k−1​x(i)x(i+1)=x(1)2+x(k)2+i=1∑k−1​(x(i)−x(i+1))2,

and 0≤x⊤Akx≤4∥x∥20\le x^\top A_kx\le 4\|x\|^20≤x⊤Ak​x≤4∥x∥2, that is 0⪯Ak⪯4In0\preceq A_k\preceq 4I_n0⪯Ak​⪯4In​.

The bound Ak⪯4InA_k\preceq4I_nAk​⪯4In​ is what makes the hard instance of Theorem 3.14 β\betaβ-smooth, and Ak⪰0A_k\succeq0Ak​⪰0 makes it convex.

Formalization Note x(i)x(i)x(i) is the book's 1-based coordinate (coord x i). The case k=0k=0k=0 is excluded because the identity refers to x(1)x(1)x(1) and x(k)x(k)x(k).

Preamble
import Mathlib
import Definitions.Def_ConvexOptAlg_LowerBounds_Defs

open scoped InnerProductSpace
Formal statement
namespace ConvexOptAlg.LowerBounds

/-- Bubeck, arXiv:1405.4980v2, proof of Theorem 3.14, p. 282: for `1 ≤ k ≤ n` the tridiagonal
matrix `A_k` is symmetric and satisfies `0 ⪯ A_k ⪯ 4Iₙ`, because
`xᵀA_k x = 2 Σ_{i=1}^{k} x(i)² − 2 Σ_{i=1}^{k−1} x(i)x(i+1) = x(1)² + x(k)² + Σ_{i=1}^{k−1} (x(i) − x(i+1))²`.
Coordinates `x(i)` are the book's 1-based ones (`coord x i` is the `Fin n` entry `i − 1`). -/
theorem thm_3_14_tridiag_psd (n k : ℕ) (hk : 1 ≤ k) (hkn : k ≤ n) :
    (tridiag n k).IsSymm ∧
      ∀ x : EuclideanSpace ℝ (Fin n),
        quadForm (tridiag n k) x =
            2 * ∑ i ∈ Finset.Icc 1 k, coord x i ^ 2
              - 2 * ∑ i ∈ Finset.Icc 1 (k - 1), coord x i * coord x (i + 1) ∧
          2 * ∑ i ∈ Finset.Icc 1 k, coord x i ^ 2
              - 2 * ∑ i ∈ Finset.Icc 1 (k - 1), coord x i * coord x (i + 1) =
            coord x 1 ^ 2 + coord x k ^ 2
              + ∑ i ∈ Finset.Icc 1 (k - 1), (coord x i - coord x (i + 1)) ^ 2 ∧
          0 ≤ quadForm (tridiag n k) x ∧ quadForm (tridiag n k) x ≤ 4 * ‖x‖ ^ 2 := by sorry

end ConvexOptAlg.LowerBounds
Source
Bubeck, arXiv:1405.4980v2, proof of Theorem 3.14, p. 282

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