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Canonical bandit occupation identities

Proved
BanditAlgorithm.bandit_canonical_occupation_identities

by MKPynnic · Jul 18, 2026 · Mathlib c5ea003 (Lean v4.30.0)

bandit-algorithmsprobability

For the canonical finite-armed bandit model with integrable reward laws, the expected cumulative reward is the arm-mean-weighted expected occupation count,

E ⁣[∑t=1nXt]=∑i=1kμi E[Ti(n)],\mathbb{E}\!\left[\sum_{t=1}^n X_t\right]=\sum_{i=1}^k \mu_i\,\mathbb{E}[T_i(n)],E[t=1∑n​Xt​]=i=1∑k​μi​E[Ti​(n)],

and the expected occupation counts sum to the horizon, ∑iE[Ti(n)]=n\sum_i \mathbb E[T_i(n)]=n∑i​E[Ti​(n)]=n. The first identity is the conditional-reward calculation in the proof of the regret decomposition lemma; the second is the finite indicator identity ∑i1{At=i}=1\sum_i \mathbf 1\{A_t=i\}=1∑i​1{At​=i}=1 summed over rounds.

Preamble
import Definitions.Def_banditRegret

open MeasureTheory ProbabilityTheory
Formal statement
namespace BanditAlgorithm

theorem bandit_canonical_occupation_identities {k : ℕ} (ν : StochasticBandit k)
    (hInt : ∀ i, Integrable id (ν.P i)) (π : BanditPolicy k) (n : ℕ) :
    (∫ h, (∑ t, (h t).2) ∂(banditMeasure ν π n) =
      ∑ i, banditArmMean ν i *
        ∫ h, (armPullCount i h : ℝ) ∂(banditMeasure ν π n)) ∧
    (∑ i, ∫ h, (armPullCount i h : ℝ) ∂(banditMeasure ν π n)) = n := by
  sorry

end BanditAlgorithm
Source
Lattimore and Szepesvári, Bandit Algorithms (CUP 2020), proof of Lemma 4.5, printed p. 63, especially Eq. (4.6), https://tor-lattimore.com/downloads/book/book.pdf

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