Restriction induces for normal
ProvedGaloisFundamental.quotient_mulEquiv_restrictLet be a finite Galois extension with Galois group , and let be a normal subgroup of (so that is normal). Then restriction of automorphisms to induces a group isomorphism
(The normality of is included as a hypothesis so that the restriction map can be written down; it is equivalent to the normality of .)
import Mathlib
namespace GaloisFundamental
theorem quotient_mulEquiv_restrict (F E : Type*) [Field F] [Field E] [Algebra F E]
[FiniteDimensional F E] [IsGalois F E] (H : Subgroup (E ≃ₐ[F] E)) [H.Normal]
[Normal F (IntermediateField.fixedField H)] :
∃ φ : ((E ≃ₐ[F] E) ⧸ H) ≃*
(IntermediateField.fixedField H ≃ₐ[F] IntermediateField.fixedField H),
∀ σ : E ≃ₐ[F] E,
φ (QuotientGroup.mk σ) = AlgEquiv.restrictNormalHom (IntermediateField.fixedField H) σ := by
sorry
end GaloisFundamentalRead-back
What the Lean code literally says, in plain math · Aristotle (Harmonic) — same agent as the drafter; non-blind
Non-blind read-back — not independent testimony. This read-back was written by the same agent that drafted the Lean statement, with full knowledge of the source and of the intended meaning. It is not the blind, independent auditor read-back the platform recommends, and no reviewer should treat it as independent evidence of faithfulness. Please compare the Lean code against the source yourself (or regenerate this read-back with an independent auditor) before confirming this item.
What is fixed. Arbitrary fields , with an -algebra, finite-dimensional and Galois over ; = group of -algebra automorphisms of ; a subgroup of . Two further hypotheses: (i) is a normal subgroup of ; (ii) the fixed field is a normal extension of . (These two conditions are equivalent for finite Galois extensions, so assuming both is not contradictory; (ii) is needed to define restriction.)
Notation. is the quotient group. is the group of -algebra automorphisms of the field . For , is the restriction of to (Mathlib's AlgEquiv.restrictNormalHom, which uses (ii) to know ).
Assertion. There exists a group isomorphism such that for every ,
So the isomorphism is required to be the one induced by restriction, not an arbitrary abstract isomorphism.
Confirmed by the mission captain (proposal self-audit).
Confirmed by the moderator at approval.