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Symmetric links are passive

Proved
PassivityTorus.passive_of_symm

by ShapeZero · Sep 24, 2026 · Mathlib 0df444a (Lean v4.33.1)

latticelinear-algebramatrices

Let W(x,a)W(x,a)W(x,a) be real d×dd\times dd×d link matrices on the periodic lattice (Z/LZ)q(\mathbb{Z}/L\mathbb{Z})^q(Z/LZ)q with L≥1L \ge 1L≥1, and suppose every one is symmetric, W(x,a)T=W(x,a)W(x,a)^{\mathsf T} = W(x,a)W(x,a)T=W(x,a). Then for every velocity field vvv,

PW(v)=0.P_W(v) = 0 .PW​(v)=0.

This is the "if" direction of the goal, valid for every lattice size.

Preamble
import Mathlib
import Definitions.Def_PassivityTorus_power

open Matrix BigOperators
Formal statement
namespace PassivityTorus
theorem passive_of_symm (q L d : ℕ) [NeZero L]
    (W : Site q L → Fin q → Matrix (Fin d) (Fin d) ℝ) (hW : ∀ x a, (W x a)ᵀ = W x a)
    (v : Site q L → (Fin d → ℝ)) : power q L d W v = 0 := by sorry
end PassivityTorus
Source
Shape Zero LLC, "Formal Proofs of the C1 Verification Package" (August 2026), §6, Theorem 6.1 (extended to a q-dimensional periodic lattice): https://github.com/ShapeZeroSZ/shape-zero/blob/main/01_source/proofs/ShapeZero_C1_Formal_Proofs.pdf ; corrected in "Errata — C1 Formal Proofs (Sections 3 and 6)", Corrected Theorem 6.1(a): https://github.com/ShapeZeroSZ/shape-zero/blob/main/01_source/proofs/ERRATUM_Theorem_6.1.md
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What the Lean code literally says, in plain math · claude-opus-5-5

Setting. Let q,L,dq, L, dq,L,d be natural numbers, with the standing assumption L≠0L \neq 0L=0 (so L≥1L \ge 1L≥1). There are no other restrictions: q=0q = 0q=0 and d=0d = 0d=0 are allowed. A site is any function x:{0,…,q−1}→Z/LZx : \{0,\dots,q-1\} \to \mathbb{Z}/L\mathbb{Z}x:{0,…,q−1}→Z/LZ, which is a point of the discrete torus (Z/LZ)q(\mathbb{Z}/L\mathbb{Z})^q(Z/LZ)q. Write xax_axa​ for its aaa-th coordinate. The shift of xxx in direction a∈{0,…,q−1}a \in \{0,\dots,q-1\}a∈{0,…,q−1} by s∈Z/LZs \in \mathbb{Z}/L\mathbb{Z}s∈Z/LZ is the site that agrees with xxx in every coordinate except aaa, where the value becomes xa+sx_a + sxa​+s computed modulo LLL:

(shift⁡(x,a,s))b={xa+s(modL)b=a,xbb≠a.(\operatorname{shift}(x,a,s))_b = \begin{cases} x_a + s \pmod L & b = a,\\ x_b & b \neq a.\end{cases}(shift(x,a,s))b​={xa​+s(modL)xb​​b=a,b=a.​

We write x+ea:=shift⁡(x,a,1)x + e_a := \operatorname{shift}(x,a,1)x+ea​:=shift(x,a,1) and x−ea:=shift⁡(x,a,−1)x - e_a := \operatorname{shift}(x,a,-1)x−ea​:=shift(x,a,−1). Here −1-1−1 means the residue L−1L-1L−1, so x−eax - e_ax−ea​ changes coordinate aaa to xa+(L−1)≡xa−1(modL)x_a + (L-1) \equiv x_a - 1 \pmod Lxa​+(L−1)≡xa​−1(modL). Both shifts wrap around periodically. When L=1L = 1L=1, the only residue is 000, so 1=−1=01 = -1 = 01=−1=0 and x±ea=xx \pm e_a = xx±ea​=x.

Data. The statement takes:

  • a family of real d×dd \times dd×d matrices Wx,aW_{x,a}Wx,a​, one for each site xxx and each direction a∈{0,…,q−1}a \in \{0,\dots,q-1\}a∈{0,…,q−1};
  • a vector field vvv that assigns to each site xxx a vector v(x)∈Rdv(x) \in \mathbb{R}^dv(x)∈Rd. Nothing is assumed about vvv.

Definition of power. The power of (W,v)(W, v)(W,v) is the real number

P(W,v)  =  ∑x∈(Z/L)q  ∑a=0q−1  v(x)⋅(Wx,a v(x+ea)  −  Wx−ea, a v(x−ea)).P(W,v) \;=\; \sum_{x \in (\mathbb{Z}/L)^q} \;\sum_{a=0}^{q-1} \; v(x) \cdot \Big( W_{x,a}\, v(x+e_a) \;-\; W_{x-e_a,\,a}\, v(x-e_a) \Big).P(W,v)=x∈(Z/L)q∑​a=0∑q−1​v(x)⋅(Wx,a​v(x+ea​)−Wx−ea​,a​v(x−ea​)).

Here ⋅\cdot⋅ is the standard dot product ∑i=1duiwi\sum_{i=1}^d u_i w_i∑i=1d​ui​wi​ on Rd\mathbb{R}^dRd, and W uW\,uWu is the ordinary matrix–vector product. The outer sum runs over all LqL^qLq sites, and the inner sum runs over all qqq directions. The matrix in the second term is indexed by the shifted site x−eax - e_ax−ea​ and the same direction aaa.

Hypothesis. Every matrix in the family is symmetric:

Wx,aT=Wx,afor all sites x and all directions a.W_{x,a}^{\mathsf T} = W_{x,a} \quad\text{for all sites } x \text{ and all directions } a.Wx,aT​=Wx,a​for all sites x and all directions a.

Assertion. For all q,L,dq, L, dq,L,d with L≥1L \ge 1L≥1, every symmetric family WWW as above, and every vector field v:(Z/L)q→Rdv : (\mathbb{Z}/L)^q \to \mathbb{R}^dv:(Z/L)q→Rd,

P(W,v)=0.P(W,v) = 0.P(W,v)=0.

Degenerate cases included by the quantifiers.

  • q=0q = 0q=0: there is exactly one site (the empty function), and the direction sum is empty, so P=0P = 0P=0 regardless of WWW and vvv.
  • d=0d = 0d=0: every vector and every dot product is zero, so P=0P = 0P=0.
  • L=1L = 1L=1: there is exactly one site, and x±ea=xx \pm e_a = xx±ea​=x. Each summand is v(x)⋅(Wx,a−Wx,a) v(x)=0v(x)\cdot(W_{x,a} - W_{x,a})\,v(x) = 0v(x)⋅(Wx,a​−Wx,a​)v(x)=0, so P=0P = 0P=0 even without symmetry.
  • L=2L = 2L=2: the residues satisfy 1=−11 = -11=−1, so x+ea=x−eax + e_a = x - e_ax+ea​=x−ea​.

The symmetry hypothesis can always be satisfied, for example by W≡0W \equiv 0W≡0.

Human review
  • Endorsed by Shuze Chen · Sep 24, 2026

    Confirmed by the moderator at approval.

  • Endorsed by ShapeZero · Sep 24, 2026

    Confirmed by the mission captain (proposal self-audit).

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