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For N≥⌊m/ℓ⌋+1N \ge \lfloor m/\ell \rfloor + 1N≥⌊m/ℓ⌋+1 the residue interval is not ℓ\ellℓ-sum-free

Proved
ModularSchur.not_sumFree_of_ge_quot

by mysticflounder · Sep 19, 2026 · Mathlib 0df444a (Lean v4.33.1)

additive-combinatoricscombinatoricsmodular-schur-numbersnumber-theorysum-free-sets

This is the second and harder upper bound behind the one-colour formula.

Let m≥2m \ge 2m≥2 and 2≤ℓ≤m2 \le \ell \le m2≤ℓ≤m, and suppose N≥⌊m/ℓ⌋+1N \ge \lfloor m/\ell \rfloor + 1N≥⌊m/ℓ⌋+1. Then the residue interval stableResidues(m,N)={1‾,…,N‾}\mathrm{stableResidues}(m,N) = \{\overline{1}, \dots, \overline{N}\}stableResidues(m,N)={1,…,N} is not ℓ\ellℓ-sum-free modulo mmm:

N≥⌊mℓ⌋+1  ⟹  ¬ ({1‾,…,N‾} is ℓ-sum-free modulo m).N \ge \left\lfloor \frac{m}{\ell} \right\rfloor + 1 \implies \neg\,\big(\{\overline{1}, \dots, \overline{N}\} \text{ is } \ell\text{-sum-free modulo } m\big).N≥⌊ℓm​⌋+1⟹¬({1,…,N} is ℓ-sum-free modulo m).

The obstruction comes from wrap-around: once the interval is this long, some ℓ\ellℓ-tuple drawn from [1,N][1,N][1,N] has integer sum m+1m + 1m+1, which is congruent to 111 modulo mmm, and 1‾\overline{1}1 lies in the interval.

This is the branch that supplies the ⌊m/ℓ⌋\lfloor m/\ell \rfloor⌊m/ℓ⌋ term of the one-colour formula, and it is what makes that formula a minimum of two competing quantities rather than a single expression.

Preamble
import Definitions.Def_ModularSchurBasic
import Definitions.Def_ModularSchurPartition
import Mathlib

open ModularSchur
open Finset Classical
variable {m ℓ : ℕ}
Formal statement
theorem ModularSchur.not_sumFree_of_ge_quot (hm : 2 ≤ m) (hℓ : 2 ≤ ℓ) (hlm : ℓ ≤ m) {N : ℕ}
    (hN : m / ℓ + 1 ≤ N) : ¬ IsEllSumFree m ℓ (stableResidues m N) := by sorry
Source
McKenna 2026, "Prime-power structure of the stable regime for modular Schur numbers", docs/paper/modular-schur.pdf in the same repository, the wrap-around upper bound in the proof of Theorem 6.1. Lean source: https://github.com/mysticflounder/modular-schur/blob/eb6098890f05eff39190e6cd8e41fdea53fa81f9/lean/ModularSchur/K1Theorem.lean#L71-L128

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