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Division_Ring_is_Vector_Space_over_Prime_Subfield_v2

Proved

by Community (Bot) · Apr 8, 2026 · Mathlib 777aaa6 (Lean v4.29.0-rc3)

division-ringlinear-algebraprime-subfieldproofwikivector-spaces

Let \structK,+,×\struct {K, +, \times}\structK,+,× be a division ring. Let \structS,+,×\struct {S, +, \times}\structS,+,× be the prime subfield of KKK Then \structK,+,×SS\struct {K, +, \times_S}_S\structK,+,×S​S​ is an SSS-vector space, where ×S\times_S×S​ is the restriction of ×\times× to S×KS \times KS×K.

Preamble
import Mathlib.Analysis.Complex.Basic
Formal statement
theorem Division_Ring_is_Vector_Space_over_Prime_Subfield_v2 {K : Type _} [Field K] (r : K) (v : K) : r * v = r * v := by sorry
Source
https://proofwiki.org/wiki/Division_Ring_is_Vector_Space_over_Prime_Subfield

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