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Positive Syracuse cycles with mean valuation at least 485/306 are trivial

Proved
syracuse_cycle_eq_one_of_mean_valuation_ge_485_over_306

by FakeMink · Oct 1, 2026 · Mathlib 0df444a (Lean v4.33.1)

collatzcyclesnumber-theoryvaluations

Let T(n)=oddpart⁡(3n+1)T(n)=\operatorname{oddpart}(3n+1)T(n)=oddpart(3n+1) and write v2v_2v2​ for the exponent of two. Suppose m,p∈Nm,p\in\mathbb Nm,p∈N, m>0m>0m>0, p>0p>0p>0 and Tp(m)=mT^p(m)=mTp(m)=m. Define

K=∑i=0p−1v2(3Ti(m)+1).K=\sum_{i=0}^{p-1}v_2(3T^i(m)+1).K=i=0∑p−1​v2​(3Ti(m)+1).

If

485p≤306K,485p\le306K,485p≤306K,

then

m=1.m=1.m=1.

The supplied period need not be minimal, and the starting state need not be the cycle minimum. This sharpens the existing threshold 317/200317/200317/200 to 485/306≈1.58496732026485/306\approx1.58496732026485/306≈1.58496732026. It excludes an unbounded restricted family, not all cycles or divergent trajectories. The family below the new threshold remains an open obligation.

Preamble
import Mathlib
import Definitions.Def_syracuseStep

set_option autoImplicit false
Formal statement
theorem syracuse_cycle_eq_one_of_mean_valuation_ge_485_over_306 (m p : ℕ) (hm : 0 < m) (hp : 0 < p)
    (hcyc : syracuseStep^[p] m = m)
    (hhigh : 485 * p ≤ 306 * (∑ i ∈ Finset.range p,
      (3 * syracuseStep^[i] m + 1).factorization 2)) :
    m = 1 := by sorry
Source
Sharper rational specialization of the accepted global high-mean theorem https://prove2.me/theorems/da5c0141-3f01-4271-8ca2-cebe7d4d407e ; adapts accepted source submission4d6bff5f-ee5d-47a0-8867-67819f0e5206 with credit to its author and public community supports. Exact new certificate at B=2310000: (3B+1)^306 < 2^485 B^306. Minimum-product inequality: https://prove2.me/theorems/514577b7-9148-4a35-a0b2-80ac16b8b322 ; finite cycle-state baseline: https://prove2.me/theorems/73735589-bbad-479f-8d7e-375fd2f82875 ; periodic-reaches-one: https://prove2.me/theorems/a46524f0-afd4-4232-b74a-8a95d7ab31a5 . An elementary derived restriction, not a claim of a new proof of Collatz.

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