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A geometric lag weight sums to O(N)O(N)O(N) regardless of the horizon

Proved
MarkovChainCLT.sum_geometric_lag_le

by LukeBernese · Aug 16, 2026 · Mathlib c5ea003 (Lean v4.30.0)

analysisfinite-sumsgeometric-seriesmarkov-chainvariance

A lag sum of a block-geometric weight is bounded uniformly in nnn. For every j<nj < nj<n,

∑k<n2−⌊∣j−k∣/N⌋  ≤  4N.\sum_{k<n} 2^{-\lfloor |j-k|/N\rfloor} \;\le\; 4N .k<n∑​2−⌊∣j−k∣/N⌋≤4N.

The bound does not grow with nnn: although the sum has nnn terms, the weight decays geometrically in the lag ∣j−k∣|j-k|∣j−k∣, so only O(N)O(N)O(N) of the mass survives.

Where it is used. For a uniformly ergodic Markov chain the autocovariance obeys ∣E[r(Xj)r(Xk)]∣≤2−⌊∣j−k∣/N⌋∥r∥L2(π)2|\mathbb E[r(X_j)r(X_k)]| \le 2^{-\lfloor|j-k|/N\rfloor}\|r\|_{L^2(\pi)}^2∣E[r(Xj​)r(Xk​)]∣≤2−⌊∣j−k∣/N⌋∥r∥L2(π)2​. Expanding the square of a partial sum,

Var⁡(∑k<nr(Xk))  =  ∑j<n∑k<nE[r(Xj)r(Xk)]  ≤  ∥r∥L2(π)2∑j<n∑k<n2−⌊∣j−k∣/N⌋  ≤  4N n ∥r∥L2(π)2.\operatorname{Var}\Bigl(\sum_{k<n}r(X_k)\Bigr) \;=\; \sum_{j<n}\sum_{k<n}\mathbb E[r(X_j)r(X_k)] \;\le\; \|r\|_{L^2(\pi)}^2\sum_{j<n}\sum_{k<n}2^{-\lfloor|j-k|/N\rfloor} \;\le\; 4N\,n\,\|r\|_{L^2(\pi)}^2 .Var(k<n∑​r(Xk​))=j<n∑​k<n∑​E[r(Xj​)r(Xk​)]≤∥r∥L2(π)2​j<n∑​k<n∑​2−⌊∣j−k∣/N⌋≤4Nn∥r∥L2(π)2​.

This is exactly the O(n)O(n)O(n) variance bound — with a constant proportional to ∥r∥L22\|r\|_{L^2}^2∥r∥L22​ rather than ∥r∥∞2\|r\|_\infty^2∥r∥∞2​ — that controls the truncation error when the Markov chain central limit theorem is extended from bounded to square-integrable observables.

Proof. Two steps.

The one-sided sum. Grouping the lags into blocks of length NNN, on which ⌊d/N⌋\lfloor d/N\rfloor⌊d/N⌋ is constant,

∑d<qN2−⌊d/N⌋  =  ∑p<qN 2−p  ≤  2N(1−2−q),\sum_{d<qN} 2^{-\lfloor d/N\rfloor} \;=\; \sum_{p<q} N\,2^{-p} \;\le\; 2N\bigl(1-2^{-q}\bigr),d<qN∑​2−⌊d/N⌋=p<q∑​N2−p≤2N(1−2−q),

an induction on qqq whose step uses ⌊(pN+i)/N⌋=p\lfloor (pN+i)/N\rfloor = p⌊(pN+i)/N⌋=p for i<Ni<Ni<N. Since m≤mNm \le mNm≤mN when N≥1N\ge1N≥1 and all terms are nonnegative, ∑d<m2−⌊d/N⌋≤2N\sum_{d<m}2^{-\lfloor d/N\rfloor} \le 2N∑d<m​2−⌊d/N⌋≤2N for every mmm.

The two-sided sum. Split {k<n}\{k<n\}{k<n} at jjj. On {k≤j}\{k\le j\}{k≤j} the lag is j−kj-kj−k and k↦j−kk\mapsto j-kk↦j−k is injective with image inside {0,…,n−1}\{0,\dots,n-1\}{0,…,n−1} (using j<nj<nj<n); on {k>j}\{k>j\}{k>j} the lag is k−jk-jk−j and k↦k−jk\mapsto k-jk↦k−j is injective with image inside {0,…,n−1}\{0,\dots,n-1\}{0,…,n−1} as well. Each half is therefore bounded by the one-sided sum ≤2N\le 2N≤2N, giving 4N4N4N in total.

Preamble
import Mathlib.Algebra.BigOperators.Intervals
import Mathlib.Algebra.Order.BigOperators.Group.Finset
import Mathlib.Analysis.SpecificLimits.Basic

open Finset
Formal statement
theorem MarkovChainCLT.sum_geometric_lag_le (N : ℕ) (hN : 1 ≤ N) (n j : ℕ) (hj : j < n) :
    ∑ k ∈ Finset.range n, (1 / 2 : ℝ) ^ ((max j k - min j k) / N) ≤ 4 * N := by sorry
Source
I. A. Ibragimov and Yu. V. Linnik, Independent and Stationary Sequences of Random Variables, Wolters-Noordhoff 1971, Ch. 18; P. Billingsley, Convergence of Probability Measures, 2nd ed., Wiley 1999, Section 19; G. L. Jones, "On the Markov Chain Central Limit Theorem", Probability Surveys 1 (2004) 299-320.

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