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A ppp-adic Schwarz lemma for restricted power series with zeros of high order

Proved
IsUltrametricDist.norm_tsum_mul_pow_le_of_hasseDeriv_eq_zero

by ebayuser · Oct 4, 2026 · Mathlib 0df444a (Lean v4.33.1)

analysisnumber-theoryp-adicpower-seriestranscendence

Let KKK be a complete field with an ultrametric norm. Let f(X)=∑k≥0ckXkf(X) = \sum_{k \ge 0} c_k X^kf(X)=∑k≥0​ck​Xk be a power series with ck→0c_k \to 0ck​→0 and ∥ck∥≤M\|c_k\| \le M∥ck​∥≤M for all kkk (a restricted power series, which converges on the closed unit disc). Let 0≤r≤10 \le r \le 10≤r≤1, let Z⊆KZ \subseteq KZ⊆K be a finite set of points with ∥z∥≤r\|z\| \le r∥z∥≤r, and let T≥0T \ge 0T≥0. Assume that fff vanishes to order at least TTT at each point of ZZZ: for each z0∈Zz_0 \in Zz0​∈Z and each t<Tt < Tt<T,

∑k≥t(kt)ckz0 k−t=0.\sum_{k \ge t} \binom{k}{t} c_k z_0^{\,k-t} = 0 .k≥t∑​(tk​)ck​z0k−t​=0.

Then for each z∈Kz \in Kz∈K with ∥z∥≤r\|z\| \le r∥z∥≤r,

∥f(z)∥  ≤  r T⋅∣Z∣ M.\|f(z)\| \;\le\; r^{\,T \cdot |Z|} \, M .∥f(z)∥≤rT⋅∣Z∣M.

Proof idea. A restricted power series that vanishes at a point z0z_0z0​ of the closed unit disc is (X−z0)(X - z_0)(X−z0​) times a restricted power series with the same bound MMM for its coefficients (re-expand at z0z_0z0​; the Gauss norm is multiplicative and X−z0X - z_0X−z0​ has Gauss norm 111). Induction gives f=∏z0∈Z(X−z0)T⋅gf = \prod_{z_0 \in Z} (X - z_0)^T \cdot gf=∏z0​∈Z​(X−z0​)T⋅g with ∥g(z)∥≤M\|g(z)\| \le M∥g(z)∥≤M on the unit disc. For ∥z∥≤r\|z\| \le r∥z∥≤r each factor has ∥z−z0∥≤r\|z - z_0\| \le r∥z−z0​∥≤r.

Use. This is the analytic estimate of Baker's method in the ppp-adic setting: a function with many zeros of high order in a small disc is small on that disc. It is a tool for NumberField.Brumer.extrapolation_step.

Formalization Note. The series are ∑' k, c k * z ^ k; the left side of the hypothesis is the Hasse derivative of order ttt, written ∑' k, (k.choose t : K) * c k * z ^ (k - t) with natural subtraction (terms with k<tk < tk<t are zero). All series converge because the terms tend to 000. For T=0T = 0T=0 or Z=∅Z = \emptysetZ=∅ the bound is ∥f(z)∥≤M\|f(z)\| \le M∥f(z)∥≤M. Mathlib (at this revision) has no maximum principle for non-archimedean power series; NonarchimedeanAddGroup.summable_of_tendsto_cofinite_zero gives convergence.

Preamble
import Mathlib
Formal statement
theorem IsUltrametricDist.norm_tsum_mul_pow_le_of_hasseDeriv_eq_zero {K : Type*} [NormedField K]
    [IsUltrametricDist K] [CompleteSpace K]
    (c : ℕ → K) (hc : Filter.Tendsto c Filter.atTop (nhds 0)) (M : ℝ) (hM : ∀ k, ‖c k‖ ≤ M)
    (r : ℝ) (hr0 : 0 ≤ r) (hr1 : r ≤ 1) (Z : Finset K) (hZ : ∀ z ∈ Z, ‖z‖ ≤ r) (T : ℕ)
    (hzero : ∀ z ∈ Z, ∀ t < T, ∑' k : ℕ, (k.choose t : K) * c k * z ^ (k - t) = 0)
    (z : K) (hz : ‖z‖ ≤ r) :
    ‖∑' k : ℕ, c k * z ^ k‖ ≤ r ^ (T * Z.card) * M := by sorry
Source
The non-archimedean Schwarz lemma used in ppp-adic transcendence: J.-P. Serre, Dépendance d'exponentielles ppp-adiques, Séminaire Delange-Pisot-Poitou 7 (1965-66), exposé 15, as cited ("lemme de Schwarz et Mahler") in B. Rousseau, Séminaire de Théorie des Nombres de Bordeaux 1968-1969, exposé 11, p. 6. The statement here is for a series given by its coefficients, with zeros of order TTT expressed by Hasse derivatives.

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