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JAO Theorem 5, small-diameter regime D<12D < 12D<12 (footnote 11)

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BanditAlgorithm.mdp_regret_lower_bound_jao_small_diameter

by Grace · Aug 5, 2026 · Mathlib c5ea003 (Lean v4.30.0)

banditslower-boundmarkov-decision-processreinforcement-learning

For any algorithm and any S,A≥10S, A \ge 10S,A≥10, D≥20log⁡ASD \ge 20\log_A SD≥20logA​S and T≥DSAT \ge DSAT≥DSA, there is an MDP with SSS states, AAA actions and diameter at most DDD on which, from every initial state, the expected regret after TTT steps is at least 0.015DSAT0.015\sqrt{DSAT}0.015DSAT​.

This is the small-diameter regime D<12D < 12D<12, which JAO treat separately in footnote 11 (p. 1582) because their main construction assumes δ=4/D≤1/3\delta = 4/D \le 1/3δ=4/D≤1/3. In this regime the hypotheses force A>2SA > 2SA>2S: from D≥20log⁡ASD \ge 20\log_A SD≥20logA​S and D<12D < 12D<12 one gets log⁡AS<3/5\log_A S < 3/5logA​S<3/5, hence S<A3/5S < A^{3/5}S<A3/5 and so A>S5/3>2SA > S^{5/3} > 2SA>S5/3>2S for S≥10S \ge 10S≥10.

With that many actions a different and simpler construction works. Use S−1S-1S−1 of the actions to connect all states to each other, producing an MDP of diameter 111, and with the remaining A−S+1A - S + 1A−S+1 actions set up an independent bandit problem in each state, exactly one state having a better action, as in the lower bound of Auer et al. (2002b). This yields regret Ω(SAT)\Omega(\sqrt{SAT})Ω(SAT​), which suffices here precisely because DDD is bounded by a constant, so DSAT\sqrt{DSAT}DSAT​ and SAT\sqrt{SAT}SAT​ agree up to a constant factor.

This case is absent from the Lattimore-Szepesvari account of the result.

This is the original statement, with the explicit constant 0.0150.0150.015 and the initial state universally quantified, as opposed to the Lattimore-Szepesvari restatement (Bandit Algorithms, Theorem 38.7) which asserts the bound for S≥3S \ge 3S≥3, A≥2A \ge 2A≥2 with an unspecified universal constant. The hypothesis S,A≥10S, A \ge 10S,A≥10 is not cosmetic: JAO's construction uses a two-state gadget with A′=⌈(A−1)/2⌉A' = \lceil (A-1)/2 \rceilA′=⌈(A−1)/2⌉ actions together with A′+1A'+1A′+1 further actions per state to connect the copies, so at A=2A = 2A=2 the construction does not exist, and the final constant is obtained from kA′≥20kA' \ge 20kA′≥20.


⚠ Not provable from the source as stated — see below. The constant 0.0150.0150.015 on DSAT\sqrt{DSAT}DSAT​ does not follow from JAO Section 6. The proof ends at 0.015D′kA′T0.015\sqrt{D'kA'T}0.015D′kA′T​ with D′=D/4D' = D/4D′=D/4, k=⌊S/2⌋k = \lfloor S/2\rfloork=⌊S/2⌋, A′=⌊(A−1)/2⌋A' = \lfloor (A-1)/2\rfloorA′=⌊(A−1)/2⌋; since the composite MDP must fit in SSS states and AAA actions, 2k≤S2k \le S2k≤S and 2A′+1≤A2A'+1 \le A2A′+1≤A, hence D′kA′≤DSA/16D'kA' \le DSA/16D′kA′≤DSA/16 and the proven bound is at most 0.0039DSAT0.0039\sqrt{DSAT}0.0039DSAT​. The exact supremum over S,A≥10S, A \ge 10S,A≥10 is 0.015/22=0.003200.015/\sqrt{22} = 0.003200.015/22​=0.00320, attained at (S,A)=(11,10)(S,A) = (11,10)(S,A)=(11,10). The rest of Section 6 is correct: its bracket at kA′=20kA' = 20kA′=20 evaluates to 0.016660>0.0150.016660 > 0.0150.016660>0.015 as claimed. The error is a single unstated substitution D′kA′→DSAD'kA' \to DSAD′kA′→DSA in the final line.

This node is kept only as a record of the statement as published. Work instead on BanditAlgorithm.mdp_regret_lower_bound_jao_universal_constant, which carries the same hypotheses and the same DSAT\sqrt{DSAT}DSAT​ scaling with a universal but unspecified constant. See mission comment afe04135 for the full computation.

Preamble
import Definitions.Def_FiniteMDPLearning
import Mathlib.Data.Real.Sqrt
import Mathlib.Analysis.SpecialFunctions.Log.Basic

open MeasureTheory ProbabilityTheory
Formal statement
theorem BanditAlgorithm.mdp_regret_lower_bound_jao_small_diameter :
    ∀ S A T : ℕ, ∀ D : ℝ, 10 ≤ S → 10 ≤ A →
      20 * (Real.log S / Real.log A) ≤ D → D * S * A ≤ (T : ℝ) → D < 12 →
        ∀ π : MDPPolicy S A,
          ∃ M : FiniteMDP S A,
            mdpDiameterENN M ≤ ENNReal.ofReal D ∧
            ∀ s : Fin S,
              0.015 * Real.sqrt (D * S * A * T) ≤
                ∫ h, mdpRegret M T h ∂(mdpMeasure M (mdpStateDirac s) π T) := by
  sorry
Source
Thomas Jaksch, Ronald Ortner, Peter Auer, "Near-optimal Regret Bounds for Reinforcement Learning", Journal of Machine Learning Research 11 (2010) 1563-1600, Theorem 5, p. 1567; proof in Section 6 "The Lower Bound", pp. 1582-1586. Footnote 11 on p. 1582: the case delta > 1/3, i.e. D < 12, where A > 2S and the alternative diameter-1 construction with a bandit in each state gives Omega(sqrt(SAT)).

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