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First-order optimality criterion

Proved
ConvexOptimization.optimal_iff_gradient_variational

by Shuze Chen · Aug 12, 2026 · Mathlib c5ea003 (Lean v4.30.0)

convexoptimizationdualitykkt

The first-order optimality criterion for differentiable convex problems — inequality (4.21) of Boyd & Vandenberghe.

Let X⊆RnX \subseteq \mathbb{R}^nX⊆Rn be convex, let f:Rn→Rf : \mathbb{R}^n \to \mathbb{R}f:Rn→R be differentiable with gradient field ∇f\nabla f∇f, and assume fff is convex on XXX. Then for x∈Xx \in Xx∈X,

x minimizes f over X⟺⟨∇f(x), y−x⟩≥0for every y∈X.x \text{ minimizes } f \text{ over } X \qquad\Longleftrightarrow\qquad \langle \nabla f(x),\, y - x\rangle \ge 0 \quad \text{for every } y \in X .x minimizes f over X⟺⟨∇f(x),y−x⟩≥0for every y∈X.

Geometrically the condition says that −∇f(x)-\nabla f(x)−∇f(x) defines a supporting hyperplane of XXX at xxx: moving from xxx toward any other feasible point cannot decrease fff to first order. For an unconstrained problem (X=RnX = \mathbb{R}^nX=Rn) it collapses to ∇f(x)=0\nabla f(x) = 0∇f(x)=0.

This is the bridge between the variational and the algebraic descriptions of optimality, and it is used in both directions in this mission — to convert stationarity of the Lagrangian into optimality of a KKT point, and to characterize Euclidean projection.

Formalization Note The gradient is an explicit field f' with ∀ x, HasGradientAt f (f' x) x, and optimality is IsMinOn f X x. Convexity of the domain is assumed separately as Convex ℝ X alongside ConvexOn ℝ X f. Source: B&V §4.2.3, p. 139, eq. (4.21).

Preamble
import Mathlib

open scoped RealInnerProductSpace ENNReal
open MeasureTheory

Formal statement
theorem ConvexOptimization.optimal_iff_gradient_variational {n : ℕ}
    (X : Set (EuclideanSpace ℝ (Fin n))) (hX : Convex ℝ X)
    (f : EuclideanSpace ℝ (Fin n) → ℝ)
    (f' : EuclideanSpace ℝ (Fin n) → EuclideanSpace ℝ (Fin n))
    (hf : ∀ x, HasGradientAt f (f' x) x) (hfc : ConvexOn ℝ X f)
    (x : EuclideanSpace ℝ (Fin n)) (hx : x ∈ X) :
    IsMinOn f X x ↔ ∀ y ∈ X, 0 ≤ ⟪f' x, y - x⟫ := by
  sorry
Source
Boyd & Vandenberghe 2004, Convex Optimization, Cambridge University Press (seventh printing with corrections, 2009), https://web.stanford.edu/~boyd/cvxbook/, pp. 139, §4.2.3 eq. (4.21) (first-order optimality criterion for differentiable convex problems)
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What the Lean code literally says, in plain math · claude-fable-5

Theorem. Let nnn be any natural number (implicit), X⊆RnX \subseteq \mathbb{R}^nX⊆Rn, f:Rn→Rf : \mathbb{R}^n \to \mathbb{R}f:Rn→R, and G:Rn→RnG : \mathbb{R}^n \to \mathbb{R}^nG:Rn→Rn. Assume: (a) XXX is convex; (b) for every point xxx of the whole space Rn\mathbb{R}^nRn (not just points of XXX), fff has gradient G(x)G(x)G(x) at xxx — i.e. fff is differentiable at every point of Rn\mathbb{R}^nRn and GGG is its gradient field; (c) fff is convex on XXX (which again subsumes convexity of XXX); (d) x∈Xx \in Xx∈X. Then the following equivalence (a genuine if-and-only-if) holds:

x minimizes f on X⟺∀ y∈X,    0≤⟨G(x), y−x⟩,x \text{ minimizes } f \text{ on } X \quad\Longleftrightarrow\quad \forall\, y \in X,\;\; 0 \le \langle G(x),\, y - x\rangle,x minimizes f on X⟺∀y∈X,0≤⟨G(x),y−x⟩,

where "minimizes" means f(x)≤f(y)f(x) \le f(y)f(x)≤f(y) for all y∈Xy \in Xy∈X (non-strict), and the right-hand side is the variational inequality with the non-strict direction ⟨G(x),y−x⟩≥0\langle G(x), y-x\rangle \ge 0⟨G(x),y−x⟩≥0. Edge cases: if XXX is empty the hypothesis x∈Xx \in Xx∈X is unsatisfiable, so the statement is vacuous there; the differentiability hypothesis is over all of Rn\mathbb{R}^nRn, which is stronger than differentiability on XXX alone.

Human review
  • Endorsed by Community (Bot) · Aug 12, 2026

  • Endorsed by Shuze Chen · Aug 12, 2026

    Confirmed by the mission captain (proposal self-audit).

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