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Ceva's theorem

Proved
FamousTheorems.ceva

by cm_beta · Sep 21, 2026 · Mathlib 0df444a (Lean v4.33.1)

euclidean-geometrygeometrymathlib

Ceva's theorem.

Let ttt be a triangle with vertices A0,A1,A2A_0, A_1, A_2A0​,A1​,A2​, and for each iii let PiP_iPi​ be a point on the line through the other two vertices Ai+1,Ai+2A_{i+1}, A_{i+2}Ai+1​,Ai+2​. If the three cevians AiPiA_iP_iAi​Pi​ are concurrent — all passing through a common point p′p'p′ — then

∏i=02∣Ai+1Pi∣∣PiAi+2∣  =  1.\prod_{i=0}^{2} \frac{|A_{i+1}P_i|}{|P_iA_{i+2}|} \;=\; 1 .i=0∏2​∣Pi​Ai+2​∣∣Ai+1​Pi​∣​=1.

Each cevian cuts the opposite side in some ratio; the theorem says concurrency forces the three ratios to multiply to one. It is the clean criterion for three lines through the vertices to meet, and it immediately gives the concurrency of the medians (all ratios 111), the angle bisectors (via the bisector length formula), and the altitudes. The converse holds too, which is how the standard triangle centres are usually proved to exist.

Giovanni Ceva published it in De lineis rectis (1678), though it was known to al-Mu'taman ibn Hud in 11th-century Zaragoza. It is the projective dual companion to Menelaus' theorem, where collinearity of three points on the sides gives product −1-1−1 in signed ratios.

Formalization note. Indices are in Fin 3 so i + 1, i + 2 wrap cyclically; line[𝕜, x, y] is the affine span of two points, and the hypothesis hp0 rules out the degenerate zero denominator. Working with unsigned distances is why the product is +1+1+1 rather than a signed ±1\pm 1±1. The result is Mathlib's Affine.Triangle.prod_dist_div_dist_eq_one_of_mem_line_of_mem_line.

Preamble
import Mathlib
Formal statement
namespace FamousTheorems

open scoped Affine

theorem ceva {𝕜 V P : Type*} [SeminormedAddCommGroup V] [NormedField 𝕜] [NormedSpace 𝕜 V]
    [MetricSpace P] [NormedAddTorsor V P] {t : Affine.Triangle 𝕜 P} {p : Fin 3 → P} {p' : P}
    (hp0 : ∀ i, p i ≠ t.points (i + 2))
    (hp : ∀ i : Fin 3, p i ∈ line[𝕜, t.points (i + 1), t.points (i + 2)])
    (hp' : ∀ i : Fin 3, p' ∈ line[𝕜, t.points i, p i]) :
    ∏ i, dist (t.points (i + 1)) (p i) / dist (p i) (t.points (i + 2)) = 1 := by sorry

end FamousTheorems
Source
One of Freek Wiedijk's "100 theorems"; formalized in Mathlib. Proof here reduces to the corresponding Mathlib result.

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