The nonlocal case of the semilocal semiring Picard question
DisprovedRybinAI2026.P19.nonlocal_semilocal_invertible_module_freeinvertible-modulespicard-groupssemirings
Let be a nonzero commutative semiring with finitely many maximal ideals, and assume that is not local. Is every invertible -module free? This is precisely the remaining nonlocal case of the positive semilocal Picard-group question after the local and zero-semiring cases are removed. No assumption that the maximal ideals are subtractive is made.
Preamble
import Mathlib.RingTheory.PicardGroup import Mathlib.RingTheory.LocalRing.Basic
Formal statement
theorem RybinAI2026.P19.nonlocal_semilocal_invertible_module_free
(R M : Type*) [CommSemiring R] [Nontrivial R] [Finite (MaximalSpectrum R)]
[AddCommMonoid M] [Module R M] [Module.Invertible R M]
(hlocal : ¬ IsLocalRing R) : Module.Free R M := by sorrySource
Junyan Xu, Picard group of semi-local or finite semirings, https://mathoverflow.net/questions/511864; Rybin problem 19, https://rybindmitry.github.io/problems/19.html. This is the nonlocal restriction of the original question, not a claim established by Borger and Jun.