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Poiseuille's law: Q=πΔp d4/(128ηL)Q=\pi\Delta p\,d^4/(128\eta L)Q=πΔpd4/(128ηL)

Proved
MathematicsOfWater.poiseuille_law

by Lucas · Sep 24, 2026 · Mathlib 0df444a (Lean v4.33.1)

fluid-dynamicsmathematical-physicsode

Consider steady pressure-driven flow of a Newtonian fluid of viscosity η>0\eta>0η>0 through a cylindrical pipe of diameter d>0d>0d>0 and length L>0L>0L>0 with pressure drop Δp=p(0)−p(L)∈R\Delta p=p(0)-p(L)\in\mathbb RΔp=p(0)−p(L)∈R. Let v(r)v(r)v(r) be the axial velocity at distance rrr from the axis, and assume

  1. vvv solves the radial momentum balance 1rddr(rdvdr)=−ΔpηL\frac1r\frac{d}{dr}\big(r\frac{dv}{dr}\big)=-\frac{\Delta p}{\eta L}r1​drd​(rdrdv​)=−ηLΔp​ for 0<r<d/20<r<d/20<r<d/2;
  2. vvv is finite (bounded) near the axis;
  3. vvv satisfies the no-slip condition v(d/2)=0v(d/2)=0v(d/2)=0 at the wall, continuously from inside.

Then the volumetric flow rate is

Q=∫0d/2v(r) 2πr dr=π Δp d4128 ηL.Q=\int_0^{d/2}v(r)\,2\pi r\,dr=\frac{\pi\,\Delta p\,d^4}{128\,\eta L}.Q=∫0d/2​v(r)2πrdr=128ηLπΔpd4​.

This is Poiseuille's (Hagen–Poiseuille) law: the flow rate scales with the fourth power of the pipe diameter.

Formalization Note The hypotheses are packaged in the definition IsPipeFlow; the flow rate is the definition flowRate.

Preamble
import Mathlib
import Definitions.Def_MathematicsOfWater_PipeFlow
open Real
Formal statement
namespace MathematicsOfWater
theorem poiseuille_law (η L Δp d : ℝ) (v : ℝ → ℝ)
    (hη : 0 < η) (hL : 0 < L) (hd : 0 < d)
    (hv : IsPipeFlow η L Δp d v) :
    flowRate d v = π * Δp * d ^ 4 / (128 * η * L) := by sorry
end MathematicsOfWater
Source
Lecture 15: The Mathematics of Water, PHYS 461 & 561 (Biophysics), Drexel University, Fall 2011-2012, 11/15/2011, lecturer Luis Cruz (for Brigita Urbanc), www.physics.drexel.edu/~brigita/COURSES/BIOPHYS_2011-2012/, slides 13–16 (goal: Q = π Δp d^4 / (128 η L), slide 16)
Read-back

What the Lean code literally says, in plain math · Aristotle (Harmonic) — NON-BLIND, same agent as drafter

Non-blind read-back — not independent testimony. This read-back was written by the same agent (Aristotle, by Harmonic) that drafted these Lean statements, at the explicit request of the proposal owner. It is not the blind, independent auditor read-back the platform recommends; the author knew the intended meaning while writing it. Reviewers must check it against the Lean code themselves and should not treat it as independent confirmation of faithfulness.

Fix real numbers η,L,Δp,d\eta,L,\Delta p,dη,L,Δp,d and v:R→Rv:\mathbb R\to\mathbb Rv:R→R with η>0\eta>0η>0, L>0L>0L>0, d>0d>0d>0; Δp\Delta pΔp is arbitrary. Write R=d/2R=d/2R=d/2 and v′(s)v'(s)v′(s) for the derivative of vvv at sss (000 where vvv is not differentiable). Assume:

  1. for every 0<r<R0<r<R0<r<R: vvv is differentiable at rrr, g(s)=s v′(s)g(s)=s\,v'(s)g(s)=sv′(s) is differentiable at rrr, and 1rg′(r)=−ΔpηL\frac1r g'(r)=-\frac{\Delta p}{\eta L}r1​g′(r)=−ηLΔp​;
  2. some real MMM bounds ∣v(r)∣≤M|v(r)|\le M∣v(r)∣≤M for all 0<r<R0<r<R0<r<R;
  3. v(x)→v(R)v(x)\to v(R)v(x)→v(R) as x→Rx\to Rx→R from the left;
  4. v(R)=0v(R)=0v(R)=0.

Conclusion:

∫0d/2v(r)⋅2πr dr=π Δp d4128 η L.\int_0^{d/2} v(r)\cdot2\pi r\,dr=\frac{\pi\,\Delta p\,d^4}{128\,\eta\,L}.∫0d/2​v(r)⋅2πrdr=128ηLπΔpd4​.

The integral is the oriented Lebesgue (interval) integral over [0,d/2][0,d/2][0,d/2]; by the platform's convention it would equal 000 if the integrand were not integrable, so the statement implicitly also requires the actual integral to have this value. The value v(0)v(0)v(0) and values outside (0,d/2](0,d/2](0,d/2] play no role except through the integral, where the single point r=0r=0r=0 has measure zero. The hypotheses are satisfiable (by v(r)=Δp4ηL(d24−r2)v(r)=\frac{\Delta p}{4\eta L}(\frac{d^2}{4}-r^2)v(r)=4ηLΔp​(4d2​−r2)).

Human review
  • Endorsed by Shuze Chen · Sep 24, 2026

    Confirmed by the moderator at approval.

  • Endorsed by Lucas · Sep 24, 2026

    Confirmed by the mission captain (proposal self-audit).

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