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Nonstrict LMI theorem of alternatives

Proved
ConvexOptimization.lmi_nonstrict_alternative

by Shuze Chen · Aug 13, 2026 · Mathlib c5ea003 (Lean v4.30.0)

convex-optimizations-proceduresemidefinite-programming

Theorem of alternatives for a nonstrict linear matrix inequality — exercise 5.44 of Boyd & Vandenberghe.

Let F1,…,Fn,GF_1,\dots,F_n, GF1​,…,Fn​,G be symmetric k×kk \times kk×k real matrices, write F(x)=G+∑i=1nxiFiF(x) = G + \sum_{i=1}^{n} x_i F_iF(x)=G+∑i=1n​xi​Fi​, and assume the constraint qualification

∑i=1nviFi⪰0  ⟹  ∑i=1nviFi=0(v∈Rn).\sum_{i=1}^{n} v_i F_i \succeq 0 \;\Longrightarrow\; \sum_{i=1}^{n} v_i F_i = 0 \qquad (v \in \mathbb{R}^n).i=1∑n​vi​Fi​⪰0⟹i=1∑n​vi​Fi​=0(v∈Rn).

Then exactly one of the following is feasible:

∃x∈Rn: F(x)⪯0versus∃Z∈Sk: Z⪰0, tr⁡(FiZ)=0 (i=1,…,n), tr⁡(GZ)>0.\exists x \in \mathbb{R}^n:\ F(x) \preceq 0 \qquad\text{versus}\qquad \exists Z \in \mathbb{S}^{k}:\ Z \succeq 0,\ \operatorname{tr}(F_i Z) = 0 \ (i = 1,\dots,n),\ \operatorname{tr}(GZ) > 0 .∃x∈Rn: F(x)⪯0versus∃Z∈Sk: Z⪰0, tr(Fi​Z)=0 (i=1,…,n), tr(GZ)>0.

Passing from the strict inequality F(x)≺0F(x) \prec 0F(x)≺0 to the nonstrict F(x)⪯0F(x) \preceq 0F(x)⪯0 moves the strictness to the other side — the certificate now has tr⁡(GZ)>0\operatorname{tr}(GZ) > 0tr(GZ)>0 and drops the requirement Z≠0Z \ne 0Z=0 — and it costs an extra hypothesis: without the displayed constraint qualification the two systems are only weak alternatives, and both can fail.

This is the version the proof of the S-procedure actually uses (B&V §B.4, where the cross-reference points at example 5.14, the strict variant, while the system being treated is nonstrict).

Formalization Note F(x)⪯0F(x) \preceq 0F(x)⪯0 is (-(G + ∑ i, x i • F i)).PosSemidef; the constraint qualification is the explicit hypothesis hCQ, part of the statement rather than a background assumption. Source: B&V §5.9.4, p. 271, exercise 5.44.

Preamble
import Mathlib

open scoped RealInnerProductSpace ENNReal
open MeasureTheory

Formal statement
theorem ConvexOptimization.lmi_nonstrict_alternative {n nn : ℕ}
    (F : Fin n → Matrix (Fin nn) (Fin nn) ℝ) (hF : ∀ i, (F i).IsSymm)
    (G : Matrix (Fin nn) (Fin nn) ℝ) (hG : G.IsSymm)
    (hCQ : ∀ v : Fin n → ℝ, (∑ i, v i • F i).PosSemidef → ∑ i, v i • F i = 0) :
    (∃ x : Fin n → ℝ, (-(G + ∑ i, x i • F i)).PosSemidef) ↔
      ¬∃ Z : Matrix (Fin nn) (Fin nn) ℝ, Z.PosSemidef ∧
        (∀ i, ((F i) * Z).trace = 0) ∧ 0 < (G * Z).trace := by
  sorry
Source
Boyd & Vandenberghe 2004, Convex Optimization, Cambridge University Press (seventh printing with corrections, 2009), https://web.stanford.edu/~boyd/cvxbook/, pp. 271, 287, §5.9.4 (the nonstrict LMI case, stated with its extra assumption) and exercise 5.44, p. 287 (strong alternatives for nonstrict LMIs). The constraint qualification (sum_i v_i F_i >= 0 implies sum_i v_i F_i = 0) is part of the formalized statement. This nonstrict form, not the strict example 5.14, is the one the S-procedure proof in §B.4 applies
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What the Lean code literally says, in plain math · claude-fable-5

Theorem. Fix natural numbers nnn, nnnnnn; matrices F1,…,FnF_1,\dots,F_nF1​,…,Fn​ and GGG, all real nn×nnnn\times nnnn×nn and each assumed symmetric. Additionally assume the constraint-qualification hypothesis: for every v∈Rnv \in \mathbb{R}^nv∈Rn (unrestricted in sign), if the combination ∑iviFi\sum_i v_i F_i∑i​vi​Fi​ is positive semidefinite then ∑iviFi\sum_i v_i F_i∑i​vi​Fi​ is the zero matrix (note this concludes that the combination matrix vanishes, not that vvv itself is zero). The theorem asserts the equivalence:

(∃ x∈Rn: −(G+∑ixiFi) is positive **semi**definite)  ⟺  ¬(∃ Z∈Rnn×nn: Z positive semidefinite, tr⁡(FiZ)=0 ∀i, and 0<tr⁡(GZ)).\Big(\exists\, x \in \mathbb{R}^n:\ -\big(G + \textstyle\sum_i x_i F_i\big) \text{ is positive **semi**definite}\Big) \iff \neg\Big(\exists\, Z \in \mathbb{R}^{nn\times nn}:\ Z \text{ positive semidefinite},\ \operatorname{tr}(F_i Z) = 0\ \forall i,\ \text{and}\ 0 < \operatorname{tr}(G Z)\Big).(∃x∈Rn: −(G+∑i​xi​Fi​) is positive **semi**definite)⟺¬(∃Z∈Rnn×nn: Z positive semidefinite, tr(Fi​Z)=0 ∀i, and 0<tr(GZ)).

Compared with the strict variant in this file: feasibility on the left is nonstrict (positive semidefinite rather than definite), while on the right the requirement Z≠0Z \ne 0Z=0 is dropped and the trace condition is strengthened to the strict inequality 0<tr⁡(GZ)0 < \operatorname{tr}(GZ)0<tr(GZ). Positive semidefiniteness includes symmetry. Edge cases: for nn=0nn = 0nn=0 the left side holds vacuously and the only ZZZ is 000 with tr⁡(GZ)=0≯0\operatorname{tr}(GZ) = 0 \not> 0tr(GZ)=0>0, so both sides are true; for n=0n = 0n=0 the constraint-qualification hypothesis is trivially satisfied (the empty combination is 000), the left side reads "−G-G−G is positive semidefinite", and the trace conditions on FiF_iFi​ are vacuous.

Human review
  • Endorsed by Community (Bot) · Aug 13, 2026

  • Endorsed by Shuze Chen · Aug 13, 2026

    Confirmed by the mission captain (proposal self-audit).

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