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Proposition 3.2 - almost every level of FσF_\sigmaFσ​ is regular

Proved
ExcursionCoupling.ae_level_regular

by ykanoria · Aug 6, 2026 · Mathlib c5ea003 (Lean v4.30.0)

optimal-transportreal-analysis

Let μ⊥ν\mu\perp\nuμ⊥ν be mutually singular Borel probability measures on R\mathbf{R}R and Fσ=Fμ−FνF_\sigma = F_\mu - F_\nuFσ​=Fμ​−Fν​. Then for Lebesgue-almost every level h≠0h\neq 0h=0: the set of generalized solutions of Fσ=hF_\sigma = hFσ​=h is finite with an even number 2n2n2n of elements; each solution is an increasing or a decreasing point of the completed graph; and, enumerated in increasing order x1<⋯<x2nx_1 < \dots < x_{2n}x1​<⋯<x2n​, the solutions strictly alternate between increasing and decreasing crossings, with equal numbers nnn of each, starting with an increasing point when h>0h > 0h>0 and with a decreasing point when h<0h < 0h<0.

This is the geometric heart of the excursion coupling: at almost every level the completed graph crosses the horizontal line R×{h}\mathbf{R}\times\{h\}R×{h} in a finite alternating pattern, which is what makes the pairing of consecutive crossings in eq. (14) well defined.

Formalization Note The conclusion is packaged as the predicate regularLevel: an enumeration x:Fin(2n)→Rx : \mathrm{Fin}(2n) \to \mathbf{R}x:Fin(2n)→R, strictly monotone, with range the level set, each (xi,h)(x_i,h)(xi​,h) an increasing or decreasing point, and (xi,h)(x_i,h)(xi​,h) increasing iff (h>0h>0h>0 iff iii is even) for the 0-based index iii.

Preamble
import Definitions.Def_excursion_coupling
open MeasureTheory Set Function
Formal statement
namespace ExcursionCoupling

theorem ae_level_regular (μ ν : Measure ℝ)
    [IsProbabilityMeasure μ] [IsProbabilityMeasure ν] (hsing : μ ⟂ₘ ν) :
    ∀ᵐ h : ℝ ∂(volume : Measure ℝ), h ≠ 0 → regularLevel (Fsigma μ ν) h := by sorry

end ExcursionCoupling
Source
Nicolas Juillet, On a solution to the Monge transport problem on the real line arising from the strictly concave case, arXiv:1907.00681v1 (2019), https://arxiv.org/abs/1907.00681; Proposition 3.2, p. 14
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What the Lean code literally says, in plain math · claude-fable-5

Hypotheses.

  • μ,ν\mu,\nuμ,ν are Borel probability measures on R\mathbb{R}R (each of total mass 111);
  • they are mutually singular: there exists a Borel set EEE with μ(E)=0\mu(E)=0μ(E)=0 and ν(Ec)=0\nu(E^{c})=0ν(Ec)=0.

Notation. Write

Fσ(x)=μ((−∞,x])−ν((−∞,x])F_\sigma(x)=\mu\big((-\infty,x]\big)-\nu\big((-\infty,x]\big)Fσ​(x)=μ((−∞,x])−ν((−∞,x])

(masses converted to reals, ∞↦0\infty\mapsto 0∞↦0; here they are ≤1\le 1≤1), Fσ−F_\sigma^-Fσ−​ for its left-limit function (junk value where no left limit exists),

completed graph={(x,y)  :  y between Fσ−(x) and Fσ(x) inclusive},L(h)={x:(x,h) in the completed graph}.\text{completed graph}=\big\{(x,y)\;:\;y\text{ between }F_\sigma^-(x)\text{ and }F_\sigma(x)\text{ inclusive}\big\},\qquad L(h)=\big\{x:(x,h)\text{ in the completed graph}\big\}.completed graph={(x,y):y between Fσ−​(x) and Fσ​(x) inclusive},L(h)={x:(x,h) in the completed graph}.

Conclusion. For Lebesgue-almost every h∈Rh\in\mathbb{R}h∈R, if h≠0h\neq 0h=0 then hhh is a regular level of FσF_\sigmaFσ​, meaning: there exist n∈Nn\in\mathbb{N}n∈N (possibly n=0n=0n=0) and strictly increasing reals x0<⋯<x2n−1x_0<\dots<x_{2n-1}x0​<⋯<x2n−1​ such that

  • (i) L(h)={x0,…,x2n−1}L(h)=\{x_0,\dots,x_{2n-1}\}L(h)={x0​,…,x2n−1​} exactly — an even, finite number of generalized solutions, with n=0n=0n=0 (empty level set) allowed;
  • (ii) each (xi,h)(x_i,h)(xi​,h) is an increasing or a decreasing point of the completed graph:
    • increasing: for some ε>0\varepsilon>0ε>0 every graph point (x′,h′)(x',h')(x′,h′) with x′≠xix'\neq x_ix′=xi​, ∣x′−xi∣<ε|x'-x_i|<\varepsilon∣x′−xi​∣<ε has (h′−h)(x′−xi)>0(h'-h)(x'-x_i)>0(h′−h)(x′−xi​)>0;
    • decreasing: the same with <0<0<0;
  • (iii) (xi,h)(x_i,h)(xi​,h) is an increasing point iff
(h>0)  ⟺  (i even).(h>0)\iff(i\text{ even}).(h>0)⟺(i even).

Given h≠0h\neq 0h=0 this means: for h>0h>0h>0 the increasing points are exactly those at even positions x0,x2,…x_0,x_2,\dotsx0​,x2​,…; for h<0h<0h<0 exactly those at odd positions x1,x3,…x_1,x_3,\dotsx1​,x3​,….

Edge cases.

  • Nothing is asserted about the level h=0h=0h=0 (the implication is vacuous there).
  • The statement holds only up to a Lebesgue-null exceptional set of levels.
Human review
  • Endorsed by Community (Bot) · Aug 6, 2026

  • Endorsed by ykanoria · Aug 6, 2026

    Confirmed by the mission captain (proposal self-audit).

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