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The flow matrix is antisymmetric

Proved
OctonionD8.flow_antisymm

by ShapeZero · Sep 27, 2026 · Mathlib 0df444a (Lean v4.33.1)

characteristic-polynomialfano-planelinear-algebraoctonions

For all real c,sc, sc,s, the flow matrix M=Re1+Lce1+se2M = R_{e_1} + L_{c e_1 + s e_2}M=Re1​​+Lce1​+se2​​ satisfies

MT=−M,M^{\mathsf T} = -M ,MT=−M,

so the flow p˙=Mp\dot p = M pp˙​=Mp conserves the norm ∣p∣|p|∣p∣.

Preamble
import Mathlib
import Definitions.Def_OctonionD8_flow
Formal statement
namespace OctonionD8

open Polynomial

theorem flow_antisymm (c s : ℝ) : (flowMat c s).transpose = -flowMat c s := by
  sorry

end OctonionD8
Source
Motivated by the two-generator D8 flow in the Shape Zero derivation (Shape Zero LLC): https://github.com/ShapeZeroSZ/shape-zero/blob/main/00_START_HERE/MODEL_SPEC.md §1b and https://github.com/ShapeZeroSZ/shape-zero/blob/main/02_synthesis/D8_SYNTHESIS.md ; Fano plane: Prove2Me definition RolesForceSeven.fano (mission "The role postulates force exactly seven points") ; public references: Wikipedia, "Octonion": https://en.wikipedia.org/wiki/Octonion ; Wikipedia, "Fano plane": https://en.wikipedia.org/wiki/Fano_plane
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What the Lean code literally says, in plain math · claude-opus-5-5

flow_antisymm. For all real numbers c,sc, sc,s (no hypotheses on them, so c=s=0c = s = 0c=s=0 is included), the 8×88\times 88×8 real matrix F(c,s)F(c,s)F(c,s) defined below is skew-symmetric:

F(c,s)T=−F(c,s),i.e.F(c,s)jk=−F(c,s)kj  for all j,k∈{0,…,7}.F(c,s)^{\mathsf T} = -F(c,s), \qquad\text{i.e.}\qquad F(c,s)_{jk} = -F(c,s)_{kj}\ \text{ for all } j,k \in \{0,\dots,7\}.F(c,s)T=−F(c,s),i.e.F(c,s)jk​=−F(c,s)kj​  for all j,k∈{0,…,7}.

The underlying bilinear product on R8\mathbb R^8R8. Index coordinates by {0,1,…,7}\{0,1,\dots,7\}{0,1,…,7} with standard basis e0,…,e7e_0,\dots,e_7e0​,…,e7​. Relabel the indices 1,…,71,\dots,71,…,7 as points of Z/7\mathbb Z/7Z/7 via π(i)=(i+6) mod 7\pi(i) = (i+6) \bmod 7π(i)=(i+6)mod7, i.e. π(i)=i−1\pi(i) = i-1π(i)=i−1 for 1≤i≤71 \le i \le 71≤i≤7 (also π(0)=6\pi(0)=6π(0)=6, but index 000 never reaches the rule where π\piπ is used). The "lines" are the seven 3-element sets Lℓ={ℓ, ℓ+1, ℓ+3}⊆Z/7L_\ell = \{\ell,\ \ell+1,\ \ell+3\} \subseteq \mathbb Z/7Lℓ​={ℓ, ℓ+1, ℓ+3}⊆Z/7 for ℓ∈Z/7\ell \in \mathbb Z/7ℓ∈Z/7 (arithmetic mod 777). An integer structure constant T(i,j,k)T(i,j,k)T(i,j,k) (the eke_kek​-coefficient of eieje_i e_jei​ej​) is defined by the first applicable clause:

  1. if i=0i = 0i=0: T=1T = 1T=1 if j=kj = kj=k, else 000;
  2. else if j=0j = 0j=0: T=1T = 1T=1 if i=ki = ki=k, else 000;
  3. else if i=ji = ji=j: T=−1T = -1T=−1 if k=0k = 0k=0, else 000;
  4. else if k=0k = 0k=0: T=0T = 0T=0;
  5. else if there is ℓ\ellℓ with Lℓ={π(i),π(j),π(k)}L_\ell = \{\pi(i),\pi(j),\pi(k)\}Lℓ​={π(i),π(j),π(k)} and (π(i),π(j))(\pi(i),\pi(j))(π(i),π(j)) is one of (ℓ,ℓ+1)(\ell,\ell+1)(ℓ,ℓ+1), (ℓ+1,ℓ+3)(\ell+1,\ell+3)(ℓ+1,ℓ+3), (ℓ+3,ℓ)(\ell+3,\ell)(ℓ+3,ℓ): T=+1T = +1T=+1;
  6. else if there is ℓ\ellℓ with Lℓ={π(i),π(j),π(k)}L_\ell = \{\pi(i),\pi(j),\pi(k)\}Lℓ​={π(i),π(j),π(k)}: T=−1T = -1T=−1;
  7. otherwise T=0T = 0T=0.

(In clauses 5–6, if kkk equals iii or jjj the set {π(i),π(j),π(k)}\{\pi(i),\pi(j),\pi(k)\}{π(i),π(j),π(k)} has at most two elements and cannot be a line, so T=0T=0T=0.) The product of p,q∈R8p, q \in \mathbb R^8p,q∈R8 is

(p⋅q)k=∑i=07∑j=07pi qj T(i,j,k).(p\cdot q)_k = \sum_{i=0}^{7}\sum_{j=0}^{7} p_i\, q_j\, T(i,j,k).(p⋅q)k​=i=0∑7​j=0∑7​pi​qj​T(i,j,k).

Thus e0e_0e0​ is a two-sided identity, eiei=−e0e_i e_i = -e_0ei​ei​=−e0​ for i≠0i \ne 0i=0, and for distinct nonzero i,ji,ji,j, eiej=±eke_i e_j = \pm e_kei​ej​=±ek​ where π(k)\pi(k)π(k) is the third point of the line through π(i),π(j)\pi(i),\pi(j)π(i),π(j), with sign +++ exactly when (π(i),π(j))(\pi(i),\pi(j))(π(i),π(j)) follows the cyclic order ℓ→ℓ+1→ℓ+3→ℓ\ell \to \ell+1 \to \ell+3 \to \ellℓ→ℓ+1→ℓ+3→ℓ on that line.

The matrix. For a∈R8a \in \mathbb R^8a∈R8, RaR_aRa​ is the matrix with (Ra)kj=(ej⋅a)k(R_a)_{kj} = (e_j\cdot a)_k(Ra​)kj​=(ej​⋅a)k​ (the matrix of right multiplication x↦x⋅ax \mapsto x\cdot ax↦x⋅a), and LbL_bLb​ has (Lb)kj=(b⋅ej)k(L_b)_{kj} = (b\cdot e_j)_k(Lb​)kj​=(b⋅ej​)k​ (the matrix of left multiplication x↦b⋅xx \mapsto b\cdot xx↦b⋅x). Then

F(c,s)=Re1+Lc e1+s e2,F(c,s)kj=T(j,1,k)+c T(1,j,k)+s T(2,j,k).F(c,s) = R_{e_1} + L_{c\,e_1 + s\,e_2}, \qquad F(c,s)_{kj} = T(j,1,k) + c\,T(1,j,k) + s\,T(2,j,k).F(c,s)=Re1​​+Lce1​+se2​​,F(c,s)kj​=T(j,1,k)+cT(1,j,k)+sT(2,j,k).

The theorem asserts that, for every c,s∈Rc,s\in\mathbb Rc,s∈R, this matrix equals the negative of its transpose (equivalently all diagonal entries vanish and Fjk=−FkjF_{jk} = -F_{kj}Fjk​=−Fkj​ for j≠kj \ne kj=k). The Steiner-triple-system structure and other imported auxiliary definitions do not appear in the statement; only the line sets LℓL_\ellLℓ​ are used.

Human review
  • Endorsed by Shuze Chen · Sep 27, 2026

    Confirmed by the moderator at approval.

  • Endorsed by ShapeZero · Sep 27, 2026

    Confirmed by the mission captain (proposal self-audit).

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