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Proposition 1.19 -- detailed balance implies stationarity

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MarkovMixing.detailed_balance_stationary

by Shuze Chen · Aug 21, 2026 · Mathlib c5ea003 (Lean v4.30.0)

markov-chainsmixing-timesprobability

If a probability distribution π\piπ satisfies the detailed balance equations π(x)P(x,y)=π(y)P(y,x)\pi(x)P(x,y)=\pi(y)P(y,x)π(x)P(x,y)=π(y)P(y,x) for all states x,yx,yx,y of a stochastic matrix PPP, then π\piπ is stationary for PPP. This is the standard tool for identifying stationary distributions of reversible chains.

Preamble
import Definitions.Def_mm_basic
Formal statement
namespace MarkovMixing

/-- **Proposition 1.19** (LPW): any probability distribution satisfying the
detailed balance equations is stationary. -/
theorem detailed_balance_stationary {V : Type*} [Fintype V] [DecidableEq V]
    (P : Matrix V V ℝ) (hP : IsStochastic P) (π : V → ℝ) (hπ : IsDist π)
    (hdb : DetailedBalance P π) :
    IsStationary P π := by
  sorry

end MarkovMixing
Source
D. A. Levin, Y. Peres, E. L. Wilmer, Markov Chains and Mixing Times, AMS 2009, https://documents.epfl.ch/groups/i/ip/ipg/www/2013-2014/Random_Walks/markovmixing.pdf, Section 1.6, Proposition 1.19, p. 14
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What the Lean code literally says, in plain math · claude-fable-5

Let VVV be an arbitrary finite type (of any universe) equipped with decidable equality; VVV may be empty. Let PPP be a V×VV \times VV×V matrix with real entries, and assume PPP is stochastic in the sense that every entry is nonnegative (0≤Px,y0 \le P_{x,y}0≤Px,y​ for all x,y∈Vx, y \in Vx,y∈V) and every row sums to one (∑y∈VPx,y=1\sum_{y \in V} P_{x,y} = 1∑y∈V​Px,y​=1 for all x∈Vx \in Vx∈V; note that when VVV is empty this row condition is vacuously true, since there are no rows). Let π:V→R\pi : V \to \mathbb{R}π:V→R be a function assumed to be a distribution, meaning πx≥0\pi_x \ge 0πx​≥0 for every x∈Vx \in Vx∈V and ∑x∈Vπx=1\sum_{x \in V} \pi_x = 1∑x∈V​πx​=1 (a condition that is unsatisfiable when VVV is empty, since the empty sum is 0≠10 \ne 10=1, making the theorem vacuous in that case). Finally, assume the detailed-balance condition: for all x,y∈Vx, y \in Vx,y∈V,

πx Px,y=πy Py,x.\pi_x \, P_{x,y} = \pi_y \, P_{y,x}.πx​Px,y​=πy​Py,x​.

The theorem concludes that π\piπ is stationary for PPP, which by the bundle's definition is the conjunction of two claims: (i) π\piπ is again a distribution (every value nonnegative and the values sum to one — a repetition of the hypothesis on π\piπ), and (ii) the row-vector–matrix product of π\piπ with PPP equals π\piπ, i.e., for every y∈Vy \in Vy∈V,

∑x∈Vπx Px,y=πy.\sum_{x \in V} \pi_x \, P_{x,y} = \pi_y.x∈V∑​πx​Px,y​=πy​.

No irreducibility, aperiodicity, or positivity of π\piπ is assumed, and nothing is claimed about uniqueness of the stationary distribution.

Human review
  • Endorsed by Community (Bot) · Aug 21, 2026

  • Endorsed by Shuze Chen · Aug 21, 2026

    Confirmed by the mission captain (proposal self-audit).

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