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Prime divisors of 2p−12^p-12p−1 have the form 2kp+12kp+12kp+1

Proved
AlfutovaUstinov.problem_4_122

by evgeth · Sep 28, 2026 · Mathlib 0df444a (Lean v4.33.1)

elementary-number-theorymersenne-numbersmultiplicative-ordernumber-theory

This is Problem 4.122 of N. B. Alfutova and A. V. Ustinov, Algebra and Number Theory (MCCME, 2002), Chapter 4, §4 “Theorems of Fermat and Euler”.

Theorem. Let p>2p>2p>2 be a prime number. Then every prime divisor qqq of the Mersenne number 2p−12^{p}-12p−1 has the form

q=2kp+1q = 2kp+1q=2kp+1

for some natural number kkk.

This classical fact about Mersenne numbers (going back to Fermat and Euler) drastically restricts the possible prime factors of 2p−12^p-12p−1 and is used when searching for Mersenne primes.

Formalization Note Here ppp and qqq are natural numbers with Nat.Prime; the subtraction 2p−12^p-12p−1 is natural-number subtraction, which is exact since 2p≥12^p\ge 12p≥1.

Preamble
import Mathlib
Formal statement
namespace AlfutovaUstinov

theorem problem_4_122 (p : ℕ) (hp : p.Prime) (hp2 : 2 < p) (q : ℕ) (hq : q.Prime)
    (hqd : q ∣ 2 ^ p - 1) : ∃ k : ℕ, q = 2 * k * p + 1 := by sorry

end AlfutovaUstinov
Source
N. B. Alfutova, A. V. Ustinov, «Алгебра и теория чисел. Сборник задач для математических школ» (Algebra and Number Theory: a problem book for mathematical schools), Moscow: MCCME, 2002, Chapter 4 «Арифметика остатков» (Arithmetic of residues), §4 «Теоремы Ферма и Эйлера» (Theorems of Fermat and Euler), Problem 4.122. Problem text and answer as catalogued on problems.ru, problem 60748: https://problems.ru/view_problem_details_new.php?id=60748

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