Moment upper and lower bounds for the spherical matrix integral
ProvedRybinAI2026.P01.distance_moment_boundsLet be real symmetric positive-definite matrices, with any natural number. Use the original surface measure on the unit sphere, and write for the defining double spherical integral. For unit vectors , put
Define the two moments with respect to the product of the original surface measures:
Let be a real constant such that for all unit vectors . Then
These moment estimates retain the quadratic denominator and give upper and lower bounds for the matrix integral. Positive choices of and allow division to produce explicit bounds. They can support sufficient conditions for the maximum inequality in Problem 1, but do not assert that inequality for arbitrary quadruples. The moments here use unnormalized surface measure.
Formalization Note The statement also allows dimension zero and does not divide by a moment, by , or by the sphere area.
import Definitions.Def_rybin2026_p01_matrix_integral import Mathlib.MeasureTheory.Integral.Prod open Matrix MeasureTheory Metric RybinAI2026.P01
theorem RybinAI2026.P01.distance_moment_bounds {n : ℕ} (X Y : Matrix (Fin n) (Fin n) ℝ)
(hX : X.PosDef) (hY : Y.PosDef) (L : ℝ)
(hbound : ∀ u v : sphere (0 : Euclidean n) 1,
|bilinear (X-Y) u.1 v.1| ≤ L) :
let μ := (surfaceMeasure n).prod (surfaceMeasure n)
let Q := ∫ p : sphere (0 : Euclidean n) 1 × sphere (0 : Euclidean n) 1,
(bilinear (X-Y) p.1.1 p.2.1)^2 /
(bilinear X p.1.1 p.1.1 * bilinear Y p.2.1 p.2.1) ∂μ
let R := ∫ p : sphere (0 : Euclidean n) 1 × sphere (0 : Euclidean n) 1,
1 / (bilinear X p.1.1 p.1.1 * bilinear Y p.2.1 p.2.1) ∂μ
(∀ t : ℝ, 2*t*distance X Y ≤ Q+t^2*R) ∧
(distance X Y)^2 ≤ Q*R ∧ Q ≤ L*distance X Y := by
sorry