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Evolving-set mixing bound (Morris--Peres)

Proved
MarkovMixing.evolving_sets_mixing

by Shuze Chen · Aug 22, 2026 · Mathlib c5ea003 (Lean v4.30.0)

markov-chainsmixing-timesprobability

Let PPP be an irreducible Markov chain on a finite state space VVV that is lazy — P(x,x)≥12P(x,x)\ge\tfrac12P(x,x)≥21​ at every state — with stationary distribution π\piπ; write πmin⁡=min⁡xπ(x)\pi_{\min}=\min_x\pi(x)πmin​=minx​π(x). Reversibility is not assumed. The bottleneck constant (Mission IV) is

Φ⋆=min⁡{∑x∈S, y∉Sπ(x)P(x,y)π(S)  :  ∅≠S⊆V, π(S)≤12},\Phi_\star=\min\Bigl\{\frac{\sum_{x\in S,\,y\notin S}\pi(x)P(x,y)}{\pi(S)}\;:\;\varnothing\ne S\subseteq V,\ \pi(S)\le\tfrac12\Bigr\},Φ⋆​=min{π(S)∑x∈S,y∈/S​π(x)P(x,y)​:∅=S⊆V, π(S)≤21​},

the worst conditional escape probability of a half-space at stationarity. For a tolerance ε\varepsilonε, the mixing time tmix(ε)t_{\mathrm{mix}}(\varepsilon)tmix​(ε) is the first ttt with max⁡x∥Pt(x,⋅)−π∥TV≤ε\max_x\|P^t(x,\cdot)-\pi\|_{TV}\le\varepsilonmaxx​∥Pt(x,⋅)−π∥TV​≤ε, where ∥μ−ν∥TV=max⁡A∣μ(A)−ν(A)∣\|\mu-\nu\|_{TV}=\max_A|\mu(A)-\nu(A)|∥μ−ν∥TV​=maxA​∣μ(A)−ν(A)∣ is the total variation distance.

The theorem (Theorem 17.10, Morris–Peres; Levin–Peres–Wilmer — the capstone of Chapter 17) asserts: for every 0<ε<10<\varepsilon<10<ε<1,

tmix(ε)  ≤  ⌈2Φ⋆2 log⁡(1ε πmin⁡)⌉t_{\mathrm{mix}}(\varepsilon)\;\le\;\Bigl\lceil\frac{2}{\Phi_\star^{2}}\,\log\Bigl(\frac{1}{\varepsilon\,\pi_{\min}}\Bigr)\Bigr\rceiltmix​(ε)≤⌈Φ⋆2​2​log(επmin​1​)⌉

(the ceiling absorbs the rounding of the real-valued bound to an integer time).

For reversible chains this recovers the Cheeger-route bound of Mission VII — but no reversibility is needed, which is the theorem's point: geometry controls mixing for every lazy chain. The proof analyzes the evolving-set process of this mission: laziness keeps the thresholds tame, the bottleneck constant forces a per-step multiplicative decay of Eπ(St)(1−π(St))\mathbb E\sqrt{\pi(S_t)(1-\pi(S_t))}Eπ(St​)(1−π(St​))​, and the identity Pt(x,y)=π(y)π(x)P{x}{y∈St}P^t(x,y)=\tfrac{\pi(y)}{\pi(x)}\mathbb P_{\{x\}}\{y\in S_t\}Pt(x,y)=π(x)π(y)​P{x}​{y∈St​} converts that decay into total-variation mixing.

Preamble
import Definitions.Def_mm_martingale
import Mathlib.Analysis.SpecialFunctions.Log.Basic
Formal statement
namespace MarkovMixing

/-- **Theorem 17.10** (Morris–Peres; LPW), the capstone of Chapter 17: for a
lazy irreducible chain (no reversibility required!),
`t_mix(ε) ≤ ⌈(2/Φ⋆²) log(1/(ε π_min))⌉` (the ceiling absorbs
integer rounding). -/
theorem evolving_sets_mixing {V : Type*} [Fintype V] [DecidableEq V] [Nonempty V]
    (P : Matrix V V ℝ) (hP : IsStochastic P) (hirr : Irreducible P)
    (hlazy : ∀ x : V, 2⁻¹ ≤ P x x)
    (π : V → ℝ) (hπ : IsStationary P π)
    (ε : ℝ) (hε : 0 < ε) (hε1 : ε < 1) :
    (mixingTime P π ε : ℝ) ≤
      ⌈2 / bottleneckStar P π ^ 2 * Real.log (1 / (ε * ⨅ x : V, π x))⌉₊ := by
  sorry

end MarkovMixing
Source
D. A. Levin, Y. Peres, E. L. Wilmer, Markov Chains and Mixing Times, AMS 2009, https://documents.epfl.ch/groups/i/ip/ipg/www/2013-2014/Random_Walks/markovmixing.pdf, Section 17.4, Theorem 17.10, p. 235
Read-back

What the Lean code literally says, in plain math · claude-fable-5

Read-back: evolving_sets_mixing

Let VVV be a finite, nonempty type with decidable equality, and let PPP be a V×VV \times VV×V real matrix subject to three hypotheses:

  • Stochastic: every entry satisfies P(x,y)≥0P(x,y) \ge 0P(x,y)≥0, and every row sums to 111: ∑yP(x,y)=1\sum_y P(x,y) = 1∑y​P(x,y)=1 for all xxx.
  • Irreducible: for every ordered pair x,y∈Vx, y \in Vx,y∈V there exists t∈Nt \in \mathbb{N}t∈N with (Pt)(x,y)>0(P^t)(x,y) > 0(Pt)(x,y)>0. (The exponent t=0t = 0t=0 is allowed, and P0P^0P0 is the identity, so for x=yx = yx=y this condition is automatically satisfiable by t=0t = 0t=0; the content is for x≠yx \ne yx=y.)
  • Laziness: P(x,x)≥12P(x,x) \ge \tfrac12P(x,x)≥21​ for every x∈Vx \in Vx∈V.

Let π:V→R\pi : V \to \mathbb{R}π:V→R be stationary for PPP: π\piπ is a probability vector (π(x)≥0\pi(x) \ge 0π(x)≥0 for all xxx and ∑xπ(x)=1\sum_x \pi(x) = 1∑x​π(x)=1) and the row-vector product satisfies πP=π\pi P = \piπP=π. Let ε\varepsilonε be a real number with 0<ε<10 < \varepsilon < 10<ε<1.

The conclusion is the inequality

tmix(ε)  ≤  ⌈2Φ⋆2⋅log⁡ ⁣1ε⋅πmin⁡⌉N,t_{\mathrm{mix}}(\varepsilon) \;\le\; \Bigl\lceil \frac{2}{\Phi_\star^{2}} \cdot \log\!\frac{1}{\varepsilon \cdot \pi_{\min}} \Bigr\rceil_{\mathbb{N}},tmix​(ε)≤⌈Φ⋆2​2​⋅logε⋅πmin​1​⌉N​,

where every symbol unfolds as follows.

  • tmix(ε)t_{\mathrm{mix}}(\varepsilon)tmix​(ε) is the mixing time: the least natural number ttt such that
d(t)  =  sup⁡x∈V  sup⁡A⊆V∣ ∑y∈A(Pt)(x,y)−∑y∈Aπ(y)∣  ≤  ε,d(t) \;=\; \sup_{x \in V}\; \sup_{A \subseteq V} \Bigl|\, \sum_{y \in A} (P^{t})(x,y) - \sum_{y \in A} \pi(y) \Bigr| \;\le\; \varepsilon,d(t)=x∈Vsup​A⊆Vsup​​y∈A∑​(Pt)(x,y)−y∈A∑​π(y)​≤ε,

the suprema being over the finite VVV and its subsets. If no time ttt satisfies this, the infimum of the empty set of naturals is the junk value 000. The left-hand side is this natural number cast to R\mathbb{R}R.

  • Φ⋆\Phi_\starΦ⋆​ is the bottleneck ratio: the infimum, over all subsets S⊆VS \subseteq VS⊆V that are nonempty and satisfy π(S):=∑x∈Sπ(x)≤12\pi(S) := \sum_{x \in S}\pi(x) \le \tfrac12π(S):=∑x∈S​π(x)≤21​, of
Φ(S)  =  ∑x∈S∑y∉Sπ(x) P(x,y)∑x∈Sπ(x).\Phi(S) \;=\; \frac{\displaystyle\sum_{x \in S}\sum_{y \notin S} \pi(x)\, P(x,y)}{\displaystyle\sum_{x \in S} \pi(x)} .Φ(S)=x∈S∑​π(x)x∈S∑​y∈/S∑​π(x)P(x,y)​.

Division here is total real division: if π(S)=0\pi(S) = 0π(S)=0 (possible, since π\piπ is only assumed nonnegative), then Φ(S)=0\Phi(S) = 0Φ(S)=0. Moreover, if no subset meets the two side conditions — e.g. when VVV has exactly one element, so the only nonempty SSS has π(S)=1>12\pi(S) = 1 > \tfrac12π(S)=1>21​ — the infimum is taken over an empty family and equals the real junk value inf⁡∅=0\inf \varnothing = 0inf∅=0.

  • πmin⁡=inf⁡x∈Vπ(x)\pi_{\min} = \inf_{x \in V} \pi(x)πmin​=infx∈V​π(x), a genuine minimum over the finite nonempty VVV.

  • log⁡\loglog is the real natural logarithm, and ⌈⋅⌉N\lceil \cdot \rceil_{\mathbb{N}}⌈⋅⌉N​ is the natural-number ceiling, which sends every nonpositive real to 000.

Two junk-value interactions materially shape the edge cases of the right-hand side. First, 2/Φ⋆22/\Phi_\star^22/Φ⋆2​ uses total division, so if Φ⋆=0\Phi_\star = 0Φ⋆​=0 (which occurs both when the infimum family is empty and when some admissible SSS has boundary flow or measure making the infimum 000) then 2/Φ⋆2=2/0=02/\Phi_\star^2 = 2/0 = 02/Φ⋆2​=2/0=0, and the whole right-hand side becomes ⌈0⌉N=0\lceil 0 \rceil_{\mathbb{N}} = 0⌈0⌉N​=0, so the claim then asserts tmix(ε)≤0t_{\mathrm{mix}}(\varepsilon) \le 0tmix​(ε)≤0, i.e. tmix(ε)=0t_{\mathrm{mix}}(\varepsilon) = 0tmix​(ε)=0. Second, the hypotheses as stated do not force πmin⁡>0\pi_{\min} > 0πmin​>0; if πmin⁡=0\pi_{\min} = 0πmin​=0 then 1/(ε πmin⁡)=1/0=01/(\varepsilon\,\pi_{\min}) = 1/0 = 01/(επmin​)=1/0=0 and log⁡0=0\log 0 = 0log0=0 (both by convention), again collapsing the right-hand side to 000. When Φ⋆>0\Phi_\star > 0Φ⋆​>0 and πmin⁡>0\pi_{\min} > 0πmin​>0, the right-hand side is the ordinary ceiling of 2Φ⋆2 log⁡1ε πmin⁡\frac{2}{\Phi_\star^2}\,\log\frac{1}{\varepsilon\,\pi_{\min}}Φ⋆2​2​logεπmin​1​ (a positive quantity, since ε πmin⁡<1\varepsilon\,\pi_{\min} < 1επmin​<1).

Human review
  • Endorsed by Community (Bot) · Aug 22, 2026

  • Endorsed by Shuze Chen · Aug 22, 2026

    Confirmed by the mission captain (proposal self-audit).

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