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Proposition 8.14 -- the riffle shuffle needs log⁡2n\log_2 nlog2​n shuffles

Proved
MarkovMixing.riffle_mixing_lower

by Shuze Chen · Aug 21, 2026 · Mathlib c5ea003 (Lean v4.30.0)

markov-chainsmixing-timesprobability

The riffle shuffle (Gilbert–Shannon–Reeds) of a deck of nnn cards cuts the deck into two packets and interleaves them; formally it is the time reversal of the inverse riffle, in which each card independently receives a uniform bit and the cards labeled 000 move to the top preserving relative order. Its stationary distribution is uniform. For a tolerance ε\varepsilonε, the mixing time tmix(ε)t_{\mathrm{mix}}(\varepsilon)tmix​(ε) is the first ttt with max⁡x∥Pt(x,⋅)−unif∥TV≤ε\max_x\|P^t(x,\cdot)-\mathrm{unif}\|_{TV}\le\varepsilonmaxx​∥Pt(x,⋅)−unif∥TV​≤ε, where ∥μ−ν∥TV=max⁡A∣μ(A)−ν(A)∣\|\mu-\nu\|_{TV}=\max_A|\mu(A)-\nu(A)|∥μ−ν∥TV​=maxA​∣μ(A)−ν(A)∣.

The theorem (Proposition 8.14 of Levin–Peres–Wilmer) asserts: for any fixed tolerances 0<ε<10<\varepsilon<10<ε<1 and margin 0<δ<10<\delta<10<δ<1 there is an NNN such that for all n≥Nn\ge Nn≥N,

tmix(ε)  ≥  (1−δ) log⁡2n.t_{\mathrm{mix}}(\varepsilon)\;\ge\;(1-\delta)\,\log_2 n.tmix​(ε)≥(1−δ)log2​n.

So the upper bound 2log⁡2(4n/3)+12\log_2(4n/3)+12log2​(4n/3)+1 of the companion theorem is sharp up to the constant factor 222: no fixed number of riffle shuffles suffices for all deck sizes, and log⁡2n\log_2 nlog2​n is the true order. The obstruction is counting: ttt shuffles produce at most 2nt2^{nt}2nt equally likely bit-histories, too few to spread mass over n!n!n! orderings until t≳log⁡2nt\gtrsim\log_2 nt≳log2​n.

Preamble
import Definitions.Def_mm_shuffle
import Mathlib.Analysis.SpecialFunctions.Log.Base
Formal statement
namespace MarkovMixing

/-- **Proposition 8.14** (LPW): for the riffle shuffle on an `n`-card deck
and fixed `0 < ε, δ < 1`, for sufficiently large `n`,
`t_mix(ε) ≥ (1 − δ) log₂ n`. -/
theorem riffle_mixing_lower (ε δ : ℝ) (hε : 0 < ε) (hε1 : ε < 1)
    (hδ : 0 < δ) (hδ1 : δ < 1) :
    ∃ N : ℕ, ∀ n : ℕ, N ≤ n →
      (1 - δ) * Real.logb 2 n ≤
        (mixingTime (riffleShuffle n) (uniformDist (Equiv.Perm (Fin n))) ε : ℝ) := by
  sorry

end MarkovMixing
Source
D. A. Levin, Y. Peres, E. L. Wilmer, Markov Chains and Mixing Times, AMS 2009, https://documents.epfl.ch/groups/i/ip/ipg/www/2013-2014/Random_Walks/markovmixing.pdf, Section 8.3.3, Proposition 8.14, p. 110
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What the Lean code literally says, in plain math · claude-fable-5

For every pair of real numbers ε\varepsilonε and δ\deltaδ with 0<ε<10 < \varepsilon < 10<ε<1 and 0<δ<10 < \delta < 10<δ<1, there exists a natural number NNN such that for every natural number n≥Nn \ge Nn≥N,

(1−δ) log⁡2n  ≤  tmix(n)(ε),(1-\delta)\,\log_2 n \;\le\; t_{\mathrm{mix}}^{(n)}(\varepsilon),(1−δ)log2​n≤tmix(n)​(ε),

where the right-hand side is a natural number (cast to a real) defined as follows. The state space is the group SnS_nSn​ of permutations of {0,…,n−1}\{0,\dots,n-1\}{0,…,n−1}. The "riffle shuffle" transition matrix PnP_nPn​ is defined entrywise by

Pn(x,y)  =  12n #{ b:{0,…,n−1}→{0,1}  ∣  ∀q,  x(q)=y(σb(q)) },P_n(x,y) \;=\; \frac{1}{2^n}\,\#\Bigl\{\, b : \{0,\dots,n-1\} \to \{0,1\} \;\Bigm|\; \forall q,\; x(q) = y\bigl(\sigma_b(q)\bigr) \,\Bigr\},Pn​(x,y)=2n1​#{b:{0,…,n−1}→{0,1}​∀q,x(q)=y(σb​(q))},

where, for each bit-string bbb, σb\sigma_bσb​ is the (stable) sorting permutation of the tuple q↦b(y(q))q \mapsto b(y(q))q↦b(y(q)) — i.e. the permutation produced by the library's sorting operation, which rearranges positions so that the composed tuple is monotone (with 0<10 < 10<1), breaking ties by position. (The matrix is defined by this counting formula alone; the statement carries no hypothesis that PnP_nPn​ is stochastic, irreducible, or anything else.) The reference distribution is the constant function πn(g)=1/n!\pi_n(g) = 1/n!πn​(g)=1/n! on SnS_nSn​ (the uniform distribution). The total-variation-style distance between two functions μ,ν:Sn→R\mu,\nu : S_n \to \mathbb{R}μ,ν:Sn​→R used here is d(μ,ν)=sup⁡A⊆Sn∣∑g∈Aμ(g)−∑g∈Aν(g)∣d(\mu,\nu) = \sup_{A \subseteq S_n} \bigl|\sum_{g\in A}\mu(g) - \sum_{g\in A}\nu(g)\bigr|d(μ,ν)=supA⊆Sn​​​∑g∈A​μ(g)−∑g∈A​ν(g)​, the supremum over all finite subsets AAA of the absolute difference of the sums (note: no factor 12\tfrac1221​). The worst-case distance to πn\pi_nπn​ at time ttt is dn(t)=max⁡x∈Snd(Pnt(x,⋅), πn)d_n(t) = \max_{x \in S_n} d\bigl(P_n^t(x,\cdot),\, \pi_n\bigr)dn​(t)=maxx∈Sn​​d(Pnt​(x,⋅),πn​), where Pnt(x,⋅)P_n^t(x,\cdot)Pnt​(x,⋅) is row xxx of the ttt-th matrix power. Finally,

tmix(n)(ε)  =  inf⁡{ t∈N∣dn(t)≤ε },t_{\mathrm{mix}}^{(n)}(\varepsilon) \;=\; \inf\{\, t \in \mathbb{N} \mid d_n(t) \le \varepsilon \,\},tmix(n)​(ε)=inf{t∈N∣dn​(t)≤ε},

with the convention (from the infimum over natural numbers) that this equals 000 when no such ttt exists. Here log⁡2n\log_2 nlog2​n denotes the real base-2 logarithm of nnn (with the convention log⁡20=0\log_2 0 = 0log2​0=0, though the claim is only about all sufficiently large nnn: the threshold NNN may depend on ε\varepsilonε and δ\deltaδ, and may be chosen arbitrarily large). The asserted inequality is non-strict (≤\le≤), and the conclusion is a lower bound: (1−δ)log⁡2n(1-\delta)\log_2 n(1−δ)log2​n is at most the mixing quantity.

Human review
  • Endorsed by Community (Bot) · Aug 21, 2026

  • Endorsed by Shuze Chen · Aug 21, 2026

    Confirmed by the mission captain (proposal self-audit).

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