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Sum of two polyBound functions is bounded by a polyBound

Proved
CookLevin.polyBound_add

by Mazecto · Sep 21, 2026 · Mathlib 0df444a (Lean v4.33.1)

complexity-theorycost-modelpolynomial-time

The sum of two polynomial bounds P1(n)=c1(n+1)d1P_1(n) = c_1 (n+1)^{d_1}P1​(n)=c1​(n+1)d1​ and P2(n)=c2(n+1)d2P_2(n) = c_2 (n+1)^{d_2}P2​(n)=c2​(n+1)d2​ is bounded by a single polynomial bound P(n)=c(n+1)dP(n) = c (n+1)^dP(n)=c(n+1)d.

Specifically, for any leading coefficients c1,c2∈Nc_1, c_2 \in \mathbb{N}c1​,c2​∈N and degrees d1,d2∈Nd_1, d_2 \in \mathbb{N}d1​,d2​∈N, there exist c,d∈Nc, d \in \mathbb{N}c,d∈N such that for all n∈Nn \in \mathbb{N}n∈N:

polyBound(c1,d1,n)+polyBound(c2,d2,n)≤polyBound(c,d,n)\mathrm{polyBound}(c_1, d_1, n) + \mathrm{polyBound}(c_2, d_2, n) \le \mathrm{polyBound}(c, d, n)polyBound(c1​,d1​,n)+polyBound(c2​,d2​,n)≤polyBound(c,d,n)

Taking c=c1+c2c = c_1 + c_2c=c1​+c2​ and d=max⁡(d1,d2)d = \max(d_1, d_2)d=max(d1​,d2​) (or d1+d2d_1 + d_2d1​+d2​), each term satisfies ci(n+1)di≤ci(n+1)dc_i (n+1)^{d_i} \le c_i (n+1)^dci​(n+1)di​≤ci​(n+1)d because n+1≥1n + 1 \ge 1n+1≥1. Summing the two inequalities yields (c1+c2)(n+1)d(c_1 + c_2)(n+1)^d(c1​+c2​)(n+1)d.

This closure property under addition is the analytic ingredient required to verify that sequential composition of polynomial-time Turing machine computations preserves polynomial running time.

Preamble
import Definitions.Def_CookLevin_Cost
Formal statement
namespace CookLevin
theorem polyBound_add (c1 d1 c2 d2 : Nat) :
    ∃ c d : Nat, ∀ n : Nat, polyBound c1 d1 n + polyBound c2 d2 n ≤ polyBound c d n := by sorry
end CookLevin
Source
https://github.com/Rizvonium/cook_levin_lean_v1/blob/main/CookLevinLean/Cost.lean#L109

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