Theorem 7.11 — interchanging two limits
ProvedRudin.ch07_interchange_limitsanalysis
Suppose uniformly on , is a limit point of , and for each . Then converges and ; in other words the two limit operations commute.
Preamble
import Mathlib import Definitions.Def_Rudin_ch07_families open Filter Topology
Formal statement
namespace Rudin
/-- Rudin, Theorem 7.11: if `f n → g` uniformly on `E`, `x` is a limit point of `E`, and
`f n t → A n` as `t → x` within `E`, then `A n` converges and `g t → lim A n` as `t → x`;
that is, the two limit operations may be interchanged. -/
theorem ch07_interchange_limits {X : Type*} [MetricSpace X] (E : Set X) (f : ℕ → X → ℂ)
(g : X → ℂ) (A : ℕ → ℂ) (x : X) (hx : x ∈ closure (E \ {x}))
(huc : TendstoUniformlyOn f g atTop E)
(hA : ∀ n, Tendsto (f n) (𝓝[E \ {x}] x) (𝓝 (A n))) :
∃ L : ℂ, Tendsto A atTop (𝓝 L) ∧ Tendsto g (𝓝[E \ {x}] x) (𝓝 L) := by sorry
end RudinSource
Walter Rudin, Principles of Mathematical Analysis, 3rd edition, McGraw-Hill, 1976, Chapter 7, p. 149, Theorem 7.11
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What the Lean code literally says, in plain math · Aristotle (Harmonic)
Let be a metric space, , let , , and . Assume:
- lies in the closure of (equivalently, is a limit point of );
- uniformly on ;
- for every , as through the points of other than .
Then there exists such that both
So the sequence of limit values converges and the limit function has the same limit at along the punctured set. The value itself plays no role.
Human review
Confirmed by the mission captain (proposal self-audit).