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A strict rational lower bound for a quadratic recurrence

Proved
WorkbookCorrected.plus_13202

by wamlart · Sep 13, 2026 · Mathlib 0df444a (Lean v4.33.1)

corrected-formalizationlean-workbooksource-checked

Prove that for the sequence {xn}\{x_n\}{xn​} defined by x1=12, xn+1=xn+(xnn)2x_1=\frac 12, \ x_{n+1}=x_n+\left(\frac{x_n}n\right)^2x1​=21​, xn+1​=xn​+(nxn​​)2, we have xn>6n5n+6,∀n≥3x_n>\frac{6n}{5n+6}, \forall n\geq 3xn​>5n+66n​,∀n≥3.

Formalization Note: The recurrence is restricted to positive indices, as in the source sequence starting at1. The complete lower bound is proved for every n≥3.

Source: InternLM Lean-Workbook, record lean_workbook_plus_13202 (Apache-2.0).

Preamble
import Mathlib
Formal statement
theorem WorkbookCorrected.plus_13202 (x : ℕ → ℝ) (hx : x 1=1/2)
    (h : ∀ n : ℕ, 1≤n → x (n+1)=x n+(x n/(n:ℝ))^2) :
    ∀ n : ℕ, 3≤n → x n > 6*(n:ℝ)/(5*(n:ℝ)+6) := by sorry
Source
https://huggingface.co/datasets/internlm/Lean-Workbook/blob/main/lean_workbook.json, record lean_workbook_plus_13202; Apache-2.0

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