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§2, proof of the THEOREM, p. 2 — for x_{k+1} ∈ S*(x_k, δ) and f bounded below, |∇f(x_k)| → 0

Proved
ArmijoGrad.Conv.gradient_norm_tendsto_zero

by mikedeng1 · Oct 4, 2026 · Mathlib 0df444a (Lean v4.33.1)

gradient-methodp2o-batch-pfp2ap2o-gran-per-chapterp2o-plan-paperp2o-v1stationarity

Let f:En→Rf : E^n \to \mathbb{R}f:En→R be bounded below on EnE^nEn, let x0∈Enx_0 \in E^nx0​∈En and δ>0\delta > 0δ>0, and let {xk}k=0∞\{x_k\}_{k=0}^\infty{xk​}k=0∞​ be a sequence with first term x0x_0x0​ such that xk+1∈S∗(xk,δ)x_{k+1} \in S^*(x_k,\delta)xk+1​∈S∗(xk​,δ) for k=0,1,2,…k = 0, 1, 2, \dotsk=0,1,2,… Then

∣∇f(xk)∣→0(k→∞).|\nabla f(x_k)| \to 0 \qquad (k \to \infty).∣∇f(xk​)∣→0(k→∞).

This is the step of the proof that turns sufficient decrease into stationarity; Condition IV then turns stationarity into convergence of the iterates.

Formalization Note Continuity and Conditions III and IV are not needed and are omitted. ∇f\nabla f∇f is Mathlib's gradient, the same gradient used in the definition of S∗(x,δ)S^*(x,\delta)S∗(x,δ).

Preamble
import Mathlib
import Definitions.Def_ArmijoGrad_Conv_Setting

open Filter Topology
Formal statement
namespace ArmijoGrad.Conv

/-- §2, proof of the THEOREM, p. 2: if `f` is bounded below, `x₀` is the first term and
`x_{k+1} ∈ S*(x_k, δ)` for every `k`, then `|∇f(x_k)| → 0`. -/
theorem gradient_norm_tendsto_zero {n : ℕ} (f : EuclideanSpace ℝ (Fin n) → ℝ)
    (hbdd : BddBelow (Set.range f)) (x0 : EuclideanSpace ℝ (Fin n)) (δ : ℝ) (hδ : 0 < δ)
    (x : ℕ → EuclideanSpace ℝ (Fin n)) (hx0 : x 0 = x0)
    (hseq : ∀ k, x (k + 1) ∈ sdSet f (x k) δ) :
    Tendsto (fun k => ‖gradient f (x k)‖) atTop (𝓝 0) := by sorry

end ArmijoGrad.Conv
Source
Armijo, Minimization of functions having Lipschitz continuous first partial derivatives, Pacific J. Math. 16 (1966), p. 2, §2, proof of the THEOREM, second sentence
Human review
  • Endorsed by Shuze Chen · Oct 5, 2026

    Confirmed by the moderator at approval.

  • Endorsed by mikedeng1 · Oct 5, 2026

    Confirmed by the mission captain (proposal self-audit).

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