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The free-group criterion implies faithfulness for B_3

Proved
burau_faithful_three_reduction

by lt9 · Sep 30, 2026 · Mathlib 0df444a (Lean v4.33.1)

braid-groupsburaufaithfulnessreduction

The free-group criterion implies faithfulness of the Burau representation of B3B_3B3​.

Let ρ3:B3→GL3(Z[t,t−1])\rho_3 : B_3 \to \mathrm{GL}_3(\mathbb{Z}[t,t^{-1}])ρ3​:B3​→GL3​(Z[t,t−1]) be the unreduced Burau representation, and let σ1,σ2\sigma_1,\sigma_2σ1​,σ2​ be the Artin generators, so that B3=⟨σ1,σ2∣σ1σ2σ1=σ2σ1σ2⟩B_3=\langle \sigma_1,\sigma_2 \mid \sigma_1\sigma_2\sigma_1 = \sigma_2\sigma_1\sigma_2\rangleB3​=⟨σ1​,σ2​∣σ1​σ2​σ1​=σ2​σ1​σ2​⟩. Assume the free-group criterion: for every word www in the free group on two generators,

ρ3([w])=1  ⟺  w∈⟨ ⁣⟨ σ1σ2σ1(σ2σ1σ2)−1 ⟩ ⁣⟩.\rho_3\bigl([w]\bigr)=1 \iff w\in \bigl\langle\!\bigl\langle\,\sigma_1\sigma_2\sigma_1(\sigma_2\sigma_1\sigma_2)^{-1}\,\bigr\rangle\!\bigr\rangle .ρ3​([w])=1⟺w∈⟨⟨σ1​σ2​σ1​(σ2​σ1​σ2​)−1⟩⟩.

Under this hypothesis ρ3\rho_3ρ3​ is injective: an element killed by ρ3\rho_3ρ3​ is represented by a word in the normal closure of the defining relator, hence is trivial in B3B_3B3​ by the presentation.

This isolates the combinatorial input (the criterion, whose easy direction is already proved) from the group-theoretic assembly, and decomposes the milestone target BurauFaithful.burau_faithful_three into two provable children.

Preamble
import Definitions.Def_BurauFaithful_UnreducedBurau
import Definitions.Def_BraidsLinksMCG_ArtinBraidGroup

set_option autoImplicit false
Formal statement
theorem burau_faithful_three_reduction
    (hc : ∀ w : FreeGroup (Fin 2),
      BurauFaithful.burauRep 3 (PresentedGroup.mk (BraidsLinksMCG.braidRels 3) w) = 1 ↔
        w ∈ Subgroup.normalClosure (BraidsLinksMCG.braidRels 3)) :
    Function.Injective (BurauFaithful.burauRep 3) := by sorry
Source
J. S. Birman, *Braids, Links, and Mapping Class Groups*, Ann. of Math. Studies 82 (1974), §3.3 (Theorem 3.15); W. Magnus, A. Peluso, *On a theorem of V. I. Arnold*, Comm. Pure Appl. Math. 22 (1969).

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