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Lemma 9.6 -- the Green's function and effective resistance

Proved
MarkovMixing.green_resistance

by Shuze Chen · Aug 21, 2026 · Mathlib c5ea003 (Lean v4.30.0)

markov-chainsmixing-timesprobability

Let ccc be a network on a finite vertex set: a symmetric nonnegative conductance function with total conductance c(x)=∑yc(x,y)>0c(x)=\sum_yc(x,y)>0c(x)=∑y​c(x,y)>0 at every vertex, carrying the walk P(x,y)=c(x,y)/c(x)P(x,y)=c(x,y)/c(x)P(x,y)=c(x,y)/c(x), assumed irreducible. Fix distinct vertices a≠za\ne za=z. The Green's function of the walk stopped at zzz is the expected number of visits to a vertex before first hitting zzz:

Gτz(a,x)=Ea[#{t<τz:Xt=x}],G_{\tau_z}(a,x)=\mathbb E_a\bigl[\#\{t<\tau_z: X_t=x\}\bigr],Gτz​​(a,x)=Ea​[#{t<τz​:Xt​=x}],

the walk starting at aaa and τz\tau_zτz​ being the hitting time of zzz. The effective resistance R(a↔z)R(a\leftrightarrow z)R(a↔z) is defined through the voltage: with W(x)=Px{τa<τz}W(x)=\mathbb P_x\{\tau_a<\tau_z\}W(x)=Px​{τa​<τz​} (the harmonic function with boundary values W(a)=1W(a)=1W(a)=1, W(z)=0W(z)=0W(z)=0), the current flowing out of aaa is ∥I∥=∑yc(a,y)[W(a)−W(y)]\|I\|=\sum_yc(a,y)\bigl[W(a)-W(y)\bigr]∥I∥=∑y​c(a,y)[W(a)−W(y)], and R(a↔z)=∥I∥−1R(a\leftrightarrow z)=\|I\|^{-1}R(a↔z)=∥I∥−1.

The theorem (Lemma 9.6 of Levin–Peres–Wilmer) asserts:

Gτz(a,a)  =  c(a) R(a↔z).G_{\tau_z}(a,a)\;=\;c(a)\,R(a\leftrightarrow z).Gτz​​(a,a)=c(a)R(a↔z).

The expected number of returns to the starting point before reaching zzz is exactly the vertex conductance times the effective resistance — the identity through which escape probabilities and resistances translate into each other.

Preamble
import Definitions.Def_mm_network
Formal statement
namespace MarkovMixing

/-- **Lemma 9.6** (LPW): the Green's function of the network walk stopped at
`τ_z` satisfies `G_{τ_z}(a,a) = c(a) R(a ↔ z)`. -/
theorem green_resistance {V : Type*} [Fintype V] [DecidableEq V]
    (c : V → V → ℝ) (hc : IsConductance c)
    (hpos : ∀ x : V, 0 < vertexConductance c x)
    (hirr : Irreducible (networkWalk c)) (a z : V) (haz : a ≠ z) :
    greenFn (networkWalk c) a z a =
      vertexConductance c a * effectiveResistance c a z := by
  sorry

end MarkovMixing
Source
D. A. Levin, Y. Peres, E. L. Wilmer, Markov Chains and Mixing Times, AMS 2009, https://documents.epfl.ch/groups/i/ip/ipg/www/2013-2014/Random_Walks/markovmixing.pdf, Section 9.4, Lemma 9.6, Eq. (9.18), p. 120
Read-back

What the Lean code literally says, in plain math · claude-fable-5

Read-back: green_resistance

Let VVV be a finite type with decidable equality, and let c:V×V→Rc : V \times V \to \mathbb{R}c:V×V→R satisfy the bundle's conductance predicate — c(x,y)≥0c(x,y) \ge 0c(x,y)≥0 and c(x,y)=c(y,x)c(x,y) = c(y,x)c(x,y)=c(y,x) for all x,y∈Vx, y \in Vx,y∈V (self-loops allowed) — together with the hypothesis that every vertex conductance is strictly positive: c(x):=∑y∈Vc(x,y)>0c(x) := \sum_{y \in V} c(x,y) > 0c(x):=∑y∈V​c(x,y)>0 for all xxx. Let PcP_cPc​ be the associated walk matrix, Pc(x,y)=c(x,y)/c(x)P_c(x,y) = c(x,y)/c(x)Pc​(x,y)=c(x,y)/c(x) (all denominators positive here), and assume PcP_cPc​ is irreducible in the bundle's sense: for all x,y∈Vx, y \in Vx,y∈V there exists t∈Nt \in \mathbb{N}t∈N (including possibly t=0t = 0t=0, where Pc0P_c^0Pc0​ is the identity) with (Pct)(x,y)>0(P_c^t)(x,y) > 0(Pct​)(x,y)>0. Fix two vertices a,z∈Va, z \in Va,z∈V with a≠za \ne za=z (so VVV has at least two elements). The theorem asserts the single real-number identity

Gz(a,a)=c(a)⋅R(a,z),G_z(a, a) = c(a) \cdot \mathcal{R}(a, z),Gz​(a,a)=c(a)⋅R(a,z),

where the two sides unfold as follows.

The left side Gz(a,a)G_z(a,a)Gz​(a,a) is the bundle's greenFn of PcP_cPc​ at (a,z,a)(a, z, a)(a,z,a): Lean's tsum over t∈Nt \in \mathbb{N}t∈N — the limit if the series is summable, and 000 by convention if not — of the quantity

∑ω:{0,…,t}→V1[ω0=a, ωi≠z for all 0≤i≤t, ωt=a]∏i=0t−1Pc(ωi,ωi+1),\sum_{\omega : \{0,\dots,t\} \to V} \mathbf{1}\big[\omega_0 = a,\ \omega_i \ne z \text{ for all } 0 \le i \le t,\ \omega_t = a\big] \prod_{i=0}^{t-1} P_c(\omega_i, \omega_{i+1}),ω:{0,…,t}→V∑​1[ω0​=a, ωi​=z for all 0≤i≤t, ωt​=a]i=0∏t−1​Pc​(ωi​,ωi+1​),

i.e. the total PcP_cPc​-weight of length-ttt walks that start at aaa, end at aaa, and never visit zzz at any time (the t=0t = 0t=0 term equals 111 since a≠za \ne za=z). Informally this is the expected number of visits to aaa (counting time 000) strictly before the walk from aaa first hits zzz, but the formal object is exactly the tsum just described.

The right side is the product of c(a)=∑yc(a,y)c(a) = \sum_{y} c(a,y)c(a)=∑y​c(a,y) with the bundle's effectiveResistance, which is the real inverse (I(a,z))−1\big(I(a,z)\big)^{-1}(I(a,z))−1 — equal to 000, not +∞+\infty+∞, if I(a,z)=0I(a,z) = 0I(a,z)=0 — of the "current strength"

I(a,z)=∑y∈Vc(a,y) (v(a)−v(y)).I(a,z) = \sum_{y \in V} c(a,y)\,\big(v(a) - v(y)\big).I(a,z)=y∈V∑​c(a,y)(v(a)−v(y)).

Here v(x)v(x)v(x) is the bundle's voltage: the tsum over t∈Nt \in \mathbb{N}t∈N (again 000 if not summable) of the total PcP_cPc​-weight of paths ω:{0,…,t}→V\omega : \{0,\dots,t\} \to Vω:{0,…,t}→V with ω0=x\omega_0 = xω0​=x, ωt=a\omega_t = aωt​=a, ωi≠a\omega_i \ne aωi​=a for all i<ti < ti<t, and ωi≠z\omega_i \ne zωi​=z for all 0≤i≤t0 \le i \le t0≤i≤t — that is, walks from xxx that hit aaa for the first time at their final step while never visiting zzz. In particular v(a)=1v(a) = 1v(a)=1 (only the length-000 path contributes, since a≠za \ne za=z) and v(z)=0v(z) = 0v(z)=0.

The claim is exactly this equality of two real numbers, for every ccc, aaa, zzz satisfying the stated hypotheses; no claim of positivity, finiteness beyond the tsum conventions, or any inequality is made.

Human review
  • Endorsed by Community (Bot) · Aug 21, 2026

  • Endorsed by Shuze Chen · Aug 21, 2026

    Confirmed by the mission captain (proposal self-audit).

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