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Theorems 8.11-8.12 — best mean-square approximation and Bessel's inequality

Disproved
Rudin.ch08_bessel

by Lucas · Sep 13, 2026 · Mathlib 0df444a (Lean v4.33.1)

analysisfourier-analysis

Let {φn}\{\varphi_n\}{φn​} be orthonormal on [a,b][a,b][a,b] and let cmc_mcm​ be the Fourier coefficients of fff. Among all combinations ∑m<nγmφm\sum_{m<n} \gamma_m \varphi_m∑m<n​γm​φm​, the choice γm=cm\gamma_m = c_mγm​=cm​ minimizes ∫ab∣f−∑γmφm∣2\int_a^b |f - \sum \gamma_m\varphi_m|^2∫ab​∣f−∑γm​φm​∣2; and ∑m<n∣cm∣2≤∫ab∣f∣2\sum_{m<n} |c_m|^2 \le \int_a^b |f|^2∑m<n​∣cm​∣2≤∫ab​∣f∣2 for every nnn (Bessel's inequality).

Preamble
import Mathlib
import Definitions.Def_Rudin_ch08_fourier

open Filter Topology
Formal statement
namespace Rudin

/-- Rudin, Theorems 8.11 and 8.12: among all linear combinations of `φ 0, …, φ (n-1)` the
partial sum of the Fourier series of `f` is the best approximation in the mean square sense, and
Bessel's inequality `∑ |cₘ|² ≤ ∫ |f|²` holds. -/
theorem ch08_bessel (a b : ℝ) (hab : a ≤ b) (φ : ℕ → ℝ → ℂ) (hφ : IsOrthonormalSystem φ a b)
    (f : ℝ → ℂ) (n : ℕ) (γ : ℕ → ℂ) :
    (∫ x in a..b, ‖f x - ∑ m ∈ Finset.range n, genFourierCoeff f φ a b m * φ m x‖ ^ 2) ≤
      (∫ x in a..b, ‖f x - ∑ m ∈ Finset.range n, γ m * φ m x‖ ^ 2) ∧
    (∑ m ∈ Finset.range n, ‖genFourierCoeff f φ a b m‖ ^ 2) ≤ ∫ x in a..b, ‖f x‖ ^ 2 := by sorry

end Rudin
Source
Walter Rudin, Principles of Mathematical Analysis, 3rd edition, McGraw-Hill, 1976, Chapter 8, pp. 187-188, Theorems 8.11 and 8.12
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What the Lean code literally says, in plain math · Aristotle (Harmonic)

Let a≤ba \le ba≤b be reals, let φ0,φ1,⋯:R→C\varphi_0,\varphi_1,\dots : \mathbb{R}\to\mathbb{C}φ0​,φ1​,⋯:R→C be an orthonormal system on [a,b][a,b][a,b] — i.e. ∫abφnφm‾=0\int_a^b \varphi_n \overline{\varphi_m} = 0∫ab​φn​φm​​=0 for m≠nm \ne nm=n and ∫ab∥φn∥2=1\int_a^b \lVert\varphi_n\rVert^2 = 1∫ab​∥φn​∥2=1 — let f:R→Cf : \mathbb{R}\to\mathbb{C}f:R→C be any function, let n∈Nn \in \mathbb{N}n∈N and let γ:N→C\gamma : \mathbb{N}\to\mathbb{C}γ:N→C be arbitrary complex numbers. Write cm=∫abfφm‾c_m = \int_a^b f \overline{\varphi_m}cm​=∫ab​fφm​​ for the Fourier coefficients of fff relative to φ\varphiφ. Then both:

  1. Least squares optimality.
∫ab∥f(x)−∑m=0n−1cmφm(x)∥2dx  ≤  ∫ab∥f(x)−∑m=0n−1γmφm(x)∥2dx;\int_a^b \Bigl\lVert f(x) - \sum_{m=0}^{n-1} c_m \varphi_m(x) \Bigr\rVert^2 dx \;\le\; \int_a^b \Bigl\lVert f(x) - \sum_{m=0}^{n-1} \gamma_m \varphi_m(x) \Bigr\rVert^2 dx ;∫ab​​f(x)−m=0∑n−1​cm​φm​(x)​2dx≤∫ab​​f(x)−m=0∑n−1​γm​φm​(x)​2dx;
  1. Bessel's inequality.
∑m=0n−1∥cm∥2  ≤  ∫ab∥f(x)∥2dx.\sum_{m=0}^{n-1} \lVert c_m \rVert^2 \;\le\; \int_a^b \lVert f(x)\rVert^2 dx .m=0∑n−1​∥cm​∥2≤∫ab​∥f(x)∥2dx.

Both sums run over m=0,…,n−1m = 0,\dots,n-1m=0,…,n−1 and both statements are asserted for every nnn, including n=0n = 0n=0 where the sums are empty. No integrability hypothesis is placed on fff; all integrals are oriented interval integrals against Lebesgue measure, which evaluate to 000 for non-integrable integrands.

Human review
  • Endorsed by Shuze Chen · Sep 13, 2026

  • Endorsed by Lucas · Sep 13, 2026

    Confirmed by the mission captain (proposal self-audit).

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