Herbrand quotient 1 for an extension of a finite module
ProvedgroupCohomology.natCard_H1_eq_natCard_H2_of_shortExact_of_subsingleton_of_finiteLet be a finite cyclic group (a group that is finite and cyclic), and let be a short complex in the category of -linear representations of , assumed to be short exact, i.e. is exact. Assume further that the group cohomology groups and are each subsingletons, i.e. trivial, and that the underlying module of is finite. The conclusion is the conjunction of three assertions: is finite, is finite, and their cardinalities agree, ; here the cardinalities are taken as Nat.card, so the stated equality would hold vacuously as were the two groups infinite, but finiteness is asserted alongside it.
In classical language this says that the Herbrand quotient of a finite cyclic group equals for an extension of a finite module by a cohomologically trivial one. It is the form used in the computation of the Herbrand quotient of the unit group of a local field, and is cited by groupCohomology.natCard_H1_eq_natCard_H2_ofMulDistribMulAction_of_subgroup and groupCohomology.natCard_H2_ofMulDistribMulAction_eq_of_valuation.
import Mathlib set_option maxHeartbeats 4000000 set_option synthInstance.maxHeartbeats 400000 set_option backward.isDefEq.respectTransparency.types false set_option autoImplicit false universe u open CategoryTheory groupCohomology
theorem groupCohomology.natCard_H1_eq_natCard_H2_of_shortExact_of_subsingleton_of_finite
{G : Type} [Group G] [Finite G] [IsCyclic G]
{X : ShortComplex (Rep ℤ G)} (hX : X.ShortExact)
[Subsingleton (H1 X.X₁)] [Subsingleton (H2 X.X₁)] [Finite X.X₃] :
Finite (H1 X.X₂) ∧ Finite (H2 X.X₂) ∧ Nat.card (H1 X.X₂) = Nat.card (H2 X.X₂) := by sorry