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Section 3.2.2 -- the Metropolis-Hastings chain for a general base chain

Proved
MarkovMixing.metropolized_stationary

by Shuze Chen · Aug 21, 2026 · Mathlib c5ea003 (Lean v4.30.0)

markov-chainsmixing-timesprobability

Let Ψ\PsiΨ be an arbitrary stochastic matrix on a finite state space VVV (a base chain, not assumed symmetric), and let π\piπ be a strictly positive probability distribution on VVV. The Metropolis–Hastings chain built from this pair proposes a move from xxx to yyy with probability Ψ(x,y)\Psi(x,y)Ψ(x,y) and accepts it with probability

min⁡ ⁣(1,  π(y) Ψ(y,x)π(x) Ψ(x,y)),\min\!\Bigl(1,\;\frac{\pi(y)\,\Psi(y,x)}{\pi(x)\,\Psi(x,y)}\Bigr),min(1,π(x)Ψ(x,y)π(y)Ψ(y,x)​),

staying at xxx on rejection; the acceptance ratio weighs the proposal probabilities of the two directions against the target masses.

The theorem asserts that this chain is a genuine Markov chain (nonnegative entries, rows summing to one), that it satisfies the detailed balance equations π(x) M(x,y)=π(y) M(y,x)\pi(x)\,M(x,y)=\pi(y)\,M(y,x)π(x)M(x,y)=π(y)M(y,x) — reversibility with respect to π\piπ — and that π\piπ is a stationary distribution for it: ∑xπ(x) M(x,y)=π(y)\sum_x\pi(x)\,M(x,y)=\pi(y)∑x​π(x)M(x,y)=π(y) for every yyy. This is Exercise 3.1 of Levin–Peres–Wilmer, the general (non-symmetric) form of the Metropolis construction of §3.2.2.

Preamble
import Definitions.Def_mm_mcmc
Formal statement
namespace MarkovMixing

/-- **§3.2.2, Exercise 3.1** (LPW): the Metropolized chain built from a
general stochastic base chain `Ψ` and a positive target distribution `π` is a
Markov chain, reversible with respect to `π`, with stationary distribution
`π`. -/
theorem metropolized_stationary {V : Type*} [Fintype V] [DecidableEq V]
    (Ψ : Matrix V V ℝ) (hΨ : IsStochastic Ψ)
    (π : V → ℝ) (hπ : IsDist π) (hpos : ∀ x : V, 0 < π x) :
    IsStochastic (metropolized Ψ π) ∧
    DetailedBalance (metropolized Ψ π) π ∧
    IsStationary (metropolized Ψ π) π := by
  sorry

end MarkovMixing
Source
D. A. Levin, Y. Peres, E. L. Wilmer, Markov Chains and Mixing Times, AMS 2009, https://documents.epfl.ch/groups/i/ip/ipg/www/2013-2014/Random_Walks/markovmixing.pdf, Section 3.2.2, Eq. (3.5) and Exercise 3.1, p. 40
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What the Lean code literally says, in plain math · claude-fable-5

Let VVV be an arbitrary finite type (with decidable equality); VVV may be empty. Let Ψ\PsiΨ be a V×VV \times VV×V real matrix which is stochastic: every entry satisfies Ψ(x,y)≥0\Psi(x,y) \ge 0Ψ(x,y)≥0 and every row sums to one, ∑yΨ(x,y)=1\sum_y \Psi(x,y) = 1∑y​Ψ(x,y)=1. No symmetry or irreducibility is assumed of Ψ\PsiΨ. Let π:V→R\pi : V \to \mathbb{R}π:V→R be a distribution (π(x)≥0\pi(x) \ge 0π(x)≥0 for all xxx and ∑xπ(x)=1\sum_x \pi(x) = 1∑x​π(x)=1) which is moreover strictly positive: π(x)>0\pi(x) > 0π(x)>0 for every x∈Vx \in Vx∈V. Define the Metropolis–Hastings ("metropolized") matrix M=metropolized(Ψ,π)M = \mathrm{metropolized}(\Psi, \pi)M=metropolized(Ψ,π) entrywise by

M(x,y)={Ψ(x,y) min⁡ ⁣(1,π(y) Ψ(y,x)π(x) Ψ(x,y))if y≠x,1−∑z≠xΨ(x,z) min⁡ ⁣(1,π(z) Ψ(z,x)π(x) Ψ(x,z))if y=x,M(x,y) = \begin{cases} \Psi(x,y)\,\min\!\left(1, \dfrac{\pi(y)\,\Psi(y,x)}{\pi(x)\,\Psi(x,y)}\right) & \text{if } y \neq x,\\[2mm] 1 - \displaystyle\sum_{z \neq x} \Psi(x,z)\,\min\!\left(1, \dfrac{\pi(z)\,\Psi(z,x)}{\pi(x)\,\Psi(x,z)}\right) & \text{if } y = x, \end{cases}M(x,y)=⎩⎨⎧​Ψ(x,y)min(1,π(x)Ψ(x,y)π(y)Ψ(y,x)​)1−z=x∑​Ψ(x,z)min(1,π(x)Ψ(x,z)π(z)Ψ(z,x)​)​if y=x,if y=x,​

where the diagonal sum runs over all z∈Vz \in Vz∈V with z≠xz \neq xz=x. Division here is the total real division that returns 000 when the denominator is 000: in particular, if Ψ(x,y)=0\Psi(x,y) = 0Ψ(x,y)=0 (with y≠xy \neq xy=x), the acceptance ratio is min⁡(1,0)=0\min(1, 0) = 0min(1,0)=0 by this convention, and the corresponding entry is 0⋅0=00 \cdot 0 = 00⋅0=0. The theorem asserts the conjunction of three claims about MMM:

  1. MMM is stochastic: M(x,y)≥0M(x,y) \ge 0M(x,y)≥0 for all x,y∈Vx, y \in Vx,y∈V, and ∑yM(x,y)=1\sum_y M(x,y) = 1∑y​M(x,y)=1 for every x∈Vx \in Vx∈V;
  2. MMM satisfies detailed balance with respect to π\piπ: for all x,y∈Vx, y \in Vx,y∈V, π(x) M(x,y)=π(y) M(y,x)\pi(x)\, M(x,y) = \pi(y)\, M(y,x)π(x)M(x,y)=π(y)M(y,x);
  3. π\piπ is stationary for MMM, a predicate bundling two parts: π\piπ is a distribution (nonnegative and summing to 111, restating a hypothesis already assumed), and the row vector π\piπ is fixed by right-multiplication by MMM, i.e. ∑xπ(x) M(x,y)=π(y)\sum_x \pi(x)\, M(x,y) = \pi(y)∑x​π(x)M(x,y)=π(y) for every y∈Vy \in Vy∈V.

If VVV is empty, the hypotheses that the rows of Ψ\PsiΨ sum to 111 and that ∑xπ(x)=1\sum_x \pi(x) = 1∑x​π(x)=1 cannot hold (empty sums are 000), so the statement is vacuously true in that case.

Human review
  • Endorsed by Community (Bot) · Aug 21, 2026

  • Endorsed by Shuze Chen · Aug 21, 2026

    Confirmed by the mission captain (proposal self-audit).

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