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Proposition 10.6 -- the commute time identity

Proved
MarkovMixing.commute_time_identity

by Shuze Chen · Aug 21, 2026 · Mathlib c5ea003 (Lean v4.30.0)

markov-chainsmixing-timesprobability

Let ccc be a network on a finite vertex set VVV: a symmetric nonnegative conductance function with total vertex conductance c(x)=∑yc(x,y)>0c(x)=\sum_yc(x,y)>0c(x)=∑y​c(x,y)>0 everywhere, carrying the irreducible walk P(x,y)=c(x,y)/c(x)P(x,y)=c(x,y)/c(x)P(x,y)=c(x,y)/c(x). Write cG=∑xc(x)c_G=\sum_xc(x)cG​=∑x​c(x) for the total conductance of the network, Ea(τb)\mathbb E_a(\tau_b)Ea​(τb​) for the expected number of steps for the walk started at aaa to first reach bbb, and R(a↔b)R(a\leftrightarrow b)R(a↔b) for the effective resistance, defined through the voltage W(x)=Px{τa<τb}W(x)=\mathbb P_x\{\tau_a<\tau_b\}W(x)=Px​{τa​<τb​} and current ∥I∥=∑yc(a,y)[W(a)−W(y)]\|I\|=\sum_yc(a,y)[W(a)-W(y)]∥I∥=∑y​c(a,y)[W(a)−W(y)] as R(a↔b)=∥I∥−1R(a\leftrightarrow b)=\|I\|^{-1}R(a↔b)=∥I∥−1.

The theorem (the Commute Time Identity, Proposition 10.6 of Levin–Peres–Wilmer, the capstone of Chapters 9–11) asserts: for any two distinct vertices a≠ba\ne ba=b,

Ea(τb)+Eb(τa)  =  cG  R(a↔b).\mathbb E_a(\tau_b)+\mathbb E_b(\tau_a)\;=\;c_G\;R(a\leftrightarrow b).Ea​(τb​)+Eb​(τa​)=cG​R(a↔b).

The expected round-trip time between two vertices is exactly the total conductance times the effective resistance between them. This single identity converts the entire electrical toolkit — series/parallel reduction, Thomson's principle, Rayleigh monotonicity — into exact computations and bounds for hitting and cover times of reversible chains.

Preamble
import Definitions.Def_mm_network
Formal statement
namespace MarkovMixing

/-- **Proposition 10.6, the Commute Time Identity** (LPW), the capstone of
Chapters 9–11: for the random walk on a network,
`E_a(τ_b) + E_b(τ_a) = c_G · R(a ↔ b)`. -/
theorem commute_time_identity {V : Type*} [Fintype V] [DecidableEq V]
    (c : V → V → ℝ) (hc : IsConductance c)
    (hpos : ∀ x : V, 0 < vertexConductance c x)
    (hirr : Irreducible (networkWalk c)) (a b : V) (hab : a ≠ b) :
    expSetHitTime (networkWalk c) a {b} + expSetHitTime (networkWalk c) b {a} =
      totalConductance c * effectiveResistance c a b := by
  sorry

end MarkovMixing
Source
D. A. Levin, Y. Peres, E. L. Wilmer, Markov Chains and Mixing Times, AMS 2009, https://documents.epfl.ch/groups/i/ip/ipg/www/2013-2014/Random_Walks/markovmixing.pdf, Section 10.3, Proposition 10.6, Eq. (10.8), p. 130
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What the Lean code literally says, in plain math · claude-fable-5

Let VVV be a finite type with decidable equality, and let c:V×V→Rc : V \times V \to \mathbb{R}c:V×V→R be a function satisfying c(x,y)≥0c(x,y) \ge 0c(x,y)≥0 and c(x,y)=c(y,x)c(x,y) = c(y,x)c(x,y)=c(y,x) for all x,yx, yx,y (a "conductance"; self-loop values c(x,x)c(x,x)c(x,x) are permitted). Write c(x)=∑y∈Vc(x,y)c(x) = \sum_{y \in V} c(x,y)c(x)=∑y∈V​c(x,y) for the vertex conductance and ctot=∑x∈Vc(x)=∑x,yc(x,y)c_{\mathrm{tot}} = \sum_{x \in V} c(x) = \sum_{x,y} c(x,y)ctot​=∑x∈V​c(x)=∑x,y​c(x,y) for the total conductance (each unordered edge counted twice), and assume c(x)>0c(x) > 0c(x)>0 for every xxx. Let PPP be the transition matrix P(x,y)=c(x,y)/c(x)P(x,y) = c(x,y)/c(x)P(x,y)=c(x,y)/c(x), and assume it is irreducible in the sense that for every pair x,y∈Vx, y \in Vx,y∈V there exists a natural number t≥0t \ge 0t≥0 with (Pt)(x,y)>0(P^t)(x,y) > 0(Pt)(x,y)>0 (automatic for x=yx = yx=y via t=0t = 0t=0). Fix vertices a≠ba \ne ba=b. For x,y∈Vx, y \in Vx,y∈V, let Ex[τy]E_x[\tau_y]Ex​[τy​] denote ∑t=0∞Pr⁡x[τy>t]\sum_{t=0}^{\infty} \Pr_x[\tau_y > t]∑t=0∞​Prx​[τy​>t], where Pr⁡x[τy>t]\Pr_x[\tau_y > t]Prx​[τy​>t] is the total weight ∑ω∏i=0t−1P(ωi,ωi+1)\sum_{\omega} \prod_{i=0}^{t-1} P(\omega_i,\omega_{i+1})∑ω​∏i=0t−1​P(ωi​,ωi+1​) of paths ω:{0,…,t}→V\omega : \{0,\dots,t\} \to Vω:{0,…,t}→V with ω0=x\omega_0 = xω0​=x that avoid yyy at every step 0≤i≤t0 \le i \le t0≤i≤t including step 000; this is the expected first hitting time of yyy for the chain started at xxx, with the hitting time counting time 000 (so Ey[τy]=0E_y[\tau_y] = 0Ey​[τy​]=0), and the infinite sum is a Lean tsum, taking the junk value 000 if the series fails to converge. The effective resistance R(a,b)\mathcal{R}(a,b)R(a,b) is defined via voltages: v(x)v(x)v(x) is the probability that the chain started at xxx reaches aaa strictly before bbb — the total weight of paths from xxx ending at aaa, not visiting aaa before their final step and never visiting bbb (so v(a)=1v(a) = 1v(a)=1, v(b)=0v(b) = 0v(b)=0) — the current strength is I=∑y∈Vc(a,y) (v(a)−v(y))I = \sum_{y \in V} c(a,y)\,(v(a) - v(y))I=∑y∈V​c(a,y)(v(a)−v(y)), and R(a,b)=I−1\mathcal{R}(a,b) = I^{-1}R(a,b)=I−1, with the convention that the reciprocal of 000 is the junk value 000. The theorem asserts the exact identity

Ea[τb]+Eb[τa]  =  ctot⋅R(a,b),E_a[\tau_b] + E_b[\tau_a] \;=\; c_{\mathrm{tot}} \cdot \mathcal{R}(a,b),Ea​[τb​]+Eb​[τa​]=ctot​⋅R(a,b),

i.e. the sum of the expected hitting time of bbb from aaa and the expected hitting time of aaa from bbb (the commute time between aaa and bbb) equals the total conductance of the network times the effective resistance between aaa and bbb.

Human review
  • Endorsed by Community (Bot) · Aug 21, 2026

  • Endorsed by Shuze Chen · Aug 21, 2026

    Confirmed by the mission captain (proposal self-audit).

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