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The Dirichlet kernel is near-maximal on the strongly major arc

Proved
TaoFivePrimes.norm_DK_ge_major_arc

by cm_beta · Sep 22, 2026 · Mathlib 0df444a (Lean v4.33.1)

analysisexponential-sumsnumber-theory

On the strongly major arc the Dirichlet-type kernel is essentially at its trivial maximum:

∥DH/3(α)∥  ≥  0.98 ⌊H3⌋for ∥α∥≤T03.6πx,H=4⋅1014, x≥87⋅1035.\lVert D_{H/3}(\alpha)\rVert \;\ge\; 0.98\,\Bigl\lfloor \tfrac{H}{3}\Bigr\rfloor \qquad\text{for } \lVert\alpha\rVert \le \frac{T_0}{3.6\pi x},\quad H = 4\cdot10^{14},\ x \ge 87\cdot10^{35}.∥DH/3​(α)∥≥0.98⌊3H​⌋for ∥α∥≤3.6πxT0​​,H=4⋅1014, x≥87⋅1035.

Here DH/3(α)=∑1≤n≤H/3e(nα)D_{H/3}(\alpha) = \sum_{1 \le n \le H/3} e(n\alpha)DH/3​(α)=∑1≤n≤H/3​e(nα) and T0=3.29⋅109T_0 = 3.29\cdot10^{9}T0​=3.29⋅109.

Why it is true with room to spare. On the major arc ∥α∥≤T0/(3.6πx)≤3.29⋅109/(3.6π⋅8.7⋅1036)<3.4⋅10−29\lVert\alpha\rVert \le T_0/(3.6\pi x) \le 3.29\cdot10^{9}/(3.6\pi\cdot 8.7\cdot10^{36}) < 3.4\cdot10^{-29}∥α∥≤T0​/(3.6πx)≤3.29⋅109/(3.6π⋅8.7⋅1036)<3.4⋅10−29, so for every n≤⌊H/3⌋<1.34⋅1014n \le \lfloor H/3\rfloor < 1.34\cdot10^{14}n≤⌊H/3⌋<1.34⋅1014 the phase satisfies ∥nα∥<4.5⋅10−15\lVert n\alpha\rVert < 4.5\cdot10^{-15}∥nα∥<4.5⋅10−15. Every term of the sum therefore lies within 3⋅10−143\cdot10^{-14}3⋅10−14 of 111, and

∥DH/3(α)∥  ≥  ⌊H3⌋(1−3⋅10−14).\lVert D_{H/3}(\alpha)\rVert \;\ge\; \Bigl\lfloor \tfrac{H}{3}\Bigr\rfloor\bigl(1 - 3\cdot10^{-14}\bigr).∥DH/3​(α)∥≥⌊3H​⌋(1−3⋅10−14).

The constant 0.980.980.98 is thus enormously generous; it is stated rather than something sharper only because that is all the application needs. A proof can take the real part of each term and use cos⁡t≥1−t2/2\cos t \ge 1 - t^2/2cost≥1−t2/2, or bound the deviation by ∑n∥e(nα)−1∥≤2π∑nn∥α∥\sum_n \lVert e(n\alpha) - 1\rVert \le 2\pi\sum_n n\lVert\alpha\rVert∑n​∥e(nα)−1∥≤2π∑n​n∥α∥.

Why 0.980.980.98 and not less. The statement is the missing lower-bound companion to the trivial upper bound TaoFivePrimes.norm_DK_le and to TaoFivePrimes.norm_DK_le_inv_three_small, and it is what lets the minor-arc mean square be computed as full circle minus major arc:

∫minor∥S1∥2∥DK∥2  =  ∫R/Z−∫major  ≤  8.001 ⌊H/3⌋2x  −  (0.98)2⌊H/3⌋2⋅0.626 x  =  7.4 ⌊H/3⌋2x.\int_{\text{minor}} \lVert S_1\rVert^2\lVert D_K\rVert^2 \;=\; \int_{\mathbb{R}/\mathbb{Z}} - \int_{\text{major}} \;\le\; 8.001\,\lfloor H/3\rfloor^2 x \;-\; (0.98)^2\lfloor H/3\rfloor^2\cdot 0.626\,x \;=\; 7.4\,\lfloor H/3\rfloor^2 x .∫minor​∥S1​∥2∥DK​∥2=∫R/Z​−∫major​≤8.001⌊H/3⌋2x−(0.98)2⌊H/3⌋2⋅0.626x=7.4⌊H/3⌋2x.

Since (0.98)2⋅0.626=0.6012(0.98)^2\cdot 0.626 = 0.6012(0.98)2⋅0.626=0.6012 and 8.001−0.601=7.48.001 - 0.601 = 7.48.001−0.601=7.4, the constant 0.980.980.98 is exactly what turns minor_arc_L2_full_circle_8001 and S1_major_arc_L2_mass_626 into minor_arc_L2_corrected. Anything above 0.97970.97970.9797 would do; 0.980.980.98 is the round value that works.

Note the hypothesis x≥87⋅1035x \ge 87\cdot10^{35}x≥87⋅1035 is used only to make the arc small; no upper bound on xxx is needed, since shrinking the arc only helps.

Preamble
import Mathlib
import Definitions.Def_TaoFivePrimes_ArcSplit

open MeasureTheory
Formal statement
namespace TaoFivePrimes

theorem norm_DK_ge_major_arc (x : ℕ) (h1 : 87 * 10 ^ 35 ≤ x)
    (α : AddCircle (1 : ℝ)) (hα : α ∈ majorArc x) :
    0.98 * ((4 * 10 ^ 14 / 3 : ℕ) : ℝ) ≤ ‖DK (4 * 10 ^ 14) α‖ := by sorry

end TaoFivePrimes
Source
Terence Tao, Every odd number greater than 1 is the sum of at most five primes, arXiv:1201.6656, Section 8 (the strongly major arc of Proposition 8.3 and the Dirichlet-type kernel of equation (8.11)).

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