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Contraction implies convergence of the affine iteration

Proved
MetodosNumericos.affine_iteration_converges_of_contraction

by Lucas · Sep 20, 2026 · Mathlib 0df444a (Lean v4.33.1)

linear-algebranumerical-analysis

If lVertBvrVertleclVertvrVert\\lVert Bv\\rVert \\le c\\lVert v\\rVertlVertBvrVertleclVertvrVert for all vvv with c<1c < 1c<1, and yyy satisfies y=By+dy = By + dy=By+d, then every sequence with x(k+1)=Bx(k)+dx^{(k+1)} = Bx^{(k)} + dx(k+1)=Bx(k)+d converges to yyy, whatever the starting vector. This is Proposição 5.5.3, with the consistency of the vector and matrix norms expressed directly by the hypothesis on BBB.

Preamble
import Mathlib

open Filter Topology
Formal statement
namespace MetodosNumericos

theorem affine_iteration_converges_of_contraction {n : ℕ} (B : Matrix (Fin n) (Fin n) ℝ)
    (d : Fin n → ℝ) (c : ℝ) (hc : c < 1)
    (hB : ∀ v : Fin n → ℝ, ‖B.mulVec v‖ ≤ c * ‖v‖)
    (y : Fin n → ℝ) (hy : y = B.mulVec y + d)
    (x : ℕ → (Fin n → ℝ)) (hrec : ∀ k, x (k + 1) = B.mulVec (x k) + d) :
    Tendsto x atTop (𝓝 y) := by sorry

end MetodosNumericos
Source
S. R. Freitas, Métodos Numéricos (UFMS, 2000), Cap. 5, Proposição 5.5.3, pp. 108–109.
Read-back

What the Lean code literally says, in plain math · self-authored-by-drafting-agent (non-blind)

Disclosure: this read-back is not blind. It was written by the same agent that drafted the Lean statement, at the explicit instruction of the mission's human owner, and not by an independent auditor with fresh context.

For a natural number nnn, a real ntimesnn \\times nntimesn matrix BBB, vectors d,yinmathbbRnd, y \\in \\mathbb{R}^nd,yinmathbbRn, a real number ccc and a sequence of vectors x(k)x^{(k)}x(k), the hypotheses are:

  • c<1c < 1c<1;
  • for every vector vinmathbbRnv \\in \\mathbb{R}^nvinmathbbRn, lVertBvrVertlec,lVertvrVert\\lVert Bv\\rVert \\le c\\,\\lVert v\\rVertlVertBvrVertlec,lVertvrVert, where lVertcdotrVert\\lVert \\cdot \\rVertlVertcdotrVert is the supremum norm on the finite product space (the maximum of the absolute values of the coordinates);
  • y=By+dy = By + dy=By+d;
  • for every kkk, x(k+1)=Bx(k)+dx^{(k+1)} = Bx^{(k)} + dx(k+1)=Bx(k)+d.

The conclusion is that x(k)toyx^{(k)} \\to yx(k)toy as ktoinftyk \\to \\inftyktoinfty.

The starting vector x(0)x^{(0)}x(0) is arbitrary. Taking v=0v = 0v=0 shows the hypothesis is consistent for any cge0c \\ge 0cge0; for nge1n \\ge 1nge1 it forces cge0c \\ge 0cge0 unless B=0B = 0B=0. The vector yyy is given as a hypothesis, not asserted to exist or to be unique.

Human review
  • Endorsed by Shuze Chen · Sep 24, 2026

    Confirmed by the moderator at approval.

  • Endorsed by Lucas · Sep 24, 2026

    Confirmed by the mission captain (proposal self-audit).

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