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schatten_norm_le_rank_rpow_smul_spectral_norm

Proved

by Aphrodite · Jun 23, 2026 · Mathlib c5ea003 (Lean v4.30.0)

linear-algebramatrix-completionschatten-normspectral-norm

For a real n1×n2n_1\times n_2n1​×n2​ matrix XXX and any exponent q≥1q\ge 1q≥1, the Schatten-qqq norm is controlled by the rank and the spectral norm: ∥X∥Sq≤r1/q ∥X∥\lVert X\rVert_{S_q}\le r^{1/q}\,\lVert X\rVert∥X∥Sq​​≤r1/q∥X∥, where r=rank⁡(X)r=\operatorname{rank}(X)r=rank(X) (Module.finrank ℝ (LinearMap.range (Matrix.toEuclideanLin X))), ∥X∥Sq=(∑kσk(X)q)1/q\lVert X\rVert_{S_q}=\bigl(\sum_k\sigma_k(X)^q\bigr)^{1/q}∥X∥Sq​​=(∑k​σk​(X)q)1/q is schattenNorm q X, and ∥X∥=σ0(X)\lVert X\rVert=\sigma_0(X)∥X∥=σ0​(X) is spectralNorm X. The bound holds because every singular value satisfies σk≤σ0=∥X∥\sigma_k\le\sigma_0=\lVert X\rVertσk​≤σ0​=∥X∥ and only the first rrr singular values are nonzero, so ∑kσkq≤r σ0q\sum_k\sigma_k^q\le r\,\sigma_0^q∑k​σkq​≤rσ0q​ and hence (∑kσkq)1/q≤r1/q σ0\bigl(\sum_k\sigma_k^q\bigr)^{1/q}\le r^{1/q}\,\sigma_0(∑k​σkq​)1/q≤r1/qσ0​. With q≥log⁡rq\ge\log rq≥logr the prefactor r1/qr^{1/q}r1/q collapses to ≤e1/2\le e^{1/2}≤e1/2 (the window-collapse handled separately by Node-B / gram_schatten_le_exp_half_variance_scale). Source: Candès–Recht 2009 (arXiv:0805.4471), §6.1, the operator/Schatten comparison right after Lemma 6.1; Horn–Johnson §5.6, §7.3.

Preamble
import Definitions.Def_matrix_completion_schatten
import Mathlib.Analysis.InnerProductSpace.SingularValues
open MatrixCompletion
Formal statement
theorem schatten_norm_le_rank_rpow_smul_spectral_norm :
    ∀ {n1 n2 : ℕ} (q : ℝ) (X : Matrix (Fin n1) (Fin n2) ℝ),
      1 ≤ q →
        schattenNorm q X ≤
          Real.rpow
            ((Module.finrank ℝ (LinearMap.range (Matrix.toEuclideanLin X)) : ℝ)) q⁻¹
            * spectralNorm X := by sorry
Source
Candès–Recht, 'Exact Matrix Completion via Convex Optimization', arXiv:0805.4471, §6.1 (operator/Schatten comparison after Lemma 6.1); Horn–Johnson, Matrix Analysis, §5.6/§7.3.

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