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The S-rule in the terminal case

Proved
burau_rho_mul_Sm_terminal

by lt9 · Oct 1, 2026 · Mathlib 0df444a (Lean v4.33.1)

braid-groupsdescent-sections-rulesl2z

The SSS-rule in the terminal case. For a unimodular 2×22\times22×2 integer matrix MMM with M00=0M_{00}=0M00​=0,

ρ(M⋅S)=ρ(M)⋅liftS,\rho\bigl(M\cdot S\bigr) = \rho(M)\cdot \mathrm{liftS},ρ(M⋅S)=ρ(M)⋅liftS,

where S=(0−110)S=\left(\begin{smallmatrix}0&-1\\1&0\end{smallmatrix}\right)S=(01​−10​) and liftS=σ02σ1‾\mathrm{liftS}=\overline{\sigma_0^2\sigma_1}liftS=σ02​σ1​​. Here M=(0±1∓1d)M=\left(\begin{smallmatrix}0&\pm1\\\mp1&d\end{smallmatrix}\right)M=(0∓1​±1d​), M⋅SM\cdot SM⋅S descends in one step to −M-M−M, and the two values of the terminal map baseQ differ exactly by the conjugation identities liftS3XliftS−1=liftSXliftS\mathrm{liftS}^3X\mathrm{liftS}^{-1}=\mathrm{liftS}X\mathrm{liftS}liftS3XliftS−1=liftSXliftS and its inverse, which hold because liftS2\mathrm{liftS}^2liftS2 is central. With the zero case this disposes of the whole terminal branch of the SSS-rule; only the branch M00≠0M_{00}\neq0M00​=0 with non-vanishing descent quotient — the continued-fraction reversal — remains open.

Preamble
import Definitions.Def_burau_cf_list
import Definitions.Def_burau_rho
import Definitions.Def_burau_reduced_braid_group
import Theorems.Thm_burau_rho_mul_Sm_of_zero
import Theorems.Thm_burau_liftS_pow_four
import Theorems.Thm_burau_liftS_sq_central

set_option autoImplicit false
Formal statement
theorem burau_rho_mul_Sm_terminal (M : BurauNC.M2) (hd : M.det = 1) (h0 : M 0 0 = 0) :
    BurauNC.rho (M * BurauNC.Sm) = BurauNC.rho M * BurauNC.liftS := by sorry
Source
Euclidean algorithm in SL(2,Z) and the reduced Burau representation; cf. C. Moser, H. S. M. Coxeter, *Generators and relations for discrete groups* (1964), Ch. 3.

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