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The two completions of {0,1,2},{0,3,4},{0,5,6}\{0,1,2\}, \{0,3,4\}, \{0,5,6\}{0,1,2},{0,3,4},{0,5,6}

Proved
FanoUnique.two_completions

by ShapeZero · Sep 24, 2026 · Mathlib 0df444a (Lean v4.33.1)

combinatoricsfano-planesteiner-triple-systems

Let SSS be a Steiner triple system on {0,…,6}\{0, \dots, 6\}{0,…,6} whose lines include {0,1,2}\{0,1,2\}{0,1,2}, {0,3,4}\{0,3,4\}{0,3,4} and {0,5,6}\{0,5,6\}{0,5,6}. Then its lines are exactly one of

A: {0,1,2},{0,3,4},{0,5,6},{1,3,6},{1,4,5},{2,3,5},{2,4,6},\text{A: } \{0,1,2\}, \{0,3,4\}, \{0,5,6\}, \{1,3,6\}, \{1,4,5\}, \{2,3,5\}, \{2,4,6\},A: {0,1,2},{0,3,4},{0,5,6},{1,3,6},{1,4,5},{2,3,5},{2,4,6}, B: {0,1,2},{0,3,4},{0,5,6},{1,3,5},{1,4,6},{2,3,6},{2,4,5}.\text{B: } \{0,1,2\}, \{0,3,4\}, \{0,5,6\}, \{1,3,5\}, \{1,4,6\}, \{2,3,6\}, \{2,4,5\}.B: {0,1,2},{0,3,4},{0,5,6},{1,3,5},{1,4,6},{2,3,6},{2,4,5}.

The line through 111 and 333 is {1,3,5}\{1,3,5\}{1,3,5} or {1,3,6}\{1,3,6\}{1,3,6}, and that choice forces the other three lines.

Preamble
import Mathlib
import Definitions.Def_FanoUnique_isFano
Formal statement
namespace FanoUnique

open RolesForceSeven

theorem two_completions (S : STS 7)
    (h₁ : ({0, 1, 2} : Finset (Fin 7)) ∈ S.lines) (h₂ : ({0, 3, 4} : Finset (Fin 7)) ∈ S.lines)
    (h₃ : ({0, 5, 6} : Finset (Fin 7)) ∈ S.lines) :
    S.lines = {{0, 1, 2}, {0, 3, 4}, {0, 5, 6}, {1, 3, 6}, {1, 4, 5}, {2, 3, 5}, {2, 4, 6}} ∨
    S.lines = {{0, 1, 2}, {0, 3, 4}, {0, 5, 6}, {1, 3, 5}, {1, 4, 6}, {2, 3, 6}, {2, 4, 5}} := by
  sorry

end FanoUnique
Source
Shape Zero LLC, "Formal Proofs of the C1 Verification Package" (August 2026), §3, proof of Theorem 3.3 ("Uniqueness of STS(7) is classical"); this is a step of the standard textbook proof, supplying the step C1 calls classical: https://github.com/ShapeZeroSZ/shape-zero/blob/main/01_source/proofs/ShapeZero_C1_Formal_Proofs.pdf ; public references: Wikipedia, "Fano plane": https://en.wikipedia.org/wiki/Fano_plane ; Wikipedia, "Steiner system": https://en.wikipedia.org/wiki/Steiner_system
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What the Lean code literally says, in plain math · claude-opus-5-5

Setting. The points are the seven elements of {0,1,2,3,4,5,6}\{0,1,2,3,4,5,6\}{0,1,2,3,4,5,6}, written [7][7][7] below. The theorem is about an arbitrary structure SSS of the following kind, called a Steiner triple system on [7][7][7]. It is given by a finite family L(S)\mathcal{L}(S)L(S) of subsets of [7][7][7], called lines, and two conditions:

  • every line ℓ∈L(S)\ell \in \mathcal{L}(S)ℓ∈L(S) has exactly 333 elements;
  • for any two distinct points x≠yx \neq yx=y in [7][7][7], there is exactly one line ℓ∈L(S)\ell \in \mathcal{L}(S)ℓ∈L(S) with x∈ℓx \in \ellx∈ℓ and y∈ℓy \in \elly∈ℓ.

The structure holds nothing else. The two conditions are proofs, so SSS is determined by its family of lines L(S)\mathcal{L}(S)L(S). The imported files also define a specific system called "fano" (lines {i,i+1,i+3}\{i, i+1, i+3\}{i,i+1,i+3} mod 777), a predicate "IsFano" and a predicate "RoleColouring". None of these appear in this statement: it uses only the notion of a Steiner triple system on [7][7][7] given above.

Hypotheses. SSS is any Steiner triple system on [7][7][7], as above, such that the following three sets are all lines of SSS:

{0,1,2}∈L(S),{0,3,4}∈L(S),{0,5,6}∈L(S).\{0,1,2\} \in \mathcal{L}(S), \qquad \{0,3,4\} \in \mathcal{L}(S), \qquad \{0,5,6\} \in \mathcal{L}(S).{0,1,2}∈L(S),{0,3,4}∈L(S),{0,5,6}∈L(S).

There are no other hypotheses. The hypotheses can be satisfied together: for example, the first family listed below meets all of them.

Conclusion. The whole family of lines of SSS is exactly equal to one of the two seven-element families below. This is equality of sets of 333-subsets: SSS has these seven lines and no others.

L(S)={{0,1,2},{0,3,4},{0,5,6},{1,3,6},{1,4,5},{2,3,5},{2,4,6}}\mathcal{L}(S) = \big\{\{0,1,2\},\{0,3,4\},\{0,5,6\},\{1,3,6\},\{1,4,5\},\{2,3,5\},\{2,4,6\}\big\}L(S)={{0,1,2},{0,3,4},{0,5,6},{1,3,6},{1,4,5},{2,3,5},{2,4,6}}

or

L(S)={{0,1,2},{0,3,4},{0,5,6},{1,3,5},{1,4,6},{2,3,6},{2,4,5}}.\mathcal{L}(S) = \big\{\{0,1,2\},\{0,3,4\},\{0,5,6\},\{1,3,5\},\{1,4,6\},\{2,3,6\},\{2,4,5\}\big\}.L(S)={{0,1,2},{0,3,4},{0,5,6},{1,3,5},{1,4,6},{2,3,6},{2,4,5}}.

The "or" is an ordinary (inclusive) disjunction. The two families are different sets (for example, {1,3,6}\{1,3,6\}{1,3,6} is in the first but not in the second), so at most one of the two can hold for a given SSS. The statement says only that L(S)\mathcal{L}(S)L(S) is literally one of these two labelled families. It says nothing about isomorphism, about the "fano" system, or about the number of lines beyond what these equalities imply.

Human review
  • Endorsed by Shuze Chen · Sep 25, 2026

    Confirmed by the moderator at approval.

  • Endorsed by ShapeZero · Sep 25, 2026

    Confirmed by the mission captain (proposal self-audit).

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